Dr Sally ONLY
Data
| ID | Salary | Compa | Midpoint | Age | Performance Rating | Service | Gender | Raise | Degree | Gender1 | Gr | Students: Copy the Student Data file data values into this sheet to assist in doing your weekly assignments. | ||||
| The ongoing question that the weekly assignments will focus on is: Are males and females paid the same for equal work (under the Equal Pay Act)? | ||||||||||||||||
| Note: to simplfy the analysis, we will assume that jobs within each grade comprise equal work. | ||||||||||||||||
| The column labels in the table mean: | ||||||||||||||||
| ID – Employee sample number | Salary – Salary in thousands | |||||||||||||||
| Age – Age in years | Performance Rating - Appraisal rating (employee evaluation score) | |||||||||||||||
| Service – Years of service (rounded) | Gender – 0 = male, 1 = female | |||||||||||||||
| Midpoint – salary grade midpoint | Raise – percent of last raise | |||||||||||||||
| Grade – job/pay grade | Degree (0= BS\BA 1 = MS) | |||||||||||||||
| Gender1 (Male or Female) | Compa - salary divided by midpoint | |||||||||||||||
Week 1
| Week 1. | Measurement and Description - chapters 1 and 2 | |||||||||||
| The goal this week is to gain an understanding of our data set - what kind of data we are looking at, some descriptive measurse, and a | ||||||||||||
| look at how the data is distributed (shape). | ||||||||||||
| 1 | Measurement issues. Data, even numerically coded variables, can be one of 4 levels - | |||||||||||
| nominal, ordinal, interval, or ratio. It is important to identify which level a variable is, as | ||||||||||||
| this impact the kind of analysis we can do with the data. For example, descriptive statistics | ||||||||||||
| such as means can only be done on interval or ratio level data. | ||||||||||||
| Please list under each label, the variables in our data set that belong in each group. | ||||||||||||
| Nominal | Ordinal | Interval | Ratio | |||||||||
| b. | For each variable that you did not call ratio, why did you make that decision? | |||||||||||
| 2 | The first step in analyzing data sets is to find some summary descriptive statistics for key variables. | |||||||||||
| For salary, compa, age, performance rating, and service; find the mean, standard deviation, and range for 3 groups: overall sample, Females, and Males. | ||||||||||||
| You can use either the Data Analysis Descriptive Statistics tool or the Fx =average and =stdev functions. | ||||||||||||
| (the range must be found using the difference between the =max and =min functions with Fx) functions. | ||||||||||||
| Note: Place data to the right, if you use Descriptive statistics, place that to the right as well. | ||||||||||||
| Some of the values are completed for you - please finish the table. | ||||||||||||
| Salary | Compa | Age | Perf. Rat. | Service | ||||||||
| Overall | Mean | 35.7 | 85.9 | 9.0 | ||||||||
| Standard Deviation | 8.2513 | 11.4147 | 5.7177 | Note - data is a sample from the larger company population | ||||||||
| Range | 30 | 45 | 21 | |||||||||
| Female | Mean | 32.5 | 84.2 | 7.9 | ||||||||
| Standard Deviation | 6.9 | 13.6 | 4.9 | |||||||||
| Range | 26.0 | 45.0 | 18.0 | |||||||||
| Male | Mean | 38.9 | 87.6 | 10.0 | ||||||||
| Standard Deviation | 8.4 | 8.7 | 6.4 | |||||||||
| Range | 28.0 | 30.0 | 21.0 | |||||||||
| 3 | What is the probability for a: | Probability | ||||||||||
| a. Randomly selected person being a male in grade E? | ||||||||||||
| b. Randomly selected male being in grade E? | ||||||||||||
| Note part b is the same as given a male, what is probabilty of being in grade E? | ||||||||||||
| c. Why are the results different? | ||||||||||||
| 4 | A key issue in comparing data sets is to see if they are distributed/shaped the same. We can do this by looking at some measures of where | |||||||||||
| some selected values are within each data set - that is how many values are above and below a comparable value. | ||||||||||||
