Statistics paper 1 Questions
Q1.
The back-to-back stem and leaf diagram gives information about the ages of a random sample of
members of parliament in Canada and in the UK.
(a)Give a reason to support the use of a back-to-back stem and leaf diagram to represent this
information.
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.............................................................................................................................................
(1)
Some information about the quartiles of these two distributions is given in the table below.
(b)Find the value of a, the value of b and the value of c
a = ...........................................................
b = ...........................................................
c = ...........................................................
(3)
(c)Write down the proportion of members of parliament in the UK that are likely to be older than 54 years
old.
Give a reason for your answer.
.............................................................................................................................................
.............................................................................................................................................
(1)
(d)Compare the spread of ages for members of parliament in Canada with the spread of ages for
members of parliament in the UK.
State clearly the values of the statistic you use to make your comparison.
Interpret your comparison.
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(3)
One member of parliament in the UK wants to investigate the ages of the people living in her
constituency.
She suggests using the electoral register as a sample frame for her investigation.
(e)State one use of a sample frame in an investigation.
.............................................................................................................................................
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(1)
(f)Assess the suitability of using the electoral register as a sample frame for this investigation.
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(2)
(Total for question = 11 marks)
Q2.
Laura owns a company that makes and sells packets of crisps.
Laura wants to find out how sales of different flavours of crisps have changed over the past five years.
Here is part of a spreadsheet showing information about the percentage of total sales for each flavour
sold by the company for each year from 2013 to 2017
(a)Explain one way that Laura can use the spreadsheet to check whether any of the data needs to be
cleaned.
.............................................................................................................................................
.............................................................................................................................................
(1)
(b)Circle the cell in the spreadsheet that needs to be cleaned.
Write down what you think the correct value should be.
........................................................... %
(1)
Laura thinks that the company should stop making one of their flavours of crisps.
Laura notes that there is a downward trend in the percentage of total sales of ready salted crisps.
She also notes that there is a decrease of 1.8% between 2013 and 2017 and that this is greater than the
decrease for any other flavour.
One of Laura's employees, Ben, concludes that this means that it might be a good idea to stop making
ready salted crisps.
(c)Assess the validity of Ben's conclusion.
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(2)
Laura wants to do some quality control work to check the weights of large packets of crisps.
A sample of 10 large packets of crisps is taken at regular intervals and the mean weight of the packets in
each sample is calculated.
The sample means should be normally distributed with a mean of 510 g and a standard deviation of 20 g.
Laura is going to draw a quality control chart for the sample means.
The next two sample means are 495 g and 558 g.
(d)Explain how Laura should draw this quality control chart for the sample means and write down what
actions, if any, should be taken based on these two sample means.
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(5)
(e)Chose the correct words from the table below to complete correctly the following sentences.
(i)The population mean weight of large packets of crisps
should be .................................................................................................................... 510 g.
(1)
(ii)The population standard deviation of large packets of crisps
should be .................................................................................................................... 20 g.
(1)
(Total for question = 11 marks)
Q3.
The cumulative frequency diagram shows some information about the heights, in metres, of a random
sample of 50 of the tallest roller coasters in the world.
(a)Write down the number of roller coasters with a height of 80 metres or less.
...........................................................
(1)
(b)Work out an estimate of the number of these roller coasters with a height between 60 metres and 110
metres.
...........................................................
(2)
A safety company is going to inspect roller coasters with a height greater than 86 metres.
(c)Calculate an estimate of the percentage of the 50 roller coasters that the safety company is going to
inspect.
........................................................... %
(3)
(Total for question = 6 marks)
Q4.
The table shows information about houses for sale in Oxford.
An estate agent says the mode of the number of bedrooms for these houses is 3
(a) Explain how she knows this.
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(1)
The estate agent wants to investigate the prices of these houses.
She takes a stratified sample of 60 houses according to the number of bedrooms.
(b) Work out the number of houses in her sample for each number of bedrooms.
(3)
(c) Describe how to select the 60 houses in the sample.
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(3)
(Total for question = 7 marks)
Q5.
The population pyramid shows information about the numbers (in thousands) of drivers of each gender
who made car insurance claims in the UK in 2015
(a)How many female drivers aged 50–59 in the UK in 2015 made car insurance claims?
