I need to do this lab as a report
Procedure:
1-
|
Nominal |
Measure |
|
22k |
21680 |
|
47k |
47293 |
|
1k |
979 |
|
470 |
465.5 |
2-
VC = 3.4731 V
VB = 1.4303 V
VE = 0.7461 V
VCE = 2.730 V
VBE = 0.6894 V
VCB = 2.0324 V
3-
IB = 9.79 µA
IC = 1.585 mA
4-
IE = IB + IC = 9.79 µA + 1.585 mA = 1.594 mA
5-
BDC = IC / IB = 1.585 mA / 9.79 µA = 161.899
You have to do in Submittal:
Number 3 ( OBJECTIVE )
Number 4 ( DATA ) part: ( b & c & d & e & f & g & h )
Number 5 ( DISCUSSION )
VCC
5.0V
R1
47kΩ
R2
22kΩ
RC
1kΩ
RE
470Ω
2N3904
Circuit 4-1