| For each group (overall, females, and males) find: | Overall | Female | Male | |||||||||
| A | The value that cuts off the top 1/3 salary value in each group | "=large" function | ||||||||||
| i | The z score for this value within each group? | Excel's standize function | ||||||||||
| ii | The normal curve probability of exceeding this score: | 1-normsdist function | ||||||||||
| iii | What is the empirical probability of being at or exceeding this salary value? | |||||||||||
| B | The value that cuts off the top 1/3 compa value in each group. | |||||||||||
| i | The z score for this value within each group? | |||||||||||
| ii | The normal curve probability of exceeding this score: | |||||||||||
| iii | What is the empirical probability of being at or exceeding this compa value? | |||||||||||
| C | How do you interpret the relationship between the data sets? What do they mean about our equal pay for equal work question? | |||||||||||
| 5. | What conclusions can you make about the issue of male and female pay equality? Are all of the results consistent? | |||||||||||
| What is the difference between the sal and compa measures of pay? | ||||||||||||
| Conclusions from looking at salary results: | ||||||||||||
| Conclusions from looking at compa results: | ||||||||||||
| Do both salary measures show the same results? | ||||||||||||
| Can we make any conclusions about equal pay for equal work yet? | ||||||||||||
Week 2
| Week 2 | Testing means - T-tests | ||||||
| In questions 2, 3, and 4 be sure to include the null and alternate hypotheses you will be testing. | |||||||
| In the first 4 questions use alpha = 0.05 in making your decisions on rejecting or not rejecting the null hypothesis. | |||||||
| 1 | Below are 2 one-sample t-tests comparing male and female average salaries to the overall sample mean. | ||||||
| (Note: a one-sample t-test in Excel can be performed by selecting the 2-sample unequal variance t-test and making the second variable = Ho value - a constant.) | |||||||
| Note: These values are not the same as the data the assignment uses. The purpose is to analyze the results of t-tests rather than directly answer our equal pay question. | |||||||
| Based on these results, how do you interpret the results and what do these results suggest about the population means for male and female average salaries? | |||||||
| Males | Females | ||||||
| Ho: Mean salary = | 45.00 | Ho: Mean salary = | 45.00 | ||||
| Ha: Mean salary =/= | 45.00 | Ha: Mean salary =/= | 45.00 | ||||
| Note: While the results both below are actually from Excel's t-Test: Two-Sample Assuming Unequal Variances, | |||||||
| having no variance in the Ho variable makes the calculations default to the one-sample t-test outcome - we are tricking Excel into doing a one sample test for us. | |||||||
| Male | Ho | Female | Ho | ||||
| Mean | 52 | 45 | Mean | 38 | 45 | ||
| Variance | 316 | 0 | Variance | 334.6666666667 | 0 | ||
| Observations | 25 | 25 | Observations | 25 | 25 | ||
| Hypothesized Mean Difference | 0 | Hypothesized Mean Difference | 0 | ||||
| df | 24 | df | 24 | ||||
| t Stat | 1.9689038266 | t Stat | -1.9132063573 | ||||
| P(T<=t) one-tail | 0.0303078503 | P(T<=t) one-tail | 0.0338621184 | ||||
| t Critical one-tail | 1.7108820799 | t Critical one-tail | 1.7108820799 | ||||
| P(T<=t) two-tail | 0.0606157006 | P(T<=t) two-tail | 0.0677242369 | ||||
| t Critical two-tail | 2.0638985616 | t Critical two-tail | 2.0638985616 | ||||
| Conclusion: Do not reject Ho; mean equals 45 | Conclusion: Do not reject Ho; mean equals 45 | ||||||
| Note: the Female results are done for you, please complete the male results. | |||||||
| Is this a 1 or 2 tail test? | Is this a 1 or 2 tail test? | 2 tail | |||||
| - why? | - why? | Ho contains = | |||||
| P-value is: | P-value is: | 0.0677242369 | |||||