........................................................... thousand
(1)
The population pyramid shows that the age group which has the fewest number of drivers who made car
insurance claims is the 17–19 age group.
(b)Suggest a reason why this should be so.
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(1)
In 2014, the number of male drivers aged 20–49 in the UK who made car insurance claims was 66 700
(c)Compare the number of male drivers aged 20–49 in the UK who made car insurance claims in 2014
with the number of male drivers aged 20–49 in the UK who made car insurance claims in 2015
You must show your working.
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(3)
The SafeDrive insurance company charges young male drivers more for car insurance than it charges all
other drivers.
(d)Explain two features of the population pyramid which SafeDrive might use as its justification for doing
this.
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(2)
Jeremy says,
"The population pyramid shows that the total number of male drivers in the UK in 2015 is greater
than the total number of female drivers in the UK in 2015"
(e)Explain whether or not Jeremy's conclusion is appropriate.
.............................................................................................................................................
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(1)
Vicki says,
"In the UK in 2019, there will be more male drivers who make car insurance claims than female
drivers who make car insurance claims"
(f)Explain whether or not the information in the population pyramid can be used to support Vicki's
statement.
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(1)
(Total for question = 9 marks)
Q6.
The table shows a summary of the results of a long jump competition.
(a)Find an estimate of the mean distance jumped.
You may use the extra columns in the table.
........................................................... m
(3)
(b)Draw a frequency polygon for the data.
(3)
(c)Describe any skew shown by the data.
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(1)
(Total for question = 7 marks)
Q7.
A farmer recorded the birth weights, in kg, of a sample of 50 piglets born on his farm.
The grouped frequency table gives information about his results.
Using the information in the table and the values of w as the class midpoints, the farmer finds that an
estimate for the mean birth weight of these piglets is 2.29 kg.
He also finds that
(a)Show that an estimate of the standard deviation of the birth weights of these 50 piglets is 0.7 kg,
correct to 1 decimal place.
(2)
(b)Calculate an estimate for the skew of the birth weights of the piglets.
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(4)
(c)Interpret your answer to part (b).
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(1)
(d)Using only the information given in this question, explain whether it is possible to deduce that any of
the birth weights are outliers.
Justify your answer.
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(3)
(Total for question = 10 marks)
Q8.
Owen collected data about the number of people per km2 living in each of the 56 counties of England and
Wales in 2015
Some information about Owen's data is shown in this incomplete table.
(a)Work out the number of counties that have at least 600 people per km2.
...........................................................
(1)
(b)Use linear interpolation and the information in the table to find an estimate of the median number of
people per km2.
........................................................... people per km2
(3)
(c)(i)Using the information in the table, explain how the mean of Owen's data would compare with the
median of Owen's data.
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(ii)Explain whether the mean or the median is the most appropriate measure of central tendency to
use for Owen's data.
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(3)
Owen uses statistical software to draw a histogram to show the data he collected.
(d)Explain whether or not a histogram is appropriate.
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(1)
Owen prints his histogram but the page gets torn.
Here is what remains.
(e)Work out the value of r and the value of s in the table.
r = .............................. s = ..............................
(2)
(Total for question = 10 marks)
Q9.
In a town music competition, 6 groups competed against each other.
The table shows the marks awarded to each group by the invited independent judge.
The table also shows what the Mayor thought the rank order of the groups should be.
(Best group is given rank 1)
Using suitable calculations, investigate how much agreement there is between the judge
and the Mayor.
You may use the blank columns in the table for your working.
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(Total for question = 5 marks)
Q10.
The age and price of 12 used cars of the same type are plotted on the scatter diagram below.
One of the points on the scatter diagram represents an outlier.
(a)Draw a circle around the outlier.
(1)
(b)Comment on the price of the car represented by this point.
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(1)
Pearson's product moment correlation coefficient for the 12 cars, including the outlier, is calculated as –
0.662
With the outlier removed, Pearson's product moment correlation coefficient for the 11 cars is calculated as
–0.842
(c)(i)Give a reason why it might be appropriate to remove the outlier.
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(ii)Give a reason why it might not be appropriate to remove the outlier.
