matlab

2) To validate your function, provide plots of log(L10) for each bearing number as shown below. Validate two cases: a) Fr = 1449 lbf, Fa = 0 and b) Fr = 1449 lbf, Fa = 1310 lbf. Attach hardcopy of your validation plot.

3) Use your function to select the smallest bearing that can provide minimum L10 life of 100x106 revolutions with Fr = 2000 lbf and Fa = 1500 lbf applied and the inner race rotating. Specify expected L10 life, bearing bore, outside diameter and axial width with units mm.

brg number ________ L10 _________ bore _________ OD _________ width _________

% Figure 11-23 Norton *********************

% Bearing C Dynamic C0 Static

% Number Load Rating Load Rating

% [lbf] [lbf]

rating = [ 6300 1400 850 ;

6301 1700 1040 ;

6302 1930 1200 ;

6303 2320 1460 ;

6304 3000 1930 ;

6305 3800 2550 ;

6306 5000 3400 ;

6307 5700 4000 ;

6308 7350 5300 ;

6309 9150 6700 ;

6310 10600 8150 ;

6311 12900 10000 ;

6312 14000 10800 ;

6313 16000 12500 ;

6314 18000 14000 ;

6315 19300 16300 ;

6316 21200 18000 ;

6317 21600 18600 ;

6318 23200 20000 ;

6319 24500 22400 ;

6320 28500 27000 ];

% Figure 11-24 Norton **********

% Fa/C0 Y e

factors = [ 0.014 2.30 0.19 ;

0.028 1.99 0.22 ;

0.056 1.71 0.26 ;

0.084 1.55 0.28 ;

0.11 1.45 0.30 ;

0.17 1.31 0.34 ;

0.28 1.15 0.38 ;

0.42 1.04 0.42 ;

0.56 1.00 0.44 ];

63006302630463066308631063126314631663186320

-0.5

0

0.5

1

1.5

2

2.5

3

3.5

4

Bearing Number

Log of L10 life [millions of revs]

ME 360 - Project 3 - HJSIII

a) Fr=1449 lbf, Fa=0

b) Fr=1449 lbf, Fa=1310 lbf