i have a lab report needs to be paraphrased

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strength_of_materials_lab_1.docx

Strength of materials

MET 2120

Lab 3

Meshal Al-Khalil

· Introduction

In this lab we will learn about how to calculate stresses and strains in different parts of a member with the same material, we will learn about how to calculate statically indeterminate problems, calculating the reactions and forces in our material.

· Calculations

· Calculations from ex. 10-15

exaple 10-15

Given

Lac (in)

Lcb (in)

Area ac (in^2)

Area cb (in)^2

Force (lb)

10

8

6

3

100000

calculated

stress ac

stress cb

-10.2563

12.82

exaple 10-16

Given

Lac (mm)

Lcd (mm)

Ldb (mm)

Force c (kn)

Force d (kn)

200

600

300

80

160

calculated

Ra (Kn)

Rb (Kn)

48

32

· Discussion and equations

In this lab you can find that the highlighted boxes are what we calculated during this lab the rest are given in the example.

· In the first part of the lab we were given an example (ex.10-15) and we had to calculate the axial stress in CB and AC, we used these formulas to solve the equation

·

E= (stress/strain)

= (P/A)/( δ/L)

= (P)(L)/(A)( δ)

ΣFx = Ra+Rb-Pc=0

= Ra+Rb=100

δAC = (PAC)(LAC)/(AAC)(E)

= (-Ra)(10)/(6)(E)

δCB = (PCB)(LCB)/(ACB)(E)

= (Rb)(8)/(3)(E)

δ = Elongation

F = Force

L = length

A = Area

P = Force

· In the second part of the lab ex. 10-16 we had to calculate the different reaction forces, we did this by using the formulas below

ΣFx = -Ra+Pc-Pd+Rb=0

= -Ra+Rb=80 Kn

Rb = (80+Ra)

Ra = (db)/(a+b)

Rb = (da)/(a+b)

d = distance

a = distance a

b = distance b

· Conclusion

I can conclude that in this lab we learned a lot about different stresses, we learned how to calculate statically indeterminate problems, we learned how to calculate different reactions, as well as solving equations with constant area and elasticity

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