Bio exam

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Question 1 (2 points)

 

1

Alleles are

Question 1 options:

	A)	Different forms of the same gene
	B)	Two different genes on the same chromosome that interact
	C)	Chromosome pairs
	D)	Different forms of phenotypes
	E)	Two different loci on the same chromosome

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Question 2 (2 points)

 

2

A human genome has 46 chromosomes/autosomes and the sperm cell has:

Question 2 options:

	A)	44
	B)	46
	C)	23
	D)	38

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Question 3 (2 points)

 

3

How many different gametes will the parent AABBDd make?

Question 3 options:

	A)	eight
	B)	two
	C)	four
	D)	six

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Question 4 (2 points)

 

4

What term best describes you if you have two chromosomes with different alleles?

Question 4 options:

	A)	heterozygous dominant
	B)	homozygous recessive
	C)	homozygous dominant
	D)	heterozygous

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Question 5 (2 points)

 

5

The The  The gametes in the punnett square produced what phenotypes?

Question 5 options:

	A)	1 dominant, 2 heterozygous and 1 recessive
	B)	1 heterozygote, 2 homozygous recessive and 1 homozygous dominant
	C)	3 dominant and 1 recessive
	D)	3 recessive and 1 dominant

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Question 6 (2 points)

 

6

What genotypes are produced in the punnett square example?

Question 6 options:

	A)	1 dominant, 2 heterozygous and 1 recessive
	B)	1 heterozygote, 2 homozygous recessive and 1 homozygous dominant
	C)	3 dominant and 1 recessive
	D)	3 recessive and 1 dominant

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Question 7 (2 points)

 

7

The punnett square in this example is a :

Question 7 options:

	monohybrid cross
	dihybrid cross
	test cross
	parent cross

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Question 8 (2 points)

 

8

The punnett square has nine individuals with what phenotypes?

Question 8 options:

	A)	nine with the same genotype
	B)	nine with both dominant characterisitics
	C)	nine individuals with one recessive and one dominant phenotype
	D)	nine with both recessive characteristics.

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Question 9 (2 points)

 

9

Which individual would have the largest number of autosomes?

Question 9 options:

	A)	A person with Klinefelter syndrome
	B)	A person with Turner syndrome
	C)	A healthy woman
	D)	A healthy man
	E)	A person with Down syndrome

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Question 10 (2 points)

 

10

Which individual would have the largest number of sex chromosomes?

Question 10 options:

	A)	A person with Klinefelter syndrome
	B)	A person with Turner syndrome
	C)	A healthy woman
	D)	A healthy man
	E)	A person with Down syndrome

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Question 11 (2 points)

 

11

 If Albinism was a dominant X-sex-linked trait fathers having the trait would pass it to all of their:

Question 11 options:

	A)	Offspring regardless of gender
	B)	Male offspring
	C)	Albino offspring
	D)	Female offspring

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Question 12 (2 points)

 

12

An example of incomplete dominance would be:

Question 12 options:

	A)	Eye color
	B)	AB blood type
	C)	Red and white flowers producing pink offspring
	D)	all of the answers are correct

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Question 13 (2 points)

 

13

An example of codominance would be:

Question 13 options:

	A)	Eye color
	B)	AB blood type
	C)	Red and white flowers producing pink offspring
	D)	all of the answers are correct

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Question 14 (2 points)

 

14

A chromosome starts off with the genes ABCDEF and ends up with ADEF, what type of mutation has taken place?

Question 14 options:

	A)	translocation
	B)	deletion
	C)	point mutation
	D)	Addition

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Question 15 (2 points)

 

15

 If a woman with blood type B had a child with blood type O you would expect the genotype of:

Question 15 options:

	A)	the father would only have blood type allele O
	B)	the mother would have the alleles B and O
	C)	the father would have the alleles A and B
	D)	The mother would have the alleles A and A

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Question 16 (2 points)

 

16

A person with blood type AB had a father that had blood type B.  What are the possible genotypes of that person’s mother?