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(2)
With the outlier removed, Spearman's rank correlation coefficient for the data in the scatter diagram is
calculated as rs
(d)Describe fully how the value of rs should compare with –0.842
Give a reason for your answer.
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(3)
(Total for question = 7 marks)
Q11.
This time series graph shows information about the quarterly sales of soft drinks in a shop.
A trend line has been drawn on the graph.
(a)Describe the trend in the quarterly sales of soft drinks in the shop from 2015 to 2017
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(1)
(b)(i)Give an example of seasonal variation shown by the graph.
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(1)
(ii)Suggest a reason for this seasonal variation.
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(1)
The trend line was drawn using 4-point moving averages.
(c)(i)Using the data values for 2017 from the time series graph, calculate the final 4-point moving
average.
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(2)
(ii)Plot your calculated 4-point moving average on the graph.
(1)
(Total for question = 6 marks)
Q12.
The table gives the price index number for the average rail fare in Great Britain for each
of six years, with 2012 as base year.
The table also gives some of the chain base index numbers for the same information.
(a)Find, correct to 2 decimal places, the chain base index number for 2017
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(2)
Chris wanted to know the percentage increase in the cost of the average rail fare in
Great Britain between 2016 and 2017
Here is his working.
(b)Explain whether or not Chris is correct.
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(2)
The geometric mean of the chain base index numbers for 2013 to 2017 is 102.18
(c)Interpret this geometric mean in the context of the average rail fare in Great Britain.
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(2)
(Total for question = 6 marks)
Q13.
The table gives information about the change in the cost of a second class stamp from 2011 to 2017
By working out the geometric mean of 3 appropriate chain base index numbers, what can be deduced
about the average two-yearly change in the cost of a second class stamp from 2011 to 2017?
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(Total for question = 6 marks)
Q14.
The table shows the average cost of comprehensive motor insurance bought online each January from
2010 to 2013
(a)Using 2010 as the base year, find the price index (price relative) for motor insurance in January 2011
...........................................................
(2)
*(b)(i)Calculate the value of the chain base index number for motor insurance in January 2013
...........................................................
(ii)Interpret your answer.
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(4)
(Total for question = 6 marks)
Q15.
Tina has collected data on the deadlifts, in kilograms, for some female powerlifters.
She has summarised her results in the table.
Tina wants to calculate the mean deadlift for all 70 women.
She thinks that she has three possible methods.
Method AFind the mean of 134, 146 and 125
Method BWork out the total of (class midpoint of age × mean deadlift) for each class and divide by 70
Method CWork out the total of (mean deadlift × frequency) for each class and divide by 70
Determine which of these calculations Tina should use.
Explain why the calculation is appropriate.
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(Total for question = 2 marks)
Q16.
Nina suggests that each of the following problems can be answered by using a binomial distribution B(n,
p).
(a)Assess the suitability of using a binomial distribution model to answer each of the problems.
If a binomial model is suitable, you should consider any assumptions that must be made and give
possible values of n and p for the model.
If a binomial model is not suitable, you should explain why.
Problem 1
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Problem 2
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(6)
The probability that a particular machine has a fault is 7%.
A random sample of 6 of these machines are taken and each machine is checked.
(b)Work out the probability that at least 2 of these machines have the fault.
Give your answer correct to 3 decimal places.
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(3)
(Total for question = 9 marks)
Q17.
X and Y are two events.
The Venn diagram shows information about the probabilities of events related to X and Y happening.
(a) Find
(i) the probability of event Y happening.
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(ii)P(X and Y ),
...........................................................
(iii)P(Y | X).
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(4)
Two different events A and B are independent.
P(A) = 0.8 and P(B) = 0.5
(b) Find P(A and B).
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(2)
(Total for question = 6 marks)
Q18.
Fruitees sweets come in different flavours.
There are 8 sweets in a pack of mixed flavours and the flavours for each pack are chosen
at random.
The mean number of strawberry flavour Fruitees in a pack of 8 sweets is 2
Ed suggests that the number of strawberry flavour Fruitees in a pack of 8 sweets can be
modelled by a binomial distribution.
(a)By considering the conditions that make a binomial distribution a suitable model,
explain why Ed's suggestion is appropriate.
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(2)
One sweet is selected at random from a pack of Fruitees.
(b)Find the probability that the flavour of this sweet is strawberry.
