Information system questions i need the answers in 3hrs please

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isds_test_practice_problems.docx

Burger Q sells about 500 DoubleHappinness burgers daily. It is their

trademarked star seller that is a double burger.  As their customers

are rather unpredictable, they need to carry extra 750 burgers.

Burger Q buys the patties from John’s Farm, who can deliver them in 3

days, at 25 cents each plus $80 flat-rate charge.  Financing comes

from Bank Krupt at 10% per year

What is the reorder point?

Select one:

a. 3750

b. 3000

c. 2250

d. 3500

e. 4500

Burger Q sells about 500 DoubleHappinness burgers daily. It is their

trademarked star seller that is a double burger.  As their customers

are rather unpredictable, they need to carry extra 750 burgers.

Burger Q buys the patties from John’s Farm, who can deliver them in 3

days, at 25 cents each plus $80 flat-rate charge.  Financing comes

from Bank Krupt at 10% per year

Now John’s Farm offers the following discount schedule:

             1  -    249999 25 cents

   250000  -    499999 24 cents

   500000  -    749999 23 cents

   750000  -  1499999 22 cents

 1500000  -  2999999 21 cents

 3000000 -                  20 cents

What is the order quantity?

Select one:

a. 3000000

b. 750000

c. 500000

d. 1500000

e. 34176

Burger Q sells about 500 DoubleHappinness burgers daily. It is their

trademarked star seller that is a double burger. As their customers

are rather unpredictable, they need to carry extra patties for 750

DoubleHappiness burgers. Financing comes from Bank Krupt at 10% per

year.

Now, they are opening their own farm and butchering facility.  This

makes the cost per patty down to be at $0.15 with only 1 day needed

for delivery.  This facility can produce 21000 patties weekly.

However, it costs them $500 every time they prepare the patties.

What is the production quantity?

Select one:

a. 203882

b. 159844

c. 191182

d. 120864

e. 154212

Burger Q sells about 500 DoubleHappinness burgers daily. It is their

trademarked star seller that is a double burger. As their customers

are rather unpredictable, they need to carry extra patties for 750

DoubleHappiness burgers. Financing comes from Bank Krupt at 10% per

year.

Now, they are opening their own farm and butchering facility.  This

makes the cost per patty down to be at $0.15 with only 1 day needed

for delivery.  This facility can produce 21000 patties weekly.

However, it costs them $500 every time they prepare the patties.

What is the total annual cost?

Select one:

a. $34521

b. $28896

c. $56682

d. $66313

e. $57056

Business Daily sells its newspapers for $.75 in coinoperated kiosks,

each of which is designed to hold up to 60 papers. The production and

delivery costs of each newspaper equal $.60, but Business Daily

receives approximately $.23 in advertising revenue for each paper sold

to compensate production cost. Any newspapers that remain at the end

of the day are sold to a recycling center. Business Daily estimates

that the revenue it receives from the recycling center will only cover

the cost of transporting the papers to the center. Management at

Business Daily estimates that the goodwill cost of not having enough

papers in the kiosk to satisfy customer demand is $1.50 per

unsatisfied customer. Demand for the Thursday paper at a particular

kiosk is estimated to follow a Poisson distribution with a mean λ=36

units. (Hint: Remember from 361A that the Poisson distribution can be

approximated by a normal distribution with μ=λ and σ=sqrt(λ) )

How many newspapers should be stocked?

Select one:

a. 42

b. 41

c. 40

d. 43

e. 44

United Parcel Delivery (UPD) owns a fleet of 1800 delivery trucks

serving the metropolitan Chicago area. All trucks are maintained at a

central garage. On the average, four trucks a week require a new

engine. Engines cost $900 each, and the delivery time is two weeks.

There is a fixed order cost of $130, and UPD uses an annual inventory

holding cost rate of 30%. For each week a truck is out of service, UPD

estimates it suffers a loss of $80.  That is in addition to about

$1000 they need to allocate for administrative cost to answer customer

complaints.

What is the reorder point?