| Is P-value < 0.05 (one tail test) or 0.025 (two tail test)? | Is P-value < 0.05 (one tail test) or 0.025 (two tail test)? | No | |||||
| Why do we not reject the null hypothesis? | Why do we not reject the null hypothesis? | P-value greater than (>) rejection alpha | |||||
| Interpretation of test outcomes: | |||||||
| 2 | Based on our sample data set, perform a 2-sample t-test to see if the population male and female average salaries could be equal to each other. | ||||||
| (Since we have not yet covered testing for variance equality, assume the data sets have statistically equal variances.) | |||||||
| Ho: | Male salary mean = Female salary mean | ||||||
| Ha: | Male salary mean =/= Female salary mean | ||||||
| Test to use: | t-Test: Two-Sample Assuming Equal Variances | ||||||
| P-value is: | |||||||
| Is P-value < 0.05 (one tail test) or 0.025 (two tail test)? | |||||||
| Reject or do not reject Ho: | |||||||
| If the null hypothesis was rejected, calculate the effect size value: | |||||||
| If calculated, what is the meaning of effect size measure: | |||||||
| Interpretation: | |||||||
| b. | Is the one or two sample t-test the proper/correct apporach to comparing salary equality? Why? | ||||||
| 3 | Based on our sample data set, can the male and female compas in the population be equal to each other? (Another 2-sample t-test.) | ||||||
| Again, please assume equal variances for these groups. | |||||||
| Ho: | |||||||
| Ha: | |||||||
| Statistical test to use: | |||||||
| What is the p-value: | |||||||
| Is P-value < 0.05 (one tail test) or 0.025 (two tail test)? | |||||||
| Reject or do not reject Ho: | |||||||
| If the null hypothesis was rejected, calculate the effect size value: | |||||||
| If calculated, what is the meaning of effect size measure: | |||||||
| Interpretation: | |||||||
| 4 | Since performance is often a factor in pay levels, is the average Performance Rating the same for both genders? | ||||||
| NOTE: do NOT assume variances are equal in this situation. | |||||||
| Ho: | |||||||
| Ha: | |||||||
| Test to use: | t-Test: Two-Sample Assuming Unequal Variances | ||||||
| What is the p-value: | |||||||
| Is P-value < 0.05 (one tail test) or 0.025 (two tail test)? | |||||||
| Do we REJ or Not reject the null? | |||||||
| If the null hypothesis was rejected, calculate the effect size value: | |||||||
| If calculated, what is the meaning of effect size measure: | |||||||
| Interpretation: | |||||||
| 5 | If the salary and compa mean tests in questions 2 and 3 provide different results about male and female salary equality, | ||||||
| which would be more appropriate to use in answering the question about salary equity? Why? | |||||||
| What are your conclusions about equal pay at this point? | |||||||
Week 3
| Week 3 | Paired T-test and ANOVA | |||||||||||||
| For this week's work, again be sure to state the null and alternate hypotheses and use alpha = 0.05 for our decision | ||||||||||||||
| value in the reject or do not reject decision on the null hypothesis. | ||||||||||||||
| 1 | Many companies consider the grade midpoint to be the "market rate" - the salary needed to hire a new employee. | Salary | Midpoint | Diff | ||||||||||
| Does the company, on average, pay its existing employees at or above the market rate? | ||||||||||||||
| Use the data columns at the right to set up the paired data set for the analysis. | ||||||||||||||
| Null Hypothesis: | ||||||||||||||
| Alt. Hypothesis: | ||||||||||||||
| Statistical test to use: | ||||||||||||||
| What is the p-value: | ||||||||||||||
| Is P-value < 0.05 (one tail test) or 0.025 (two tail test)? | ||||||||||||||
| What else needs to be checked on a 1-tail test in order to reject the null? | ||||||||||||||
| Do we REJ or Not reject the null? | ||||||||||||||
| If the null hypothesis was rejected, what is the effect size value: | ||||||||||||||
| If calculated, what is the meaning of effect size measure: | ||||||||||||||