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(1)
Ed buys a pack of Fruitees.
(c)Find the probability that there will be exactly 3 strawberry flavour Fruitees in the pack.
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(2)
(Total for question = 5 marks)
Question
Answer
Additional
guidance
Mark
(a)
Bil
eg
‘allows
two
data
sets
to
be
B1
for
a
suitable
reason
(1)
compared
easily
(b)
Bl
a=
53
B1
for
each
correct
value
found
(3)
Bl
b=43
Bl
c=62
(c)
Bl
eg
i
as
sample
median
is
likely
to
Bl
for
~
and
correct
supporting
reason
(1)
be
the
same
as
the
population
(accept
=
from
the
stem
and
leaf
diagram)
median
since
it
is
arandom
sample’
0
(dq)
Blft
CanadaIQR=17
and
UKIQR=19
Bi
for
identifying
both
IQKs
or
ranges
(3)
or
Canada
range
=
43
and
(allow
ft
from
part
(b))
UK
range
=
44
Blft
IQR/range
in
UK
ts
greater
than
B1
for
a
correct
comparison
of
measure
of
IOR/range
in
Canada
spread
(allow
ft
from
part
(b))
Bl
There
is
a
greater
spread
of
agesin
Bl
for
a
correct
conclusion
im
context
the
UK
parliament
(e)
Bl
Any
one
from
B1
for
a
correct
use
of
a
sample
frame
(1)
used
to select
sample
¢
used
to
identify
the
population
(f)
B2
eg
‘not
a
suitable
sample
frame
since
B2
for
assessing
the
suitability
of
the
(2)
it
does
not
mclude
all
members
of
the
population’
sampling
frame
with
supporting
reason
(B1
for
assessing
the
suttability
of
the
sampling
frame
with
incomplete
reasoning)
Mark Scheme
Q1.
Q2.
SE
|e
Additional
guidance
pass
@
BI
(Use
the
summing
feature
of
the
spreadsheet
Bl
for
correct
explanation
how
to
use
the
(1)
to)
add
up
each
column
to
check
it
equals
100%
spreadsheet
to
check
if
data
needs
to
be
cleaned
())__|
Bi
for
176
circled
and answer
17.6
@
©
B2
Ben's
conclusion
is
not a
good
one
because
B2
for
complete
assessment
of
validity
of
|)
eg
Ben’s
conclusion
with
a decision
that
itis
‘*
although
this
flavour
is
clearly
dropping
not
good
and
including
an
appropriate
in
popularity
itis
still
one
of
the top
reason
flavours
for
percentage
of
total
sales
(BI
for
a
decision
that
it
is
not
good
with an
©
it
would
be
better
to
drop
Pickled
incomplete
reason)
Onion
which
is
showing
a
drop
in
percentage
of
total
sales
and
has
the
lowest
percentage.
@
|B
BS
fora
complete
explanation
including
the
The
chart
should
have
key
values
explaining
how
the
quality
©
aline
showing
the
target
weight
at
510
control
chart
is
drawn
and
used
zg
©
Lines
showing
waming
limits
at
550
g_|
(Award
B1
for
each
correct
bullet
point
to
a
and
470
g
maximum
of
B3
for
the
first
four
bullet
‘©
Lines
showing
action
limits
at
570 g
points)
and
450
g
©
The
sample
means
(495
g
and 558
g)
are
plotted
B2
*
495 gis
inside the
waming
limits
no
action
is
required
©
558
gis
between
the
waming
limits
and
action
limits
another
sample
should be
taken
(©@
Bi
approximately
equal
to
@
©@)_|
Bi
greater
than
@
Q3.
Question
Scheme
‘Marks
(a)
350r36
Bl
@
(b)
45-8=37
MI
AL
@
©
Cumulative
frequency
at
86
metres
is
38
M1
So
12
are
taller
than
86
metres
Al
12
=x100=
50
Al
@)
[6]
Notes
(a)
35.5isB0
(b)
M1
for
the
subtraction
of
two
values
read
off
the
graph
at
60 and
110
(45k
or
k—8
scores
this
mark)
Al
cao
(©
M1
fora
vertical
line
drawn
up
at
86
or
38
seen
or
marked
on
cumulative
frequency
axis
or
76%
1*
Al
for
50
—
38
(=
12)
or
100
—
76
(may
be
implied
by
correct
answer)
2
Al
for
24 (%)
Question
Answer
‘Additional
guidance
Mark
number
(@)
BI
3
bedrooms
has
the
highest
frequency
Allow
equivalent
statistical
@
(for
any
individual
number
of
bedrooms)
reasoning
based
on
the
table
indicating
why
3
is
the
mode.
