Understanding lab
Please open all pdfs
2 years ago
10
PHYreport1.docx
PHYexp1data.pdf
PHY2048LExp1Theory.pdf
- PHY2048LExp.1Labmanual.pdf
PHYreport1.docx
Experiment 1:
Student name:
Pre-lab section:
1) Introduction: Explain the theory behind this experiment in a paragraph between 150 and 250 words. (2.5 Points)
Suppose you are using external resources; include the reference. It would be best if you had any relevant formulas and explanations of each term. You may use the rich formula tools embedded here.
2) Hypothesis: In an If /Then statement, highlight the purpose of the experiment.
For instance: If two same shape objects with different masses are dropped from the same height, they will hit the ground simultaneously. (2 points)
Post-lab section:
3) Attach an image of your signed data sheet here. (3 Points)
4) Attach your analysis here, including any table, chart, or plot image. (6 points)
Each part is 1.5 points.
Table 1 and the calculation of the percent error.
Table 2 and the calculation of the percent error.
Table 3 and the calculation of the percent error.
Table 4 and the calculation of the percent error.
5) Attach the image of samples of your calculation here. (1 point)
6) In a paragraph between 100 and 150 words, explain what you Learn. What conclusion can you draw from the results of this lab assignment? (2 points)
7) In one sentence, compare the results of the experiment with your Hypothesis. Why? (1 point)
8) Attach your response to the questions in the lab manual here. (2.5 points)
Question 1: 1.5 points
Question 2: 1 point
PHYexp1data.pdf
1
Provided data for Exp 1 and instructions for data analysis and lab report
1. Provided data for Experiment 1 are given in Tables 1 to 4.
Table 1 Steel ball
Table 2 Aluminum block
Table 3 Brass cylinder
1 2 3 4 5 average
D (mm) 15.885 15.880 15.880 15.880 15.880 3
/ 6V D=
Vi i d V V= −
m (g) 16.650 16.650 16.650 16.650 16.650
(g/mm3)
i i d
= −
% error between the measured Fe and the accepted 3 3
:17.8 0 /Fe kg m =
1 2 3 4 5 average
L1 (cm) 1.550 1.550 1.550 1.550 1.550
L2 (cm) 1.560 1.550 1.540 1.550 1.540
L3 (cm) 4.880 4.890 4.880 4.870 4.880
1 2 3 V L L L=
Vi i d V V= −
m (g) 32.685 32.685 32.685 32.685 32.685
(g/cm3)
i i d
= −
% error between the measured Al and the accepted 3 3
:2.7 10 /Al kg m =
1 2 3 4 5 average
D (mm) 12.670 12.665 12.670 12.660 12.660
L (cm) 3.890 3.880 3.890 3.880 3.880 2
/ 4V D L=
Vi i d V V= −
m (g) 43.800 43.790 43.790 43.790 43.790
(g/mm3)
i i d
= −
% error between the measured Brace and the accepted 3 3
8.9 :10 /Brass kg m =
2
Table 4 Aluminum annular cylinder
2. Data analysis for Experiment 1
(a) To reduce the measurements errors five measurements have been made for each object as
shown in each of above 4 tables. Calculate the average (mean) dimensions of each object
and record your calculated data in each Table.
(b) Calculate the volume of each object (V dV ), where V is the mean of volume and dV
is the mean deviation of volume. Record your calculated data in each Table.
(c) Calculate the density ( d ) of the material of each object, where is the mean of
density and d is the mean deviation of density. Record your calculated data in each Table.
(d) Compare the measured with accepted of each object and calculate the percent %.
Record your calculated data in each Table.
(e) Put attention to the significant figures of your calculated data.
3. Lab report on Experiment 1
(a) Tables 1 to 4 with analyzed data must be included in your lab report.
(b) Answers to the questions #1 & #2 at the end of Exp 1 lab manual must be included in your lab
report.
(c) The required other contents and format for your lab report can be found in the syllabus.
1 2 3 4 5 average
L (cm) 0.940 0.940 0.940 0.940 0.940
D1 (cm) 1.880 1.890 1.870 1.880 1.870
D2 (cm) 0.960 0.970 0.970 0.970 0.960
( )2 2
1 2 4
L V D D
= −
VVd iVi −=
m (g) 5.720 5.720 5.720 5.720 5.720
(g/cm3)
−= ii
d
% error between the measured Al and the accepted 3 3
:2.7 10 /Al kg m =
PHY2048LExp1Theory.pdf
Significant figures (sig. fig.)