Question 16 options:

	A)	Every blood type.
	B)	The blood types A, B or AB.
	C)	Genotypes AO, AA and AB.
	D)	Genotypes BO, BB and AB.

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Question 17 (2 points)

 

17

A population is represented by the equation p2+ 2pq + q2 and you need to know how many heterozygotes are in the population, which part of the equations represents them?

Question 17 options:

	A)	p2
	B)	2pq
	C)	q2
	D)	none of the answers

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Question 18 (2 points)

 

18

If the equation .25 + .5 + .25 were the numbers in the Hardy-Weinberg equation what is the frequency of heterozygotes?

Question 18 options:

	A)	100,000
	B)	25
	C)	25%
	D)	50%

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Question 19 (2 points)

 

19

The shaded squares represent:

Question 19 options:

	A)	females with the trait of interest
	B)	males with the trait of interest
	C)	females without the trait of interest
	D)	males without the trait of interest

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Question 20 (2 points)

 

20

The trait of interest displayed in the pedigree above is more than likely:

Question 20 options:

	A)	sex-linked dominant
	B)	sex-linked recessive
	C)	autosomal dominant
	D)	autosomal recessive

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Question 21 (2 points)

 

21

There are many genetically inherited diseases or conditions.  When the allele, causing the condition, is recessive the parents can be carriers of the allele but they are unaffected by the disease themselves.  The dominant allele protects them.  However, there are conditions caused by dominant alleles.  For example, the condition Achondroplasia, which causes dwarfism in humans, is the result of a dominant allele.  Therefore only one allele is required to have Achondroplasia. Achondroplasia is lethal for those that are homozygous dominant and no adult exists with that genotype.  Migraine headaches are another example of a dominant allele causing a deleterious condition.  In cases like this at least one parent is affected by the condition if it is passed to the offspring.  We will use A  and a to represent the dominant and recessive alleles for Achondroplasia.  In addition, M and m will be used for the dominant and recessive alleles for migraine headaches.  Consider the following problem.   A woman with Achondroplasia who has never had a migraine headache marries a man that has migraine headaches but does not have Achondroplasia.  The man’s father did not have migraine headaches.  The woman’s mother did not have Achondroplasia.  Based upon the following information what is the genotype of the woman?

Question 21 options:

	A)	You cannot determine this from the information given.
	B)	The AAMm would be her genotype.
	C)	The Aamm would have to be her genotype.
	D)	The aaMM would have to be her genotype.

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Question 22 (2 points)

 

22

There are many genetically inherited diseases or conditions.  When the allele, causing the condition, is recessive the parents can be carriers of the allele but they are unaffected by the disease themselves.  The dominant allele protects them.  However, there are conditions caused by dominant alleles.  For example, the condition Achondroplasia, which causes dwarfism in humans, is the result of a dominant allele.  Therefore only one allele is required to have Achondroplasia. Achondroplasia is lethal for those that are homozygous dominant and no adult exists with that genotype.  Migraine headaches are another example of a dominant allele causing a deleterious condition.  In cases like this at least one parent is affected by the condition if it is passed to the offspring.  We will use A  and a to represent the dominant and recessive alleles for Achondroplasia.  In addition, M and m will be used for the dominant and recessive alleles for migraine headaches.  Consider the following problem.   A woman with Achondroplasia who has never had a migraine headache marries a man that has migraine headaches but does not have Achondroplasia.  The man’s father did not have migraine headaches.  The woman’s mother did not have Achondroplasia.  Based on the information above what is the genotype of the man?

Question 22 options:

	A)	You could not determine this from the information given.
	B)	The aaMm would have to be his genotype.
	C)	The AaMm would have to be his genotype.
	D)	The aaMM would have to be his genotype.

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Question 23 (2 points)

 

23

If the p allele was at a frequency.4 in a population what is the frequency of the q allele?

