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Screenshot for Circuit 1:
Screenshot for Circuit 2:
Table 3-1:
|
|
Nominal |
Measured |
|
R1 |
1k Ω |
984 Ω |
|
RL1 |
1k Ω |
985 Ω |
|
RL2 |
680 Ω |
678 Ω |
Table 3-2:
|
|
RL = 1000 Ω |
|
Ch1 ( max ) |
19.7 V |
|
Ch1 ( min ) |
13.3 V |
|
Vrpp |
19.7 – 13.3 = 6.4 V |
|
Ch2 ( max ) |
4.8 V |
|
Ch2 ( min ) |
4.2 V |
|
Vout |
4.8 – 4.2 = 0.6 V |
Table 3-3:
|
|
RL = 680 Ω |
|
Ch1 ( max ) |
19.7 V |
|
Ch1 ( min ) |
13.5 V |
|
Vrpp |
19.7 – 13.5 = 6.2 V |
|
Ch2 ( max ) |
4.8 V |
|
Ch2 ( min ) |
4.0 V |
|
Vout |
4.8 – 4.2 = 0.8 V |
Table 3-4:
|
RL |
1000 Ω |
680 Ω |
|
IR1 |
(19.7 – 4.8 ) / 984 = 15.14 mA |
(19.7 – 4.8 ) / 984 = 15.14 mA |
|
ILoad |
4.8 / 985 = 4.87 mA |
4.8 / 678 = 7.08 mA |
|
IZener |
15.14 mA – 4.87 mA = 10.27 mA |
15.14 mA – 7.08 mA = 8.06 mA |
Sample calculations for 1k Ω & 680 Ω:
IR1: (VAPK – VBPK) / R1 = (19.7 – 4.8) / 984 = 15.14 mA
ILoad: VBPK / RL1 = 4.8 / 985 = 4.87 mA
IZener: IR1 - ILoad = 15.14 mA – 4.87 mA = 10.27 mA
ILoad: VBPK / RL1 = 4.8 / 678 = 7.08 mA
IZener: IR1 - ILoad = 15.14 mA – 7.08 mA = 8.06 mA
Q: What effect does lowering the load resistance have on the regulation of the circuit?
117.8Vrms
60Hz
0°
10µF
R1
1kΩ
RL
1KΩ
D2
D1
D3
D4
BA
Circuit 1
117.8Vrms
60Hz
0°
10µF
R1
1kΩ
RL
680Ω
D2
D1
D3
D4
BA
Circuit 2