Operations Management- Case 2

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topic_4_s.ppt

Topic 4
Quality Management

Dr. Bin Jiang

Department of Management

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Dichotomy of Quality

MGT 504 by Dr. Bin Jiang

Quality is the ability of a product or service to consistently meet or exceed customer expectations.

Red Side of Quality:
Dimensions of Quality

  • Performance – main characteristics of the product
  • Reliability – consistency of performance
  • Durability – useful life of the product
  • Safety – risk of injury
  • Aesthetics – appearance, feel, etc
  • Service After Sale
  • Perceived Quality – e.g. reputation

MGT 504 by Dr. Bin Jiang

Blue Side of Quality:
Process Control Charts

Control Charts show sample data plotted on a graph with Center Line (CL), Upper Control Limit (UCL), and Lower Control Limit (LCL).

MGT 504 by Dr. Bin Jiang

Control Chart

  • Control Chart
  • Purpose: to monitor process output to see if its variation is random
  • A time ordered plot representative sample statistics obtained from an on going process (e.g. sample means)
  • Upper and lower control limits define the range of acceptable variation

MGT 504 by Dr. Bin Jiang

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Types of Control Charts

  • Control chart for variables are used to monitor characteristics that can be measured, e.g. length, weight, diameter, time, etc.
  • Control charts for attributes are used to monitor characteristics that have discrete values and can be counted, e.g. % defective, number of flaws in a shirt, number of broken eggs in a box, etc.

MGT 504 by Dr. Bin Jiang

Empirical Rule

MGT 504 by Dr. Bin Jiang

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-3

-1

-2

+1

+2

+3

68%

95%

99.7%

Upper Limit

Lower Limit

Expected Output

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Six Sigma

MGT 504 by Dr. Bin Jiang

Mean

Lower limits

Upper limits

±6

3.4 defects/million

2,700 defects/million

±3

Control Charts for Variables

  • Are named according to the statistics being plotted, i.e., X bar, R
  • Have a center line that is the overall average
  • Have limits above and below the center line at ± 3 standard deviations (usually)

MGT 504 by Dr. Bin Jiang

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Center line

Lower Control Limit (LCL)

Upper Control Limit (UCL)

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Control Charts for Variables

  • Mean control chart: X bar chart
  • Used to monitor the central tendency of a process.

Range control chart: R chart

  • Used to monitor the process dispersion

MGT 504 by Dr. Bin Jiang

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Variables Data Charts

  • Process Centering
  • X bar chart
  • X bar is a sample mean
  • Process Dispersion (consistency)
  • R chart
  • R is a sample range

MGT 504 by Dr. Bin Jiang

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X chart

  • Center line is the grand mean (X double bar)
  • Points are X bars

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-OR-

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Example 1

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Standard Deviation is 0.02

Sample 1 Sample 2 Sample 3 Sample 4 Sample 5
O1 12.11 12.15 12.09 12.12 12.09
O2 12.10 12.12 12.09 12.10 12.14
O3 12.11 12.10 12.11 12.08 12.13
O4 12.08 12.11 12.15 12.10 12.12
X bar 12.10 12.12 12.11 12.10 12.12

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Factors for Calculating Three-Sigma Limits

For x-Chart and R-Chart

Example 1

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Approach 1

Approach 2

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Example 1

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MGT 504 by Dr. Bin Jiang

UCL=12.14

LCL=12.08

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R Chart

  • Center line is the grand mean (R bar)
  • Points are R
  • D3 and D4 values are tabled according to n (sample size)

MGT 504 by Dr. Bin Jiang

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Example 1

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UCL = 0.105

LCL = 0

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X and Range Charts

MGT 504 by Dr. Bin Jiang

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UCL

Does not
reveal increase

UCL

LCL

LCL

R-chart

Reveals increase

(process variability is increasing)

Sampling

Distribution

x-Chart

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X and Range Charts

MGT 504 by Dr. Bin Jiang

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UCL

LCL

UCL

LCL

R-chart

x-Chart

Detects shift

Does not
detect shift

(process mean is

shifting upward)

Sampling

Distribution

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Example 2

Processing new accounts at a bank is intended to average 10 minutes each. Five samples of four observations each have been taken. Use the sample data in the following table to construct upper and lower control limits for both a mean chart and a range chart. Do the results suggest that the process is in control?