Question 23 options:

	A)	.6
	B)	.4
	C)	.25
	D)	.5

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Question 24 (2 points)

 

24

The pedigree represented here is more than likely a:

Question 24 options:

	A)	trait on an autosome
	B)	dominnant trait
	C)	recessive sex-linked trait on the x-chromosome
	D)	recessive and on an autosome

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Question 25 (2 points)

 

25

Filling in on the punnett square would give:

Question 25 options:

	A)	50% bb and 50% Bb
	B)	100% Bb
	C)	25%BB, 50% Bb and 25% bb
	D)	75% BB and 25% bb

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Question 26 (2 points)

 

26

Which stage of mitosis has chromosomes lining up at the middle getting ready to break into separate sets?

Question 26 options:

	A)	Prophase
	B)	Metaphase
	C)	Anaphase
	D)	Telophase

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Question 27 (2 points)

 

27

Which stage of mitosis has DNA starting to condense into chromosomes?

Question 27 options:

	A)	Prophase
	B)	Metaphase
	C)	Anaphase
	D)	Telophase

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Question 28 (2 points)

 

28

In which stage of mitosis do separate sets of chromesomes exist and begin migrating away from each other?

Question 28 options:

	A)	Prophase
	B)	Metaphase
	C)	Anaphase
	D)	Telophase

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Question 29 (2 points)

 

29

Which stage of mitosis has two nuclei and nuclear envelopes reform?

Question 29 options:

	A)	Prophase
	B)	Metaphase
	C)	Anaphase
	D)	Telophase

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Question 30 (2 points)

 

30

After telophase is complete _____ will happen resulting in two daughter cells.

Question 30 options:

	A)	Anaphase
	B)	crossing over
	C)	cytokinesis
	D)	telokinesis

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Question 31 (2 points)

 

31

The two chromosomes are _____ for the purpose of _____ genes.

Question 31 options:

	Telophasing/cleaning genes
	crossing over/ exchanging genes
	DNAing/exchanging genes
	Shaking arms/changing genes

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Question 32 (2 points)

 

32

If you crossed AaBbCc x AaBbCc you would have a _____ cross in an ___ x ____ punnett square.

Question 32 options:

	A)	trihybrid/8 x 8
	B)	dihybrid/4 x 4
	C)	monohybrid/2 x 2
	D)	tetrahybrid/8 x 8

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Question 33 (2 points)

 

33

What is the difference between a sex-influenced trait and a sex-linked trait?

Question 33 options:

	A)	In sex influenced traits the gene for this is on the sex chromosomes and it is dominant in one sex and recessive in the other.
	B)	These two terms are identical.
	C)	In sex influenced traits the gene is on an autosome and behaves differently in the two genders because of hormonal factors.
	D)	Sex-linked traits are on the x-sex-chromosome and behave differently in men and women.

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Question 34 (2 points)

 

34

Someone with Klinefelter's syndrome would have what different about their karyotype?

Question 34 options:

	A)	They would not be able to express a karyotype because they are sterile.
	B)	They would express a trisomy on chromosome 23.
	C)	They would have three chromosomes for each loci rather than two.
	D)	They would have a karyotype with a missing X sex chromosome.

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Question 35 (2 points)

 

35

       Mice carry a lethal gene.  The agouti-colored mice have the recessive gene; yellow mice, the dominant gene.  The reason why this yellow gene or allele is of interest is because all dominant homozygotes die before birth.  Only the heterozygotes display the yellow phenotype.  If we were to cross two yellow mice then determined that eight embryos started to develop within the pregnant female, how many mice would be born alive with what phenotypes?

Question 35 options:

	A)	eight mice would be born, six would be yellow and two agouti colored.
	B)	eight mice would be born, six agouti and two yellow colored.
	C)	eight mice would be born, two homozygous dominant, four heterozygous and two homozygous recessive.
	D)	six mice would be born four yellow and two agouti.

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Question 36 (2 points)

 

36

    If the dark color for moths is dominant over the white, what would a cross between the two types of homozygotes produce for offspring? 

