Information system questions i need the answers in 3hrs please
Burger Q sells about 500 DoubleHappinness burgers daily. It is their
trademarked star seller that is a double burger. As their customers
are rather unpredictable, they need to carry extra 750 burgers.
Burger Q buys the patties from John’s Farm, who can deliver them in 3
days, at 25 cents each plus $80 flat-rate charge. Financing comes
from Bank Krupt at 10% per year
What is the reorder point?
Select one:
a. 3750
b. 3000
c. 2250
d. 3500
e. 4500
Burger Q sells about 500 DoubleHappinness burgers daily. It is their
trademarked star seller that is a double burger. As their customers
are rather unpredictable, they need to carry extra 750 burgers.
Burger Q buys the patties from John’s Farm, who can deliver them in 3
days, at 25 cents each plus $80 flat-rate charge. Financing comes
from Bank Krupt at 10% per year
Now John’s Farm offers the following discount schedule:
1 - 249999 25 cents
250000 - 499999 24 cents
500000 - 749999 23 cents
750000 - 1499999 22 cents
1500000 - 2999999 21 cents
3000000 - 20 cents
What is the order quantity?
Select one:
a. 3000000
b. 750000
c. 500000
d. 1500000
e. 34176
Burger Q sells about 500 DoubleHappinness burgers daily. It is their
trademarked star seller that is a double burger. As their customers
are rather unpredictable, they need to carry extra patties for 750
DoubleHappiness burgers. Financing comes from Bank Krupt at 10% per
year.
Now, they are opening their own farm and butchering facility. This
makes the cost per patty down to be at $0.15 with only 1 day needed
for delivery. This facility can produce 21000 patties weekly.
However, it costs them $500 every time they prepare the patties.
What is the production quantity?
Select one:
a. 203882
b. 159844
c. 191182
d. 120864
e. 154212
Burger Q sells about 500 DoubleHappinness burgers daily. It is their
trademarked star seller that is a double burger. As their customers
are rather unpredictable, they need to carry extra patties for 750
DoubleHappiness burgers. Financing comes from Bank Krupt at 10% per
year.
Now, they are opening their own farm and butchering facility. This
makes the cost per patty down to be at $0.15 with only 1 day needed
for delivery. This facility can produce 21000 patties weekly.
However, it costs them $500 every time they prepare the patties.
What is the total annual cost?
Select one:
a. $34521
b. $28896
c. $56682
d. $66313
e. $57056
Business Daily sells its newspapers for $.75 in coinoperated kiosks,
each of which is designed to hold up to 60 papers. The production and
delivery costs of each newspaper equal $.60, but Business Daily
receives approximately $.23 in advertising revenue for each paper sold
to compensate production cost. Any newspapers that remain at the end
of the day are sold to a recycling center. Business Daily estimates
that the revenue it receives from the recycling center will only cover
the cost of transporting the papers to the center. Management at
Business Daily estimates that the goodwill cost of not having enough
papers in the kiosk to satisfy customer demand is $1.50 per
unsatisfied customer. Demand for the Thursday paper at a particular
kiosk is estimated to follow a Poisson distribution with a mean λ=36
units. (Hint: Remember from 361A that the Poisson distribution can be
approximated by a normal distribution with μ=λ and σ=sqrt(λ) )
How many newspapers should be stocked?
Select one:
a. 42
b. 41
c. 40
d. 43
e. 44
United Parcel Delivery (UPD) owns a fleet of 1800 delivery trucks
serving the metropolitan Chicago area. All trucks are maintained at a
central garage. On the average, four trucks a week require a new
engine. Engines cost $900 each, and the delivery time is two weeks.
There is a fixed order cost of $130, and UPD uses an annual inventory
holding cost rate of 30%. For each week a truck is out of service, UPD
estimates it suffers a loss of $80. That is in addition to about
$1000 they need to allocate for administrative cost to answer customer
complaints.
What is the reorder point?
Select one:
a. 10
b. 6
c. 8
d. 4
United Parcel Delivery (UPD) owns a fleet of 1800 delivery trucks
serving the metropolitan Chicago area. All trucks are maintained at a
central garage. On the average, four trucks a week require a new
engine. Engines cost $900 each, and the delivery time is two weeks.
