What is the probability a vacationer will visit at least one of these attractions?
A National Park Service survey of visitors to the Rocky Mountain region revealed that 50% visit Yellowstone Park, 40% visit the Tetons, and 35% visit both. |
a. | What is the probability a vacationer will visit at least one of these attractions? (Round your answer to 2 decimal places.) |
Probability |
c. | Are the events mutually exclusive? |
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2.
P(A1) = .20, P(A2) = .40, and P(A3) = .40. P(B1|A1) = .25. P(B1|A2) = .05, and P(B1|A3) = .10. |
Use Bayes' theorem to determine P(A3|B1). (Round your answer to 4 decimal places.) |
P(A3|B1) | ||
b. | The time between customer arrivals to a bank ATM. |
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c. | The number of customers in Big Nick’s barber shop. |
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d. | The amount of fuel in your car’s gas tank. |
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e. | The number of minorities on a jury. |
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f. | The outside temperature today. |
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5.
The U.S. Postal Service reports 95% of first-class mail within the same city is delivered within 2 days of the time of mailing. Six letters are randomly sent to different locations. |
a. | What is the probability that all six arrive within 2 days? (Round your answer to 4 decimal places.) |
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Probability | [removed] |
b. | What is the probability that exactly five arrive within 2 days? (Round your answer to 4 decimal places.) |
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Probability | [removed] |
c. | Find the mean number of letters that will arrive within 2 days. (Round your answer to 1 decimal place.) |
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Number of letters | [removed] |
d-1. | Compute the variance of the number that will arrive within 2 days. (Round your answer to 3 decimal places.) |
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Variance | [removed] |
d-2. | Compute the standard deviation of the number that will arrive within 2 days. (Round your answer to 4 decimal places.) |
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Standard Deviation | [removed] |
6.
In a binomial distribution, n = 12 and π = .60. |
a. | Find the probability for x = 5? (Round your answer to 3 decimal places.) |
Probability | [removed] |
b. | Find the probability for x ≤ 5? (Round your answer to 3 decimal places.) |
Probability | [removed] |
c. | Find the probability for x ≥ 6? (Round your answer to 3 decimal places.) |
Probability | [removed] |
7.
A population consists of 15 items, 10 of which are acceptable. |
In a sample of four items, what is the probability that exactly three are acceptable? Assume the samples are drawn without replacement. (Round your answer to 4 decimal places.) |
Probability | [removed] |
8.
The mean of a normal probability distribution is 60; the standard deviation is 5. (Round your answers to 2 decimal places.) |
a. | About what percent of the observations lie between 55 and 65? |
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Percentage of observations | [removed]% |
b. | About what percent of the observations lie between 50 and 70? |
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Percentage of observations | [removed]% |
c. | About what percent of the observations lie between 45 and 75? |
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Percentage of observations | [removed]% |
9.
A normal population has a mean of 12.2 and a standard deviation of 2.5. |
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a. | Compute the z value associated with 14.3. (Round your answer to 2 decimal places.) |
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Z | [removed] |
b. | What proportion of the population is between 12.2 and 14.3? (Round your answer to 4 decimal places.) |
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Proportion | [removed] |
c. | What proportion of the population is less than 10.0? (Round your answer to 4 decimal places.) |
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Proportion | [removed] |
10.
A normal population has a mean of 80.0 and a standard deviation of 14.0. |
a. | Compute the probability of a value between 75.0 and 90.0. (Round intermediate calculations to 2 decimal places. Round final answer to 4 decimal places.) |
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Probability | [removed] |
b. | Compute the probability of a value of 75.0 or less. (Round intermediate calculations to 2 decimal places. Round final answer to 4 decimal places.) |
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Probability | [removed] |
c. | Compute the probability of a value between 55.0 and 70.0. (Round intermediate calculations to 2 decimal places. Round final answer to 4 decimal places.) |
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Probability | [removed] |
For the most recent year available, the mean annual cost to attend a private university in the United States was $26,889. Assume the distribution of annual costs follows the normal probability distribution and the standard deviation is $4,500. |
Ninety-five percent of all students at private universities pay less than what amount? (Round z value to 2 decimal places and your final answer to the nearest whole number.) |
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Amount | $ [removed] |
11 years ago
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