Question 36 options:

	A)	half homozygous dominant and half recessive
	B)	half heterozygous and half homozygous dominant
	C)	all heterozygous
	D)	all homozygous dominant

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Question 37 (2 points)

 

37

The karyotype in the picture has:

Question 37 options:

	a set of normal female chromosomes
	an abnormal trisomy on chromosome 21
	no sex chromomes
	both a trisomy on 21 and no sex chromomes

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Question 38 (2 points)

 

38

Andalusian chickens are an example of incomplete dominance. If you wanted to raise Andalusian Blue chickens, the way to produce the most would be:

Question 38 options:

	A)	to cross two Andalusian Blue chickens
	B)	to cross a homozygous black with a homozygous white
	C)	to cross two heterozygotes
	D)	to cross a white with a blue chicken

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Question 39 (2 points)

 

39

Consider the question for blood type. If your mother gives you an A allele and your father gives you an O allele, what blood type are you?

Question 39 options:

	A)	AO
	B)	Not a compatible blood type
	C)	blood type A
	D)	blood type O

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Question 40 (2 points)

 

40

The ABO blood group has actually four blood types A, B, AB and O. The hardy Weinberg equation would be a trinomial. How many heterozygous genotypes can be produced with this blood typing system?

Question 40 options:

	A)	two, AO and BO
	B)	Three, AO, BO, and AB
	C)	four, A, AB, B and O
	D)	five, AB, BA, BO, AO and ABO

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Question 41 (2 points)

 

41

In the following dihybrid cross yellow is dominant to green and round is dominant to wrinkled. What were the original parents that made the two F1 parents in this cross?

Question 41 options:

	A)	YYrr x yyRR
	B)	YyRr x YYrr
	C)	YYRr x yyRr
	D)	YyRr x YyRr

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Question 42 (2 points)

 

42

In the dihybrid cross for pea seeds  how many yellow wrinkled individuals will there be?

Question 42 options:

	9
	3
	4
	1

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Question 43 (2 points)

 

43

In the dihybrid cross how many green round indivduals will there be?

Question 43 options:

	A)	9
	B)	3
	C)	4
	D)	1

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Question 44 (2 points)

 

44

In the dihybrid cross how many green wrinkled individuals will there be?

Question 44 options:

	A)	9
	B)	3
	C)	4
	D)	1

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Question 45 (2 points)

 

45

In the dihybrid cross how many yellow round individuals will there be?

Question 45 options:

	A)	9
	B)	3
	C)	4
	D)	1

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Question 46 (2 points)

 

46

In order for a female child to have hemophilia her father and mother would be what:

Question 46 options:

	A)	mother would have it father would not.
	B)	mother and father would both have the condition there would be no other way.
	C)	The mother could either be a carrier or have the condition the father must have it.
	D)	The father could either be a carrier or have it as well as the mother.

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Question 47 (2 points)

 

47

When the gene for color blindess is considered it shows up on the male's X sex chromosome he is color blind; however, if the condition shows up on one X sex chromosome of a female she will not be color blind this trait is:

Question 47 options:

	A)	sex influenced
	B)	dominant sex-linked trait
	C)	recessive sex-linked trait
	D)	none of the answers is correct

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Question 48 (2 points)

 

48

If the cross in this picture displayed an incomplete dominance with red and white flower color the cross would produce:

Question 48 options:

	3 red and 1 white
	2 red and 2 white
	1 red and 3 white
	1 red, 2 pink and 1 white

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Question 49 (2 points)

 

49

What syndrome is this karyotype displaying?

Question 49 options:

	A)	Turner's Syndrome
	B)	Klinefelter's Syndrome
	C)	Down Syndrome
	D)	Brown's Syndrome

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Question 50 (2 points)

 

50

What syndrome is the karyotype displaying?

Question 50 options:

	A)	Turner's Syndrome
	B)	Klinefelter's Syndrome
	C)	Down Syndrome
	D)	Brown's Syndrome

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