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MGT 504 by Dr. Bin Jiang

Sample1 Sample2 Sample3 Sample4 Sample5
10.2 10.3 9.7 9.9 9.8
9.9 9.8 9.9 10.3 10.2
9.8 9.9 9.9 10.1 10.3
10.1 10.4 10.1 10.5 9.7
10.0 10.1 9.9 10.2 10.0

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Example 2

MGT 504 by Dr. Bin Jiang

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Step 1:

Step 2:

For n = 4: A2 = 0.73, D4 = 2.28, D3 = 0.

Step 3:

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Example 2

Step 4:

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x-Chart

R-chart

10.04

10.42

9.66

1.19

0.52

0

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Control Chart Checks

MGT 504 by Dr. Bin Jiang

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Any point outside of the control limits

A run of 7 points all above or all below the nominal line

A run of 7 points up or down (trends)

Any other obviously non-random pattern

Control Charts for Attributes
P-Charts & C-Charts

  • Use P-Charts for quality characteristics that are discrete and involve yes/no or good/bad decisions
  • Percent of leaking caulking tubes in a box of 48
  • Percent of broken eggs in a carton

  • Use C-Charts for discrete defects when there can be more than one defect per unit
  • Number of flaws or stains in a carpet sample cut from a production run
  • Number of complaints per customer at a hotel

MGT 504 by Dr. Bin Jiang

Constructing a P-Chart:

A Production manager for a tire company has inspected the number of defective tires in five random samples with 20 tires in each sample. The table below shows the number of defective tires in each sample of 20 tires.

MGT 504 by Dr. Bin Jiang

Sample Sample Size (n) Number Defective
1 20 3
2 20 2
3 20 1
4 20 2
5 20 1

Step 1:
Calculate the Percent defective of Each Sample and the Overall Percent Defective (P-Bar)

MGT 504 by Dr. Bin Jiang

Sample Number Defective Sample Size Percent Defective
1 3 20 .15
2 2 20 .10
3 1 20 .05
4 2 20 .10
5 1 20 .05
Total 9 100 .09

Step 2: Calculate the Standard Deviation of P.

MGT 504 by Dr. Bin Jiang

Step 3: Calculate CL, UCL, LCL

MGT 504 by Dr. Bin Jiang

Center line (p bar):

Control limits for ±3σ limits:

Step 4: Draw the Chart

MGT 504 by Dr. Bin Jiang

Constructing a C-Chart:

The number of weekly customer complaints are monitored in a large hotel. Develop a three sigma control limits For a C-Chart using the data table On the right.

MGT 504 by Dr. Bin Jiang

Week Number of Complaints
1 3
2 2
3 3
4 1
5 3
6 3
7 2
8 1
9 3
10 1
Total 22

Calculate CL, UCL, LCL

MGT 504 by Dr. Bin Jiang

Center line (c bar):

Control limits for ±3σ limits:

Process Capability

MGT 504 by Dr. Bin Jiang

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Product Specifications

Preset product or service dimensions, tolerances: bottle fill might be 16 oz. ±.2 oz. (15.8oz.-16.2oz.)

Based on how product is to be used or what the customer expects

Process Capability – Cp and Cpk

Assessing capability involves evaluating process variability relative to preset product or service specifications

Cp assumes that the process is centered in the specification range

Cpk helps to address a possible lack of centering of the process

Relationship between Process Variability and Specification Width

  • Three possible ranges for Cp
  • Cp = 1, as in Fig. (a), process

variability just meets specifications

  • Cp ≤ 1, as in Fig. (b), process not capable of producing within specifications
  • Cp ≥ 1, as in Fig. (c), process

exceeds minimal specifications

  • One shortcoming, Cp assumes that the process is centered on the specification range
  • Cp=Cpk when process is centered

MGT 504 by Dr. Bin Jiang

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Process Capability

800

1000

1200

MGT 504 by Dr. Bin Jiang

Nominal

value

Hours

Upper

specification

Lower

specification

Process distribution

Process Capability

Nominal

value

Hours

Upper

specification

Lower

specification

Process distribution

800

1000

1200

MGT 504 by Dr. Bin Jiang

MGT 504 by Dr. Bin Jiang

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Computing the Cp Value at Cocoa Fizz: 3 bottling machines are being evaluated for possible use at the Fizz plant. The machines must be capable of meeting the design specification of 15.8-16.2 oz. with at least a process capability index of 1.0 (Cp≥1).