®
legion
Accept
a
correct
equivalent
i)
2
calculation
shown
for
any
one
class
M1
implied
by
one
correct
answer
AIAI
OR
an
indication
they
need
1
in
20
Bedrooms
TTT
273
74
131]
440,
5;
Houses
in
.
-
for
any
one
value
correct
sample
7
15 21 12
5
2441
for
all
correct
©
BI
Use
a
sampling
frame
for
each
strata
Each
category/strata
to
be
@
considered
separately
B1
Select
houses
randomly
or
generate
Samples
have
to
be
random
random
numbers
e.g.
How
the
random
numbers
are
B1
For
an
aspect
of
detail
obtained
and
used
Q4.
Question]
Answer
‘Additional
guidance
Mark]
number
(@/B1
9 (thousand)
B1
Accept
9000
@
@)BI
eg
B1
for
equivalent
wording
a
age
group
is
suggesting
that
the
class
is
narrower/doesn’t
start
at
10
‘smaller’.
(e.g.
drivers
start
from
there
are
fewer
drivers
age
17)
(under
20)
o..
Condone
sensible
contextual
comments,
e.g.
‘they
have
aot
been
driving
long’,
‘they
are
leaming’,
“they
are
more
careful”,
etc
(©[
Mi
25(000)
+
21(000)
+
19(000)
‘MI
for
addition
of
3
conecl
(3)
Al
65
(thousand)
figures
from
population
pyrami
Bl They
have
decreased
/
there
were
more
claims
(oe)
(in
2014
by male
drivers
aged
2049)
there
were
fewer
claims
in
2015
0.€
Al
for
65
of
65.000
(may
be
implied
by
1700
or
1.7)
B1
fora
correct
conclusion
(This
mark
is
independent
of
MIA1)
Q5.
@
BI
BI
for
two
correct
statements
+
Bars
get
shorter
as
age
increases,
o.€
+
Bars
are
shorter
for
females,
o.¢.
‘NOTE:
Condone
use
of
e.g
¢
‘accidents’
for
‘claims
1*B1
for
a
correct
statement
comparing
age.
Accept
e.g.
“20
=
29
make
most
claims’
(Condone
‘older
drivers
make
fewer
claims’
o.e.
but
‘there
are
fewer
older
drivers’
0.
is
BO)
2°
BI
fora
correct
statement
comparing
gender.
(Condone
“male
drivers
make
more
claims
o.e.
and
reference
to
single
age-
groups,
but
‘there
are
more
male
drivers’
o.e.
is
BO)
If
both
age
and
gender
are
included
in
a
single
comment.
award
this
comment
for
the
feature
that
is
different.
‘NB:
If
BO
scored,
then a
single
incomplete
comment
eg.
“young
males
make
more
claims’
can
score
B1BO
(as
we
don’t
know
if
they
are
comparing age
or
gender).
Q6.
Question
Answer,
Additional
guidance
Mark
@)
Bl
72,74,
76,78,
8.0,
8.2
Mi
for
Sf
=
7.2
1+7.4%2+7.6x5+
(218.8
+
28)
Al
78
BI
for
midpoints
correct.
Condone
one
error.
(Can be
implied
by
218.8
seen)
M1
for
sensible
attempt
at
Ef
(x
must
be
a
consistent
value
within
each
class)
Al
for
awrt
7.8
not
from
wrong
method
@
)
nay
Bl
Bl
Bl
Correct
heights
Correct
horizontal
and
joined
All
correct
including
polygon,
scale
and
label
Different
vertical
scales
are
possible.
£
square
tolerance
on
plots.
BI
for
at
least
5
points
at
comect
height,
consistently
within
intervals.