| Interpretation of test results: | ||||||||||||||
| Let's look at some other factors that might influence pay - education(degree) and performance ratings. | ||||||||||||||
| 2 | Last week, we found that average performance ratings do not differ between males and females in the population. | |||||||||||||
| Now we need to see if they differ among the grades. Is the average performace rating the same for all grades? | ||||||||||||||
| (Assume variances are equal across the grades for this ANOVA.) | Here are the data values sorted by grade level. | |||||||||||||
| The rating values sorted by grade have been placed in columns I - N for you. | A | B | C | D | E | F | ||||||||
| Null Hypothesis: | Ho: means equal for all grades | 90 | 80 | 100 | 90 | 85 | 70 | |||||||
| Alt. Hypothesis: | Ha: at least one mean is unequal | 80 | 75 | 100 | 65 | 100 | 100 | |||||||
| Place B17 in Outcome range box. | 100 | 80 | 90 | 75 | 95 | 95 | ||||||||
| 90 | 70 | 80 | 90 | 55 | 95 | |||||||||
| 80 | 95 | 80 | 95 | 90 | 95 | |||||||||
| 85 | 80 | 95 | 95 | |||||||||||
| 65 | 90 | 90 | ||||||||||||
| 70 | 75 | |||||||||||||
| 95 | 95 | |||||||||||||
| 60 | 90 | |||||||||||||
| 90 | 95 | |||||||||||||
| 75 | 80 | |||||||||||||
| 95 | ||||||||||||||
| 90 | ||||||||||||||
| 100 | ||||||||||||||
| Interpretation of test results: | ||||||||||||||
| What is the p-value: | 0.57 | If the ANVOA was done correctly, this is the p-value shown. | ||||||||||||
| Is P-value < 0.05? | ||||||||||||||
| Do we REJ or Not reject the null? | ||||||||||||||
| If the null hypothesis was rejected, what is the effect size value (eta squared): | ||||||||||||||
| Meaning of effect size measure: | ||||||||||||||
| What does that decision mean in terms of our equal pay question: | ||||||||||||||
| 3 | While it appears that average salaries per each grade differ, we need to test this assumption. | |||||||||||||
| Is the average salary the same for each of the grade levels? | ||||||||||||||
| Use the input table to the right to list salaries under each grade level. | ||||||||||||||
| (Assume equal variance, and use the analysis toolpak function ANOVA.) | ||||||||||||||
| Null Hypothesis: | If desired, place salaries per grade in these columns | |||||||||||||
| Alt. Hypothesis: | A | B | C | D | E | F | ||||||||
| Place B51 in Outcome range box. | ||||||||||||||
| Note: Sometimes we see a p-value in the format of 3.4E-5; this means move the decimal point left 5 places. In this example, the p-value is 0.000034 | ||||||||||||||
| What is the p-value: | ||||||||||||||
| Is P-value < 0.05? | ||||||||||||||
| Do we REJ or Not reject the null? | ||||||||||||||
| If the null hypothesis was rejected, calculate the effect size value (eta squared): | ||||||||||||||
| If calculated, what is the meaning of effect size measure: | ||||||||||||||
| Interpretation: | ||||||||||||||
| 4 | The table and analysis below demonstrate a 2-way ANOVA with replication. Please interpret the results. | |||||||||||||
| Note: These values are not the same as the data the assignment uses. The purpose of this question is to analyze the result of a 2-way ANOVA test rather than directly answer our equal pay question. | ||||||||||||||
| BA | MA | Ho: Average compas by gender are equal | ||||||||||||
| Male | 1.017 | 1.157 | Ha: Average compas by gender are not equal | |||||||||||
| 0.870 | 0.979 | Ho: Average compas are equal for each degree | ||||||||||||
| 1.052 | 1.134 | Ha: Average compas are not equal for each degree | ||||||||||||
| 1.175 | 1.149 | Ho: Interaction is not significant | ||||||||||||
| 1.043 | 1.043 | Ha: Interaction is significant | ||||||||||||
| 1.074 | 1.134 | |||||||||||||
| 1.020 | 1.000 | Perform analysis: | ||||||||||||
| 0.903 | 1.122 | |||||||||||||
| 0.982 | 0.903 | Anova: Two-Factor With Replication | ||||||||||||
| 1.086 | 1.052 | |||||||||||||
| 1.075 | 1.140 | SUMMARY | BA | MA | Total | |||||||||