Example of Cp

The table below shows the information gathered from production runs on each machine. Are they all acceptable?

Machine A:

MGT 504 by Dr. Bin Jiang

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Example of Cpk

Design specifications call for a target value of 16.0 ±0.2 OZ.

(USL = 16.2 & LSL = 15.8)

Observed process output has now shifted and has a µ of 15.9 and a

σ of 0.1 oz.

Cpk is less than 1, revealing that the process is not capable

What if we don’t know ?

MGT 504 by Dr. Bin Jiang

Sample Size

d2

2

1.128

3

1.693

4

2.059

5

2.326

6

2.534

10

3.078

n

X

X

n

i

i

å

=

=

1

)

min(

)

max(

i

i

X

X

R

-

=

x

z

X

UCL

s

+

=

n

x

/

s

s

=

x

z

X

LCL

s

-

=

m

X

X

m

j

j

å

=

=

1

R

A

X

UCL

2

+

=

R

A

X

LCL

2

-

=

11

.

12

5

5

4

3

2

1

=

+

+

+

+

=

x

x

x

x

x

x

046

.

0

5

5

4

3

2

1

=

+

+

+

+

=

R

R

R

R

R

R

14

.

12

046

.

0

73

.

0

11

.

12

2

=

´

+

=

+

=

R

A

x

UCL

08

.

12

046

.

0

73

.

0

11

.

12

2

=

´

-

=

-

=

R

A

x

LCL

14

.

12

4

02

.

0

3

11

.

12

=

÷

ø

ö

ç

è

æ

+

=

+

=

x

z

x

UCL

s

08

.

12

4

02

.

0

3

11

.

12

=

÷

ø

ö

ç

è

æ

-

=

-

=

x

z

x

LCL

s

10

.

12

4

=

x

12

.

12

2

=

x

10

.

12

1

=

x

12

.

12

5

=

x

11

.

12

3

=

x

11

.

12

=

x

R

D

UCL

4

=

R

D

LCL

3

=

046

.

0

5

5

4

3

2

1

=

+

+

+

+

=

R

R

R

R

R

R

105

.

0

046

.

0

28

.

2

4

=

´

=

=

R

D

UCL

0

046

.

0

0

3

=

´

=

=

R

D

LCL

046

.

0

=

R

52

.

0

,

04

.

10

=

=

R

x

0

)

52

.

0

(

0

19

.

1

)

52

.

0

(

28

.

2

66

.

9

)

52

.

0

(

73

.

0

04

.

10

42

.

10

)

52

.

0

(

73

.

0

04

.

10

3

4

2

2

=

=

=

=

=

=

=

-

=

-

=

=

+

=

+

=

R

D

LCL

R

D

UCL

R

A

x

LCL

R

A

x

UCL

R

R

x

x

p

p(1-p)(.09)(.91)

σ===0.064

n20

CLp.09

==

(

)

(

)

p

p

UCLpz

σ.093(.064).282

LCLpz

σ.093(.064).1020

=+=+=

=-=-=-=

#complaints22

CL2.2

# of samples10

===

UCLcc2.232.26.65

LCLcc2.232.22.250

z

z

=+=+=

=-=-=-=

s

6

LSL

USL

C

p

-

=

ú

ú

û

ù

ê

ê

ë

é

-

-

=

s

s

3

,

3

x

US

LS

x

Min

C

pk

Sample Size

d

2

2

1.128

3

1.693

4

2.059

5

2.326

6

2.534

10

3.078

2

ˆ

d

R

@

s