(If
no
correct
scale
check
relative
heights:
,
2k,
5k,
9k, 8k,
38)
BI
for
at
least
5
correct
horizontal
plots
and
attempt
at
joining
(ignore
extra
lines)
BI
for
fully
correct
frequency
polygon
with
consistent
numbered
and
labelled
scale
(For
3"
B1
ignore
lines
joining
first/last
points
to
axis
but
not
to
each
other)
©
BI
ft
Negative
(kew)
BI
for
correct
conclusion
about
the
skewness
BO
for
negative
correlation
or
negative
trend
@
Q7.
‘Question
‘Additional
guidance
Mark
M1
fora
comrect
expression
for (2)
(@)
MI
the
standard
deviation
(allow
ore
without
square
root)
Al
0.7(0242...)
which
is
0.7
to
1
decimal
place
‘Tr
eet
0.7
hova
comrect
working
a)
Mi
for
using
linear
interpolation
|)
|
MiMedian=
2+—x05
total
de
cedian
Al
awrt
2.26
Al
226047...)
Allow
2.28
from
using
(n
+
1)/2
M1
for
using
30.29
3(mean
-
median)
MI'Skew
oT
standard
deviation
AL
answer
in
the
range
0.10
to
0.13
‘Al
for
answer
in
the
range
0.10
100.13
Allow
answer
in the
range
0.04
to
0.05 coming
from
use
of
(7
+
2
BI
fi
Glight
positive
skew)
so
the
weights
above
BI
fi
for
a correct
contextualised
(1)
(©
the
median
have
a
greater
spread
than
the
weights
interpretation
of
the
skew
below
the
median/more
piglets
have
a
weight
less
Allow
neatly
symmetric
than
the
mean
BI
Outlier
limits
are
[mean
=3sd]02and44
BI
for
using
mean
+3
sdto
@
@
obtain
awrt
0.2
and
awrt
4.4
B1
[0.2
<0.5]
So
there are
no
lower
outliers
BI
[4.0
<4.4<6.0]
We
don't
know
the
exact
weight
of
the
piglet
in
the
4.0
<w
<6.0
class,
so
cannot
determine
if
itis
an
outlier
BI
for
no
lower
outliers
BI
for
not
possible
to
determine
if
there
is
an
upper
outlier
Q8.
Question
Answer
Additional
guidance
Mark
@
BI
13
BI
for
correct
evaluation of
remaining
counties
@
)
MI
2004
(28-15)
Al
x
200
Al
=386
awst
Mi
for
identifying
Ind
class
and
attempting
to
find
median
value
within
the
class
Al
for
use
of
correct
fraction
and
class
width
(condone
use
of
28.5
for
28)
Al
for
value
rounding
to
386
(or
awrt
393
if
28.5
used)
oOo
©a)
BI mean
greater
(than
median)
BI
median
more
appropriate
with
attempt
to
give
a
reason
BI
...due
to (positive)
skew
BI
for
equivalent
statement
recognising
mean
will
be
greater
than
median
BI
for
correct
choice
AND
attempt
to
justify
BI
for
stating
data
is
skewed
This
may
be
seen
in
either
@
or
Gi)
@
BI
Appropriate
as
data
is
grouped
/
continuous
BI
for
conclusion
recognising
appropriateness
with
equivalent
reason
@
©
‘M1
0.0125
x
400
Alr=5
s=8
MI
for
attempting
area
of
bar
Alcao
Q9.
(Question
Answer
‘Additional
guidance
Mark
number
M1
Judge's
ranks:
2,1,3,5,6,4
1°
M1
for
correct
ranks
(accept
reversed)
2
2=4
M1
for
attempting
sum
of
squared
M1
d?=0+0+4+140+1
©6)
£9)
silos
anaes
wilh
at
honed
4
eacit
ae
3"
M1
for
complete
attempt
at
formula,
MYA
Se
including
“1
—
*
(allow
their
“6°)
ese
Al
for
0.83 or
better
‘AY
psiNS
earTCERTEA)
SS
al
&
ie
correct
interpretation
of
their
s
ancora
between
jade
Dependent
on
complete
attempt
to
use
and
Mayor.
formula
and
r
value
in
range —Ito
+1
Question
Answer
‘Additional
guidance
Mark
number
@)
BI
Point
circled
at
(15,
11000)
‘No
other
points
circled
@
®
BIA
The
value
of
this
car
is
significantly
higher
BI
comectinterpretationia
()
than
other
cars
(around
the
same
age)
context
Oo
BI
eg.