| 1.052 | 1.087 | Male | ||||||||||||
| Female | 1.096 | 1.050 | Count | 12 | 12 | 24 | ||||||||
| 1.025 | 1.161 | Sum | 12.349 | 12.9 | 25.249 | |||||||||
| 1.000 | 1.096 | Average | 1.0290833333 | 1.075 | 1.0520416667 | |||||||||
| 0.956 | 1.000 | Variance | 0.006686447 | 0.0065198182 | 0.0068660417 | |||||||||
| 1.000 | 1.041 | |||||||||||||
| 1.043 | 1.043 | Female | ||||||||||||
| 1.043 | 1.119 | Count | 12 | 12 | 24 | |||||||||
| 1.210 | 1.043 | Sum | 12.791 | 12.787 | 25.578 | |||||||||
| 1.187 | 1.000 | Average | 1.0659166667 | 1.0655833333 | 1.06575 | |||||||||
| 1.043 | 0.956 | Variance | 0.006102447 | 0.0042128106 | 0.004933413 | |||||||||
| 1.043 | 1.129 | |||||||||||||
| 1.145 | 1.149 | Total | ||||||||||||
| Count | 24 | 24 | ||||||||||||
| Sum | 25.14 | 25.687 | ||||||||||||
| Average | 1.0475 | 1.0702916667 | ||||||||||||
| Variance | 0.0064703478 | 0.0051561286 | ||||||||||||
| ANOVA | ||||||||||||||
| Source of Variation | SS | df | MS | F | P-value | F crit | ||||||||
| Sample | 0.0022550208 | 1 | 0.0022550208 | 0.3834821171 | 0.5389389507 | 4.0617064601 | (This is the row variable or gender.) | |||||||
| Columns | 0.0062335208 | 1 | 0.0062335208 | 1.0600539609 | 0.3088295633 | 4.0617064601 | (This is the column variable or Degree.) | |||||||
| Interaction | 0.0064171875 | 1 | 0.0064171875 | 1.0912877664 | 0.3018915062 | 4.0617064601 | ||||||||
| Within | 0.25873675 | 44 | 0.0058803807 | |||||||||||
| Total | 0.2736424792 | 47 | ||||||||||||
| Interpretation: | ||||||||||||||
| For Ho: Average compas by gender are equal | Ha: Average compas by gender are not equal | |||||||||||||
| What is the p-value: | ||||||||||||||
| Is P-value < 0.05? | ||||||||||||||
| Do you reject or not reject the null hypothesis: | ||||||||||||||
| If the null hypothesis was rejected, what is the effect size value (eta squared): | ||||||||||||||
| Meaning of effect size measure: | ||||||||||||||
| For Ho: Average compas are equal for all degrees | Ha: Average compas are not equal for all grades | |||||||||||||
| What is the p-value: | ||||||||||||||
| Is P-value < 0.05? | ||||||||||||||
| Do you reject or not reject the null hypothesis: | ||||||||||||||
| If the null hypothesis was rejected, what is the effect size value (eta squared): | ||||||||||||||
| Meaning of effect size measure: | ||||||||||||||
| For: Ho: Interaction is not significant | Ha: Interaction is significant | |||||||||||||
| What is the p-value: | ||||||||||||||
| Is P-value < 0.05? | ||||||||||||||
| Do you reject or not reject the null hypothesis: | ||||||||||||||
| If the null hypothesis was rejected, what is the effect size value (eta squared): | ||||||||||||||
| Meaning of effect size measure: | ||||||||||||||
| What do these three decisions mean in terms of our equal pay question: | ||||||||||||||
| Place data values in these columns | ||||||||||||||
| 5. | Using the results up thru this week, what are your conclusions about gender equal pay for equal work at this point? | Dif | ||||||||||||
Week 4
| Week 4 | Confidence Intervals and Chi Square (Chs 11 - 12) | |||||||||||||||
| For questions 3 and 4 below, be sure to list the null and alternate hypothesis statements. Use .05 for your significance level in making your decisions. | ||||||||||||||||
| For full credit, you need to also show the statistical outcomes - either the Excel test result or the calculations you performed. | ||||||||||||||||
| 1 | Using our sample data, construct a 95% confidence interval for the population's mean salary for each gender. | |||||||||||||||
| Interpret the results. | ||||||||||||||||
| Mean | St error | t value | Low | to | High | |||||||||||
| Males | ||||||||||||||||
| Females | ||||||||||||||||
| <Reminder: standard error is the sample standard deviation divided by the square root of the sample size.> | ||||||||||||||||
| Interpretation: | ||||||||||||||||
