Week 3	Testing multiple means with ANOVA					<Note: use right click on row numbers to insert rows to perform analysis below any question>
For questions 3 and 4 below, be sure to list the null and alternate hypothesis statements. Use .05 for your significance level in making your decisions.
For full credit, you need to also show the statistical outcomes - either the Excel test result or the calculations you performed.

1.	Based on the sample data, can the average(mean) salary in the population be the same for each of the grade levels? (Assume equal variance, and use the analysis toolpak function ANOVA.)
	Set up the input table/range to use as follows: Put all of the salary values for each grade under the appropriate grade label.
	Be sure to incllude the null and alternate hypothesis along with the statistical test and result.
	A	B	C	D	E	F	Note: Assume equal variances for all grades.


2.	The table and analysis below demonstrate a 2-way ANOVA with replication. Please interpret the results.
	Grade
	Gender	A	B	C	D	E	F
	M	24	27	40	47	56	76		The salary values were randomly picked for each cell.
		25	28	47	49	66	77
	F	22	34	41	50	65	75
		24	36	42	57	69	77

	Ho: Average salaries are equal for all grades
	Ha: Average salaries are not equal for all grades
	Ho: Average salaries by gender are equal
	Ha: Average salaries by gender are not equal
	Ho: Interaction is not significant
	Ha: Interaction is significant
	Perform analysis:
	Anova: Two-Factor With Replication

	SUMMARY	A	B	C	D	E	F	Total
	M
	Count	2	2	2	2	2	2	12
	Sum	49	55	87	96	122	153	562
	Average	24.5	27.5	43.5	48	61	76.5	46.8333
	Variance	0.5	0.5	24.5	2	50	0.5	364.515

	F
	Count	2	2	2	2	2	2	12
	Sum	46	70	83	107	134	152	592
	Average	23	35	41.5	53.5	67	76	49.3333
	Variance	2	2	0.5	24.5	8	2	367.333

	Total
	Count	4	4	4	4	4	4
	Sum	95	125	170	203	256	305
	Average	23.75	31.25	42.5	50.75	64	76.25
	Variance	1.58333	19.5833	9.66667	18.9167	31.3333	0.91667


	ANOVA
	Source of Variation	SS	df	MS	F	P-value	F crit
	Sample	37.5	1	37.5	3.84615	0.07348	4.74723
	Columns	7841.83	5	1568.37	160.858	1.5E-10	3.10588		Note: a number with an E after it (E9 or E-6, for example)
	Interaction	91.5	5	18.3	1.87692	0.17231	3.10588		means we move the decimal point that number of places.
	Within	117	12	9.75					For example, 1.2E4 becomes 12000; while 4.56E-5 becomes 0.0000456

	Total	8087.83	23

	Do we reject or not reject each of the null hypotheses? What do your conclusions mean about the population values being tested?
Interpretation:




3.	Using our sample results, can we say that the compa values in the population are equal by grade and/or gender, and are independent of each factor?
	Grade	Be sure to include the null and alternate hypothesis along with the statistical test and result.
	Gender	A	B	C	D	E	F		<Randomly pick compas to fill each cell - for exampe, a compa
	M								for the intersection of M and A might be 1.043.>
									<If desired, you can use the compa values that relate to the
	F								salary values used in question 2 for a more direct comparison of the two
									outcomes.>

	Conduct and show the results of a 2-way ANOVA with replication using the completed table above. The results should look something like those in question 2.
	Interpret the results. Are the average compas for each gender (listed as sample) equal? For each grade? Do grade and gender interaction impact compa values?


4.	Pick any other variable you are interested in and do a simple 2-way ANOVA without replication. Why did you pick this variable and what do the results show?
	Variable name:		Be sure to include the null and alternate hypothesis along with the statistical test and result.
	Gender	A	B	C	D	E	F
	M								Hint: use mean values in the boxes.
	F

5.	Using the results for this week, What are your conclusions about gender equal pay for equal work at this point?

HELP!!!!!!!! Must be done in Microsoft Excel

Help needed from anytimehelp only

BUS 308 Week 3 Assignment

Week 3 Assignment - Due Monday november 3rd 11pm CST