i have a lab report from past year need to be paraphrased

Strength of materials

MET 2120

Lab 1 & 2

Meshal Al-Khalil

· Introduction

In this lab we will learn about different stresses and strains in various materials, we will learn how to calculate different stresses, forces and deformation in different materials such as (Aluminum, and brass) we calculate these forces using a couple new formulas shown in the discussion part below.

· Calculations

· Calculations from ex. 9-3 & 9-5

section	force (lbf)	area (in^2)	stress (lb/in^2)
1	50000	3.14	15923.56688
2	10000	3.14	3184.713376
3	20000	3.14	6369.426752
section	force (N)	area (m^2)	stress (N/m^2)
1	140000	0.002827433	49514871.18
2	60000	0.001256637	47746482.93
3	20000	0.000314159	63661977.24

· Graphs that show how the force effects the stress

· Calculations from lab 2

INPUT FROM 10-2
Element	Elasticity (n/m^2)	Area (m^2)	Length (m)	Force (N)
1	7.00E+10	0.000314159	3.078760801	25000

OUTPUT from 10-2
Element	Normal stress	Unit deformation	Total deformation (m)
1			0.0035

INPUT FROM 10-8
Element	Elasticity (n/m^2)	Area (m^2)	Length (m)	Force (N)
1	7.00E+10	0.000706858	2	30000
2	7.00E+10	0.000706858	1.5	20000
3
4
5

OUTPUT from 10-8
Element	Normal stress (Pa)	Unit deformation (mm)	Total deformation (mm)	Stress is in
1	42441318.16	1.21260909		Tension
2	28294212.11	0.606304545		Tension
3			1.818913635

INPUT FROM 10-9
Element	Elasticity (Psi)	Area (in^2)	Length (in)	Force (lb)	Stress is in
1	1.70E+07	2	36	30000	Tension
2	1.70E+07	2	24	10000	Compression
3	1.70E+07	2	48	20000	Tension

OUTPUT from 10-9
Element	Normal stress (Psi)	Unit deformation (in)	Total deformation (in)
1	15000	0.031764706
2	5000	-0.007058824
3	10000	0.028235294
			0.052941176

INPUT FROM 10-11
Element	Elasticity (Pa)	Area (m^2)	Length (m)	Force (n)	Stress is in
1	2.1E+11	0.000706858	1.2	100000	Tension
2	2.1E+11	0.001256637	1.8	125000	Compression
3	2.1E+11	0.000490874	1.7	50000	Tension

OUTPUT FROM 10-11
ELEMENT	Normal stress (PA)	Unit deformation (mm)	Total deformation (mm)
1	141471060.5	0.80840606
2	99471839.43	-0.852615767
3	101859163.6	0.824574181
			0.780364475

· Discussion

In this lab you can find that the highlighted boxes are what we calculated during this lab the rest are given in the example.

· In the first part of the lab we were given an example (ex.9-3 & 9-5) and we had to calculate the normal stress, we did this first by calculated the area by using (pi/4)(d)^2 then we plugged in into the normal stress equation which is σ = F/A

pi = 3.14

F = Force

D = diameter

A = area

· In the second part of the lab ex. 10-2 we had to calculate the original length of the material, we did this by manipulating the elongation formula in order to find the length

The elongation formula δ = (F)(L)/(A)(E)

δ = elongation

L = Length

E = material elasticity

We found the length by using L = (δ)(A)(E)/(F)

· In examples 10-8, 10-9 and 10-11 we had to calculate the deformation of each unit then the total deformation of our material

We first calculated the normal stress using σ = F/A

Then we calculated the deformation of each section of our material using the elongation formula, which is [δ = (F)(L)/(A)(E)]

We took the deformation from each section and added them to get the total deformation of our material.

· Conclusion

I can conclude that in this lab we learned a lot about different kinds of stresses and strains, we learned how they can affect different materials. We also learned how to calculate the deformation and normal stresses in our materials, this lab helped us understand more about what we have been studying in class, and most importantly to pay attention to our units.

force and stress in figure 9-3

force (lbf)

50000.0 10000.0 20000.0 stress (lb/in^2)

15923.56687898089 3184.713375796178 6369.426751592356

force and stress in figure 9-5

force (N)

140000.0 60000.0 20000.0 stress (N/m^2)

4.95148711841452E7 4.77464829275686E7 6.36619772367581E7

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