Select one:

a. 10

b. 6

c. 8

d. 4

United Parcel Delivery (UPD) owns a fleet of 1800 delivery trucks

serving the metropolitan Chicago area. All trucks are maintained at a

central garage. On the average, four trucks a week require a new

engine. Engines cost $900 each, and the delivery time is two weeks.

There is a fixed order cost of $130, and UPD uses an annual inventory

holding cost rate of 30%. For each week a truck is out of service, UPD

estimates it suffers a loss of $80.  That is in addition to about

$1000 they need to allocate for administrative cost to answer customer

complaints.

How many spare engins are allowed to be in repair/not ready?

Select one:

a. 0

b. 4

c. 1

d. 2

e. 3

To inspect the utilization of in-house mechanics for engine repair,

United Parcel Delivery (UPD) is now doing a simulation.  Each engine

costs $900 to repair.  The holding cost for an engine that is being

repaired is $80. The probability of new repair for engine for each

week is given by:

Probability    New Repair

15%    1

20%    2

30%    3

35%    4

While the weekly probability engine finished with the repair process

is given by:

Probability    Repaired

50%    1

20%    2

10%    3

20%    4

Use the random numbers provided: column A for new repair and column B

for repaired. Do not use rand() function.

Random 1    Random 2

0.166119    0.393304

0.087571    0.31857

0.260241    0.822331

0.044354    0.167577

0.390011    0.595165

0.414265    0.848542

0.672457    0.658607

0.454708    0.048241

0.279303    0.698857

0.662554    0.410256

0.662554    0.410256

What is the cost for week 8?

Select one:

a. $1380

b. $2120

c. $1880

d. $980

e. $1580

To inspect the utilization of in-house mechanics for engine repair,

United Parcel Delivery (UPD) is now doing a simulation.  Each engine

costs $900 to repair.  The holding cost for an engine that is being

repaired is $80. The probability of new repair for engine for each

week is given by:

Probability    New Repair

15%    1

20%    2

30%    3

35%    4

While the weekly probability engine finished with the repair process

is given by:

Probability    Repaired

50%    1

20%    2

10%    3

20%    4

Use the random numbers provided: column A for new repair and column B

for repaired. Do not use rand() function.

Random 1    Random 2

0.166119    0.393304

0.087571    0.31857

0.260241    0.822331

0.044354    0.167577

0.390011    0.595165

0.414265    0.848542

0.672457    0.658607

0.454708    0.048241

0.279303    0.698857

0.662554    0.410256

0.662554    0.410256

What is the cost for week 3?

Select one:

a. $1880

b. $1580

c. $900

d. $1380

e. $2280

To inspect the utilization of in-house mechanics for engine repair,

United Parcel Delivery (UPD) is now doing a simulation.  Each engine

costs $900 to repair.  The holding cost for an engine that is being

repaired is $80. The probability of new repair for engine for each

week is given by:

Probability    New Repair

15%    1

20%    2

30%    3

35%    4

While the weekly probability engine finished with the repair process

is given by:

Probability    Repaired

50%    1

20%    2

10%    3

20%    4

Use the random numbers provided: column A for new repair and column B

for repaired. Do not use rand() function.

Random 1    Random 2

0.166119    0.393304

0.087571    0.31857

0.260241    0.822331

0.044354    0.167577

0.390011    0.595165

0.414265    0.848542

0.672457    0.658607

0.454708    0.048241

0.279303    0.698857

0.662554    0.410256

0.662554    0.410256

How many engines were repaired in week 3?

Select one:

a. 4

b. 1

c. 5

d. 3

e. 2

To inspect the utilization of in-house mechanics for engine repair,

United Parcel Delivery (UPD) is now doing a simulation.  Each engine

costs $900 to repair.  The holding cost for an engine that is being

repaired is $80. The probability of new repair for engine for each

week is given by:

Probability    New Repair

15%    1

20%    2

30%    3

35%    4

While the weekly probability engine finished with the repair process

is given by:

Probability    Repaired

50%    1

20%    2

10%    3

20%    4

Use the random numbers provided: column A for new repair and column B

for repaired. Do not use rand() function.