‘maybe
an
error
in
the
data’,
‘doesn't
fit
B1
fora
suitable
appropriate_|
@)
the
trend’
reason
for
not
including
the
ww
outlier
BI
eg.
‘includes
all
data’,
“genuine
value
B1
for
suitable
appropriate
reason
for
including
the
outlier
@
B2
closer
to
—1
(smaller/lower)
@)
BI
will
still
be
negative)
BI
(since
as
age
increases,
value
of
car
decreases
but)
not
at
a constant
rate
linear
pattern
Q10.
Q11.
‘Question
Answer
‘Additional
guidance
Mark
(a)
Bi
egsales
increase
(as
time goes
on)
BI
for
a
description
of
trend.
Accept
@
rising/upward
trend
(Condone
‘positive’
but
‘positive
correlation
is
BO)
@@
|
Bi
egsales
are
higher
in
each
quarter
3,
Bi
for
comectly
identifying
a
seasonal
o
OR
variation
lower
in
each
quarter
1
(i)
BI
egitis
warmer/
it
is
summer
there
B1
for
a
sensible
corresponding
suggestion
@
ismore
demand
for
drinks,
OR
itis
why
sales
are
higher
in
quarter
3
OR
why
colder
itis
winter
/there
is
less
lower
in
quaster
1
demand
for
drinks
(©@
M1
(180
+
260
+
300
+
240)
+4
MI
for
selecting
the
last
4
values
from
the
Q)
graph
(at
least
2
correct)
and
division
by 4
al
(=)
=245
Al
cao
+
(i)
B1
ft
Their
“245°
plotted
midway
between
B1ft
for
correct
horizontal
positioning
of
@
Q2&Q3.2017
their
moving
average
paertae
Answer
Additional
guidance
Mark
@)
M1 +44
100
@
eur
M1
for
complete
equivalent
working
Al
101.18
bess
(o)
B2
Not
correct
with
B2
for
correct
assessment
of
statement,
with
2)
acceptable
reason.
correct
reasoning
(allow
FT
from
their
(a))
eg
(B1
Not
correct
(with
attempt
at
reason))
©
this
is
1.3%
of
the
2012
average
rail
fare
*
should
use
chain
base
index
number
(so
increase
is
“1.18%")
#
increase
is
“1.18%
Ke)
B2
(on
average)
2.18%
B2
for
complete
answer
with
figures
and
2)
increase
per
year
interpretation.
(Otherwise
B1
for
2.18%
seen)
Q12.
Q13.
‘Question
Answer
‘Additional
guidance
‘Mark
M1
56/54
=
100
‘M1
for
correct
calculation
of
chain
base
©
index
number
Al
103.7
Al
for
awrt
103.7
M1
for
VI389
=
108
*
103.7
M1
ft
for
correct
calculation
of
the
geometric
mean
of
3
chain
base
index
sumbers
‘Al
ft
115.9
Alft
for
awrt
115.9
B1
ft
for
(average)
rate
of
‘increase’
per
B1
ft
for
correct
contextual
interpretation
as
two
years
rate
of
increasing
per
two
years
BI
ft...
is
‘159°%
BI
ft
for
correct
contextual
interpretation
of
the
value
for
their
geometric
mean
Question
Scheme
Marks
(@)
618.59
559
Mi
501.75
=
123.286
(Accept
123
or
better,
truncated
or
rounded)
Al
Q)
(y@
595.66
100)
5132
“1
si
=
91.454
(Accept
91
or
better,
truncated
or
rounded)
Al
*Gi)
Cost of
motor
insurance
decreased
over
the
year by 8.5%
(or
9%)
o.€
B2,1.08
a
[6]
Notes
(a)
M1
Full
method
(including
100)
using
correct
months.
(Implied by awst
123)
Al
for
123 or
better,
truncated
or
rounded
(e.g.
123,
123.2,
123.3
etc)
BUT
123%
or
£123
scores
MIAO
(b)@
M1
Fraction
using
comect
figures.
Al
for
91
or
better,
truncated
or
rounded
(e.g.