| 2 | Using our sample data, construct a 95% confidence interval for the mean salary difference between the genders in the population. | |||||||||||||||
| How does this compare to the findings in week 2, question 2? | ||||||||||||||||
| Difference | St Err. | T value | Low | to | High | |||||||||||
| Yes/No | ||||||||||||||||
| Can the means be equal? | Why? | |||||||||||||||
| How does this compare to the week 2, question 2 result (2 sampe t-test)? | Results are the same - means are not equal. | |||||||||||||||
| a. | Why is using a two sample tool (t-test, confidence interval) a better choice than using 2 one-sample techniques when comparing two samples? | |||||||||||||||
| 3 | We found last week that the degree values within the population do not impact compa rates. | |||||||||||||||
| This does not mean that degrees are distributed evenly across the grades and genders. | ||||||||||||||||
| Do males and females have athe same distribution of degrees by grade? | ||||||||||||||||
| (Note: while technically the sample size might not be large enough to perform this test, ignore this limitation for this exercise.) | ||||||||||||||||
| Ignore any cell size limitations. | ||||||||||||||||
| What are the hypothesis statements: | ||||||||||||||||
| Ho: | ||||||||||||||||
| Ha: | ||||||||||||||||
| Note: You can either use the Excel Chi-related functions or do the calculations manually. | ||||||||||||||||
| Data InTables | The Observed Table is completed for you. | |||||||||||||||
| OBSERVED | A | B | C | D | E | F | Total | If desired, you can do manual calculations per cell here. | ||||||||
| M Grad | 1 | 1 | 1 | 1 | 5 | 3 | 12 | A | B | C | D | E | F | |||
| Fem Grad | 5 | 3 | 1 | 1 | 1 | 2 | 13 | M Grad | ||||||||
| Male Und | 2 | 2 | 2 | 1 | 5 | 1 | 13 | Fem Grad | ||||||||
| Female Und | 7 | 1 | 1 | 2 | 1 | 0 | 12 | Male Und | ||||||||
| 15 | 7 | 5 | 5 | 12 | 6 | 50 | Female Und | |||||||||
| Sum = | ||||||||||||||||
| EXPECTED | ||||||||||||||||
| M Grad | For this exercise - ignore the requirement for a correction | |||||||||||||||
| Fem Grad | for expected values less than 5. | |||||||||||||||
| Male Und | ||||||||||||||||
| Female Und | ||||||||||||||||
| Interpretation: | ||||||||||||||||
| What is the value of the chi square statistic: | ||||||||||||||||
| What is the p-value associated with this value: | ||||||||||||||||
| Is the p-value <0.05? | ||||||||||||||||
| Do you reject or not reject the null hypothesis: | ||||||||||||||||
| If you rejected the null, what is the Cramer's V correlation: | ||||||||||||||||
| What does this correlation mean? | ||||||||||||||||
| What does this decision mean for our equal pay question: | ||||||||||||||||
| 4 | Based on our sample data, can we conclude that males and females are distributed across grades in a similar pattern | |||||||||||||||
| within the population? | Again, ignore any cell size limitations. | |||||||||||||||
| What are the hypothesis statements: | ||||||||||||||||
| Ho: | ||||||||||||||||
| Ha: | ||||||||||||||||
| Do manual calculations per cell here (if desired) | ||||||||||||||||
| A | B | C | D | E | F | A | B | C | D | E | F | |||||
| OBS COUNT - m | M | |||||||||||||||
| OBS COUNT - f | F | |||||||||||||||
| Sum = | ||||||||||||||||
| EXPECTED | ||||||||||||||||
| What is the value of the chi square statistic: | ||||||||||||||||
| What is the p-value associated with this value: | ||||||||||||||||
| Is the p-value <0.05? | ||||||||||||||||
| Do you reject or not reject the null hypothesis: | ||||||||||||||||
| If you rejected the null, what is the Phi correlation: | ||||||||||||||||
| If calculated, what is the meaning of effect size measure: | ||||||||||||||||
| What does this decision mean for our equal pay question: | ||||||||||||||||
| 5. How do you interpret these results in light of our question about equal pay for equal work? | ||||||||||||||||
Week 5
| Week 5 | Correlation and Regression | ||||||||||||||||