Least Count: Smallest marked division of an instrument. Illustration:
Counting # of significant figures in a direct measurement: # of sig. fig in a reading = # of figures read directly from instrument
+ 1 for an estimate figure Illustration: Using a standard ruler, you measure some object’s
length to be 2.5cm. But, actual length is between the 2.5cm and 2.6cm marks on ruler. So, real length = 2.5cm + (extra). You then eye estimate the (extra) to be 0.04cm. Then you have: final length reading = 2.54cm. Then this reading have 3 sig. fig., with the last ‘4’ as the estimate figure.
Calculations with sig. fig.
Multiplication and Division: The # of sig. fig. in calculated result is same as that in the measured number with the least # of sig. fig. Decimal place of last sig. fig in each factor is irrelevant. Illustration: If the sides of a rectangle are measured to be
2.03cm and 1.234cm, measured with different instruments. Then, if we calculate its area, then it can only have 3 sig. fig. Area= (1.234 × 2.03)cm2 = 2.5 0̄502cm2≃ 2.51cm2
Addition and Subtraction: The last significant decimal place in calculated result is same as that of the term with least # of sig. fig. after the decimal place. Total # of sig. fig. in each term is irrelevant. Illustration: Say we add Potential energy 1.234J with kinetic
Energy 100.0 J, with correct sig fig each. Then total energy E is: E= (1.234+100.0)J = 101. 2̄34 J ≃ 101.2 J
Calculations with sig. fig. (contd.)
Sig fig. for constants: Constants do not contribute to determining # of sig. fig. A constant is assumed to have infinite # of sig. fig. and hence can be truncated at any necessary decimal place. Illustration: If the radius of a ring is measured to be
r = 2.035cm , then its area is Area = π r2. Then we can choose value of as 3.142, as that is the number of figures in the radius. Then,π
we have: Area= (3.142× 2.0352)cm2= 13.0 1̄172895 ≃ 13.01 cm2
About 0’s: Any 0’s on the left of 1st non-zero digit are not sig. fig. Any 0’s on the right of and in between non-zero digits are sig. fig. Illustration: 0.00010, 0.10 and 1.0 → all have 2 sig. fig.
Scientific Notation → 0.00010 J→1.0×10−4 J (2 sig. fig.)
Mass, volume and Density
Density: Density of a body is obtained through equation:
ρ = m
V
where m is mass and V is volume of the object.
Volume determination: To determine volume of an object, you need its dimensions (such as length, diameter, etc.) and plug them in correct equation.
Dimension measurements: To measure dimensions of the objects, we use vernier calipers and micrometer.
Mass measurements: To measure mass, we utilize the laboratory balance.
Vernier Calipers
Least count: The vernier calipers we use have least count of 0.01cm.
Bottom prongs measure length or outer diameters. Top prongs measure inner diameters.
Vernier Calipers: Taking Measurements
Key Idea of taking reading: Total reading = Main scale reading
+ (Least count) X (smaller Marking # on vernier scale that line up or almost line up with some main scale marking)
Offset Error
In some instruments, the 0 of main scale do not match with the 0 of vernier scale even when the prongs are touching each other, causing error. This is offset error.
Micrometer
Least count: The vernier calipers we use have least count of 0.01mm.
Micrometer: Taking Measurements
Key Idea of taking reading: Total reading = Main scale reading
+ (Least count) X (Marking # on circular Scale that is just below central line on main scale)
Percent error
When average experimentally measured value for some quantity is̄x , and its true accepted standardized value is known to be A , either through literature or through theoretical considerations, then the percent error in the measurement done through the experiment is given by:
% error = |x̄ − A| A
× 100%
End of Theory
- Case study
- What The Playing Field Looks Like Now.
- Tonight
- Ashford University MGMT 601 The Functions of Modern Management Week 1 DQ1
- annotated bibliography Expert
- FIN 534 Week 11 Discussion 2
- FIN 534 Week 10 Quiz 9 Chapter 16
- accounting 306( Micro app for accounting)
- Intermediate Accounting III - Online Midterm Exam
- ENVIRONMENTAL SCAN ****NADIA TUTOR******