H1, µ ≠ 50, the tSTAT 2 > .21315, so reject H1.
Yes, because the sample size is large enough.
√64
64-1 = 63
-1.9983 < -1.3 < 1.9983
P- Value: .0968 + (1-.9032) = .1936 DO NOT REJECT
(B) No, the sample size is large enough, which should result in a normal distribution.
9.30) X = 2.00072, n= 50, µ= 2.0, S = .045
(a) 2.00072 – 2 = .00072 = .00072 = .1142
0.045 0.045 .0063
√50 7.07
50 -1= 49, + 2.0096
-2.0096 < .1142 < +2.0096
I have no evidence to conclude that the mean is different from 2.0
(b) P Value
.4562 + (1-.5438) = .4562 + .4562 = .9124, because this number is greater than a= .05, don’t reject H0.
(c)
(d) Yes, using the assumption for the t test, we were able to the distribution would be normal or not.
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budsimpson
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