| 1. | Create a correlation table for the variables in our data set. (Use analysis ToolPak or StatPlus:mac LE function Correlation.) | ||||||||||||||||
| a. | Reviewing the data levels from week 1, what variables can be used in a Pearson's Correlation table (which is what Excel produces)? | ||||||||||||||||
| b. Place table here (C8): | |||||||||||||||||
| c. | Using r = approximately .28 as the signicant r value (at p = 0.05) for a correlation between 50 values, what variables are | ||||||||||||||||
| significantly related to Salary? | |||||||||||||||||
| To compa? | |||||||||||||||||
| d. | Looking at the above correlations - both significant or not - are there any surprises -by that I | ||||||||||||||||
| mean any relationships you expected to be meaningful and are not and vice-versa? | |||||||||||||||||
| e. | Does this help us answer our equal pay for equal work question? | ||||||||||||||||
| 2 | Below is a regression analysis for salary being predicted/explained by the other variables in our sample (Midpoint, | ||||||||||||||||
| age, performance rating, service, gender, and degree variables. (Note: since salary and compa are different ways of | |||||||||||||||||
| expressing an employee’s salary, we do not want to have both used in the same regression.) | |||||||||||||||||
| Plase interpret the findings. | |||||||||||||||||
| Note: These values are not the same as the data the assignment uses. The purpose is to analyze the result of a regression test rather than directly answer our equal pay question. | |||||||||||||||||
| Ho: The regression equation is not significant. | |||||||||||||||||
| Ha: The regression equation is significant. | |||||||||||||||||
| Ho: The regression coefficient for each variable is not significant | Note: technically we have one for each input variable. | ||||||||||||||||
| Ha: The regression coefficient for each variable is significant | Listing it this way to save space. | ||||||||||||||||
| Sal | |||||||||||||||||
| SUMMARY OUTPUT | |||||||||||||||||
| Regression Statistics | |||||||||||||||||
| Multiple R | 0.9915590747 | ||||||||||||||||
| R Square | 0.9831893985 | ||||||||||||||||
| Adjusted R Square | 0.9808437332 | ||||||||||||||||
| Standard Error | 2.6575925726 | ||||||||||||||||
| Observations | 50 | ||||||||||||||||
| ANOVA | |||||||||||||||||
| df | SS | MS | F | Significance F | |||||||||||||
| Regression | 6 | 17762.2996738743 | 2960.383278979 | 419.1516111294 | 1.8121523852609E-36 | ||||||||||||
| Residual | 43 | 303.7003261257 | 7.062798282 | ||||||||||||||
| Total | 49 | 18066 | |||||||||||||||
| Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | ||||||||||
| Intercept | -1.7496212123 | 3.6183676583 | -0.4835388157 | 0.6311664899 | -9.0467550427 | 5.547512618 | -9.0467550427 | 5.547512618 | |||||||||
| Midpoint | 1.2167010505 | 0.0319023509 | 38.1382881163 | 8.66416336978111E-35 | 1.1523638283 | 1.2810382727 | 1.1523638283 | 1.2810382727 | Note: These values are not the same as in the data the assignment uses. The purpose is to analyze the result of a 2-way ANOVA test rather than directly answer our equal pay question. | ||||||||
| Age | -0.0046280102 | 0.065197212 | -0.0709847876 | 0.9437389875 | -0.1361107191 | 0.1268546987 | -0.1361107191 | 0.1268546987 | |||||||||
| Performace Rating | -0.0565964405 | 0.0344950678 | -1.6407110971 | 0.1081531819 | -0.1261623747 | 0.0129694936 | -0.1261623747 | 0.0129694936 | |||||||||
| Service | -0.0425003573 | 0.0843369821 | -0.5039350033 | 0.6168793519 | -0.2125820912 | 0.1275813765 | -0.2125820912 | 0.1275813765 | |||||||||
| Gender | 2.420337212 | 0.8608443176 | 2.8115852804 | 0.0073966188 | 0.684279192 | 4.156395232 | 0.684279192 | 4.156395232 | |||||||||
| Degree | 0.2755334143 | 0.7998023048 | 0.3445019009 | 0.732148119 | -1.3374216547 | 1.8884884833 | -1.3374216547 | 1.8884884833 | |||||||||
