S : L 1REPORT HEET AB CHEM 108
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name
III.Chlorine isotopes: “Mix Isotopes”
Composition of Cl found in nature:
# 35Cl atoms# 37Cl atoms
3 1
II.Oxygen isotopes: “Make Isotopes”
Heaviest stable isotope:
Mass numberIsotope name
Fill in all the information in boxes highlighted in yellow!
I.Carbon isotopes: “Make Isotopes”
First unstable “heavy” isotope:
Mass numberIsotope name
14 Carbon-14
First unstable “light” isotope:
Mass numberIsotope name
11 Carbon-11
Most abundant isotope:
Mass numberIsotope name
% abundance Cl
# of protons
6
# of protons
6
# of protons
8
CHEM108-
B01
section
% abundance
# of neutrons
# of neutrons
# of neutrons
Cl
date
12
19
Carbon-12
Oxygen-19
75%
SIMULATION: Isotopes and Atomic Mass
37
25%
8
5
% abundance
98.93%
11
35
CHEM 108
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EXPERIMENT: Laboratory Techniques and Measurements
Use rules of significant figures; include units with each result.
Data Table 3: Mass measurements
Data Table 1: Length measurements
Data Table 2: Temperature measurements
Object
CD or DVD
Key
Spoon
Fork
Water
Hot from tap
Boiling
Boiling for 5 minutes
Cold from tap
Ice water – 1 minute
Ice water – 5
minutes
Object
Pen or pencil
3 Pennies
1 Quarter
2 Quarters, 3 Dimes
4 Dimes, 5 Pennies
3 Quarters, 1 Dime, 5 Pennies
Key
Key, 1 Quarter, 4 Pennies
Temperature (°C)
Length (cm)
Estimated Mass (g)
Temperature (°F)
Length (mm)
Actual Mass (g)
Length (m)
Temperature (K)
Actual mass (kg)
5
0
6
5
9
2
1
3
5
1
11.9
5.1
14.8
15.3
4.9
5.6
5.0
7.0
5.0
12.
9
5.0
16.
9
122
149
197.6
57.2
41
33.8
11
9
51
14
8
15
3
5.1
8.1
5.7
18.
2
22.
1
32.
5
9.0
25.
2
323.1
5
338.1
5
365.1
5
286.1
5
278.1
5
274.1
5
0.119
0.051
0.148
0.153
0.005
1
0.008
1
0.005
7
0.018
2
0.022
1
0.032
5
0.009
0.025
2
CHEM 108
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Data Table 7: Archimedes’ Method
Data Table 6: Displacement Method
Data Table 4: Liquid measurements
Data Table 5: Magnet – Measurement Method
Object:
Magne
t
Object
Magnet
Metal bolt
Object
Metal Bolt
Magnet
Liquid
Water
Isopropyl alcohol
Mass
(g)
Mass
(g)
Volume
(mL)
Mass
(g)
Lengt
h (cm)
Mass A
Graduated
Cylinder (g)
Initial volume of
graduated cylinder
(mL)
Widt
h
(cm)
Mass of
Displaced
Water (g)
Mass B
Graduated
Cylinder
with liquid (g)
Heigh
t (cm)
Final volume of
graduated cylinder
(mL)
Volume of
Displaced
Water
(mL)
Mass B -
A Liquid
(g)
Volume
(cm3)
Object
Volume
(mL)
Densit
y g/mL
Densit
y
(g/mL)
Densit
y
(g/cm3
)
Densit
y
(g/mL)
%
Error
4.2
8.0
4.2
5.0
5.0
4.2
8.0
2.4
17.2
17.2
0.5
22.
0
21.
7
0.5
4.8
4.5
0.6
0.9
6
0.9
6.9
-4%
14%
D=m/v
CHEM 108
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Post-Laboratory Questions
C.
Show work whenever feasible! Use rules of significant figures; include units with each result.
A.Water boils at 100°C at sea level. If the water in this experiment did not boil at 100°C, what
could be the reason?
Extrinsic/ environmental factors could effects the water’s ability to reach 100 degrees C
B.While heating two different samples of water at sea level, one boils at 102°C and one boils at
99.2°C. Calculate the percent error for each sample from the theoretical 100.0°C.
Sample 1: 100-102= -2
-2/102= -0.0196
-0.0196x100=
-1.96%
Sample 2: 100-99.2= 0.8
0.8/99.2= 0.008065
0.0080x100=
0.81%
An unknown, rectangular substance measures 3.6 cm high, 4.21 cm long, and 1.17 cm wide. If the
mass is 21.3 g, what is this substance’s density (in grams per milliliter)?
D=m/v
3.6x4.21x1.17= 17.73
21.3/17.73= 1.20 g/ml
CHEM 108
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E.What would happen if you dropped the object into the beaker while using the Archimedes’
Principle method instead of submerging the object?
This could lead to an inaccurate reading d/t wrong placement or dropping the object
F.How did the magnet’s density measurement using the Archimedes’ Principle compare to the
density measurement using the calculated volume? Which method might be more accurate?
Why?
Unable to complete these steps in lab
D.A sample of gold (Au) has a mass of 26.15 g. Given that the theoretical density is 19.30 g/mL,
what is the volume of the gold sample?
V=m/d
26.15/19.30=
1.35 ml
CHEM 108
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G.You are given a small piece of gold colored material and want to determine if it is actually gold.
Using the Archimedes’ Principle, you find that the volume is 0.40 cm3 and the mass is 6.0 g.
What conclusions can you reach from your simple density analysis?
D= m/v
6.0/0.40= 15 g/cm3
This would prove that the material is not gold.