Random 1    Random 2

0.166119    0.393304

0.087571    0.31857

0.260241    0.822331

0.044354    0.167577

0.390011    0.595165

0.414265    0.848542

0.672457    0.658607

0.454708    0.048241

0.279303    0.698857

0.662554    0.410256

0.662554    0.410256

How many engines were repaired in week 8?

Select one:

a. 5

b. 3

c. 4

d. 2

e. 1

To inspect the utilization of in-house mechanics for engine repair,

United Parcel Delivery (UPD) is now doing a simulation.  Each engine

costs $900 to repair.  The holding cost for an engine that is being

repaired is $80. The probability of new repair for engine for each

week is given by:

Probability    New Repair

15%    1

20%    2

30%    3

35%    4

While the weekly probability engine finished with the repair process

is given by:

Probability    Repaired

50%    1

20%    2

10%    3

20%    4

Use the random numbers provided: column A for new repair and column B

for repaired. Do not use rand() function.

Random 1    Random 2

0.166119    0.393304

0.087571    0.31857

0.260241    0.822331

0.044354    0.167577

0.390011    0.595165

0.414265    0.848542

0.672457    0.658607

0.454708    0.048241

0.279303    0.698857

0.662554    0.410256

0.662554    0.410256

Which statement is true?

Select one:

a. Based on a decreasing trend of the number of end inventory of

engine being repaired (p-value=0.48), UPD doesn't to hire additional

mechanics.

b. Based on a decreasing trend of the number of end inventory of

engine being repaired (p-value=0.24), UPD doesn't to hire additional

mechanics.

c. Based on an increasing trend of the number of end inventory of

engine being repaired (p-value=0.24), UPD needs to hire additional

mechanics.

d. Based on no trend of the number of end inventory of engine being

repaired (p-value=0.008), UPD does not need to hire additional

mechanics.

e. Based on an increasing trend of the number of end inventory of

engine being repaired (p-value=0.48), UPD needs to hire additional

mechanics.

To inspect the utilization of in-house mechanics for engine repair,

United Parcel Delivery (UPD) is now doing a simulation.  Each engine

costs $900 to repair.  The holding cost for an engine that is being

repaired is $80. The probability of new repair for engine for each

week is given by:

Probability    New Repair

15%    1

20%    2

30%    3

35%    4

While the weekly probability engine finished with the repair process

is given by:

Probability    Repaired

50%    1

20%    2

10%    3

20%    4

Use the random numbers provided: column A for new repair and column B

for repaired. Do not use rand() function.

Random 1    Random 2

0.166119    0.393304

0.087571    0.31857

0.260241    0.822331

0.044354    0.167577

0.390011    0.595165

0.414265    0.848542

0.672457    0.658607

0.454708    0.048241

0.279303    0.698857

0.662554    0.410256

0.662554    0.410256

Which statement is true?

Select one:

a. Based on the cost, UPD doesn’t need to hire additional mechanics

since there is sufficient evidence that cost is decreasing

(p-value=0.003)

b. Based on the cost, UPD does not need to hire additional mechanics

since there is sufficient evidence that cost is decreasing

(p-value=0.08)

c. Based on the cost, UPD doesn’t need to hire additional mechanics

since there is no sufficient evidence that cost is increasing

(p-value=0.008)

d. Based on the cost, UPD doesn’t need to hire additional mechanics

since there is no sufficient evidence that cost is increasing

(p-value=0.01)

e. Based on the cost, UPD needs to hire additional mechanics since

there is sufficient evidence that cost is increasing (p-value=0.08)

Replication    Days

1    55

2    52

3    55

4    55

5    52

6    50

7    55

8    50

9    54

10    53

We want to see if the mean is equal to 52 or not. Do an appropriate

hypothesis testing.

What is the sample standard deviation?

Select one:

a. 2.0248

b. 1.5055

c. We don’t know the sample standard deviation for this type of testing

d. 1.5239

e. 1.4944

Suppose that 10 replications of a simulation give these results:

Replication    Days

1    53

2    52

3    54

4    50

5    50

6    54

7    52

8    54

9    52

10    53

We want to see if the mean is equal to 52 or not. Do an appropriate

hypothesis testing.

What is the σ?

Select one:

a. 1.5239

b. 1.5055

c. 2.0248

d. 1.4944