| Note: since Gender and Degree are expressed as 0 and 1, they are considered dummy variables and can be used in a multiple regression equation. | |||||||||||||||||
| Interpretation: | |||||||||||||||||
| For the Regression as a whole: | |||||||||||||||||
| What is the value of the F statistic: | |||||||||||||||||
| What is the p-value associated with this value: | |||||||||||||||||
| Is the p-value <0.05? | |||||||||||||||||
| Do you reject or not reject the null hypothesis: | |||||||||||||||||
| What does this decision mean for our equal pay question: | |||||||||||||||||
| For each of the coefficients: | Intercept | Midpoint | Age | Perf. Rat. | Service | Gender | Degree | ||||||||||
| What is the coefficient's p-value for each of the variables: | NA | ||||||||||||||||
| Is the p-value < 0.05? | NA | ||||||||||||||||
| Do you reject or not reject each null hypothesis: | NA | ||||||||||||||||
| What are the coefficients for the significant variables? | |||||||||||||||||
| Using the intercept coefficient and only the significant variables, what is the equation? | Salary = | ||||||||||||||||
| Is gender a significant factor in salary: | |||||||||||||||||
| If so, who gets paid more with all other things being equal? | |||||||||||||||||
| How do we know? | |||||||||||||||||
| 3 | Perform a regression analysis using compa as the dependent variable and the same independent | ||||||||||||||||
| variables as used in question 2. Show the result, and interpret your findings by answering the same questions. | |||||||||||||||||
| Note: be sure to include the appropriate hypothesis statements. | |||||||||||||||||
| Regression hypotheses | |||||||||||||||||
| Ho: | |||||||||||||||||
| Ha: | |||||||||||||||||
| Coefficient hyhpotheses (one to stand for all the separate variables) | |||||||||||||||||
| Ho: | |||||||||||||||||
| Ha: | |||||||||||||||||
| Place c94 in output box. | |||||||||||||||||
| Interpretation: | |||||||||||||||||
| For the Regression as a whole: | |||||||||||||||||
| What is the value of the F statistic: | |||||||||||||||||
| What is the p-value associated with this value: | |||||||||||||||||
| Is the p-value < 0.05? | |||||||||||||||||
| Do you reject or not reject the null hypothesis: | |||||||||||||||||
| What does this decision mean for our equal pay question: | |||||||||||||||||
| For each of the coefficients: | Intercept | Midpoint | Age | Perf. Rat. | Service | Gender | Degree | ||||||||||
| What is the coefficient's p-value for each of the variables: | NA | ||||||||||||||||
| Is the p-value < 0.05? | NA | ||||||||||||||||
| Do you reject or not reject each null hypothesis: | NA | ||||||||||||||||
| What are the coefficients for the significant variables? | |||||||||||||||||
| Using the intercept coefficient and only the significant variables, what is the equation? | Compa = | ||||||||||||||||
| Is gender a significant factor in compa: | |||||||||||||||||
| Regardless of statistical significance, who gets paid more with all other things being equal? | |||||||||||||||||
| How do we know? | |||||||||||||||||
| 4 | Based on all of your results to date, | ||||||||||||||||
| Do we have an answer to the question of are males and females paid equally for equal work? | |||||||||||||||||
| Does the company pay employees equally for for equal work? | |||||||||||||||||
| How do we know? | |||||||||||||||||
| Which is the best variable to use in analyzing pay practices - salary or compa? Why? | |||||||||||||||||
| What is most interesting or surprising about the results we got doing the analysis during the last 5 weeks? | |||||||||||||||||
| 5 | Why did the single factor tests and analysis (such as t and single factor ANOVA tests on salary equality) not provide a complete answer to our salary equality question? | ||||||||||||||||
| What outcomes in your life or work might benefit from a multiple regression examination rather than a simpler one variable test? | |||||||||||||||||