91,
91.4,
91.5
etc)
BUT
912%
or
£91
scores
M1A0
unless
the
same
error
is
seen
in
(a)
Gi)
QW
NB
ft
their
answer
to
(i)
only
if
it
is
an
attempt
at
an
index
number
G£no
answer
to
part
(j)
then
score
BO)
B2ft
for
correct
interpretation
including
all
three
features:
decrease/fall.
reference
to
period
of
‘one’
year,
and
figures
%
OR
BIft
for
their
9%
or
decrease
seen
(must
follow
through
from
their
(i)
Q14.
Question]
Answer
‘Additional
guidance
Mark|
B2
for
Method
C
AND
reference
to
dividing
B2
for
a
complete
assessment
of
the
appropriate
(2)
the
total
of
the
deadlifts
by
the
total
mumber
choice
with
reason
of
people
OR
OR
BI
for
Method
C
with
attempt
at
reason
BI
for
an
incomplete
assessment
of
the
appropriate
choice
‘Question
[Answer
‘Additional
guidance
Mark
(@)_|
Problem
1
B3
for
fully
comect
assessment of
(6)
B3
suitability
and
assumptions
with
all
*
binomial
appropriate
as
6
bullet
points
correct
©
fixed
number
of
trials
©
two
possible
outcomes
~
getting
yellow/not
(B2
for
partially
correct
answer.
4
getting
yellow
bullet
points
correct
©
trials
are
independent
B1
for
partially
comrect
answer,
2
©
n=3andp=O.10e
bullet
points
correct)
«assume
probability
of
yellow
is
constant
Problem
2
B3
*
binomial
may
not
appropriate
as
although
there
is
a fixed
number
of
trials
and
two
possible
outcomes
—
five-set
/not
five-set
©
trials
are
not
independent,
the
people he
is
playing
change
(people
in
early
matches
are
likely
to
be
easier
to
beat
in
3
sets
than people
in
later
matches)
©
probability
is
unlikely
to
remain
constant
his
form
will
not
be
constant
OR
SC
B2
©
binomial
may
be
appropriate
as
2
fixed
number
of
trials
2
two
possible
outcomes
~
five-set
match/not
five-set
match
©
n=8andp
Soe
a
B3
for
fully
comrect
assessment of
suitability
and
assumptions
with
all
bullet
points
correct
(B2
for
partially
comect
answer,
2
bullet
points
correct
BI
for
partially
comrect
answer,
1
bullet
point
correct)
B2
for
complete
assessment
of
suitability
and
assumptions
with
all
4
bullet
points
correct
(BI
for
partially
correct
answer,
1
bullet
point
correct)
Q15.
Q16.
(@)
MI
093% or
6x
0.93"
x
0.07
M1
for
one
correct
probability
@
ML
1-(0.93°+
6 x
0.935
x
0.07)
‘M1
for
a
complete
method
Al
0.061
Al
for
awrt
0.061
Question
Answer
‘Additional
guidance
Mark
number
@@
[BI
@3+045)
07
For
probability
answers
accept
@)
equivalent
fractions,
decimals
or
percentages
@@i)
BI
03
gi)
yg,
03
05
Al
=06
)
MI
08x05
@
Al
=04
Q17.
Q18.
[Question]
Answer
Additional
guidance
‘Mar
number
(a)
B2
Suggestion
is
appropriate
B2
for
at
least
two
correct
conditions
@
because
(any
two
from):
referred
to,
with
at
least
one
in
context.
i
eed
maine
0
weet
(Otherwise
B1
for
one
correct
condition
8
in
each
packet
mentioned,
need
not
be
in
context.)
©
Flavours
are
independent
random
packing
©
Probability
(of
a
strawberry
Fruitee
would
be)
constant
©
Strawberry
&
not
strawberry
are the
only
two
outcomes
7
(o)
BI
(mean=
nxp
=
8Xp=2.
sop=)
o
1
toe
2
©
M1
0.25?
x
0.755
x
®C,
M1
for
correct
combination
of
probabilities
2)
Alft
=
0.2076.
with
attempt
at
binomial
coefficient
(e.g
from
Pascal's
triangle)
For
Alft
accept
0.21
or
0.208 with
correct
working.
ET
use
of
their
0.25
from
(b)
or
(a).