There is a fixed order cost of $130, and UPD uses an annual inventory
holding cost rate of 30%. For each week a truck is out of service, UPD
estimates it suffers a loss of $80. That is in addition to about
$1000 they need to allocate for administrative cost to answer customer
complaints.
How many spare engins are allowed to be in repair/not ready?
Select one:
a. 0
b. 4
c. 1
d. 2
e. 3
To inspect the utilization of in-house mechanics for engine repair,
United Parcel Delivery (UPD) is now doing a simulation. Each engine
costs $900 to repair. The holding cost for an engine that is being
repaired is $80. The probability of new repair for engine for each
week is given by:
Probability New Repair
15% 1
20% 2
30% 3
35% 4
While the weekly probability engine finished with the repair process
is given by:
Probability Repaired
50% 1
20% 2
10% 3
20% 4
Use the random numbers provided: column A for new repair and column B
for repaired. Do not use rand() function.
Random 1 Random 2
0.166119 0.393304
0.087571 0.31857
0.260241 0.822331
0.044354 0.167577
0.390011 0.595165
0.414265 0.848542
0.672457 0.658607
0.454708 0.048241
0.279303 0.698857
0.662554 0.410256
0.662554 0.410256
What is the cost for week 8?
Select one:
a. $1380
b. $2120
c. $1880
d. $980
e. $1580
To inspect the utilization of in-house mechanics for engine repair,
United Parcel Delivery (UPD) is now doing a simulation. Each engine
costs $900 to repair. The holding cost for an engine that is being
repaired is $80. The probability of new repair for engine for each
week is given by:
Probability New Repair
15% 1
20% 2
30% 3
35% 4
While the weekly probability engine finished with the repair process
is given by:
Probability Repaired
50% 1
20% 2
10% 3
20% 4
Use the random numbers provided: column A for new repair and column B
for repaired. Do not use rand() function.
Random 1 Random 2
0.166119 0.393304
0.087571 0.31857
0.260241 0.822331
0.044354 0.167577
0.390011 0.595165
0.414265 0.848542
0.672457 0.658607
0.454708 0.048241
0.279303 0.698857
0.662554 0.410256
0.662554 0.410256
What is the cost for week 3?
Select one:
a. $1880
b. $1580
c. $900
d. $1380
e. $2280
To inspect the utilization of in-house mechanics for engine repair,
United Parcel Delivery (UPD) is now doing a simulation. Each engine
costs $900 to repair. The holding cost for an engine that is being
repaired is $80. The probability of new repair for engine for each
week is given by:
Probability New Repair
15% 1
20% 2
30% 3
35% 4
While the weekly probability engine finished with the repair process
is given by:
Probability Repaired
50% 1
20% 2
10% 3
20% 4
Use the random numbers provided: column A for new repair and column B
for repaired. Do not use rand() function.
Random 1 Random 2
0.166119 0.393304
0.087571 0.31857
0.260241 0.822331
0.044354 0.167577
0.390011 0.595165
0.414265 0.848542
0.672457 0.658607
0.454708 0.048241
0.279303 0.698857
0.662554 0.410256
0.662554 0.410256
How many engines were repaired in week 3?
Select one:
a. 4
b. 1
c. 5
d. 3
e. 2
To inspect the utilization of in-house mechanics for engine repair,
United Parcel Delivery (UPD) is now doing a simulation. Each engine
costs $900 to repair. The holding cost for an engine that is being
repaired is $80. The probability of new repair for engine for each
week is given by:
Probability New Repair
15% 1
20% 2
30% 3
35% 4
While the weekly probability engine finished with the repair process
is given by:
Probability Repaired
50% 1
20% 2
10% 3
20% 4
Use the random numbers provided: column A for new repair and column B
for repaired. Do not use rand() function.
Random 1 Random 2
0.166119 0.393304
0.087571 0.31857
0.260241 0.822331
0.044354 0.167577
0.390011 0.595165
0.414265 0.848542
0.672457 0.658607
0.454708 0.048241
0.279303 0.698857
0.662554 0.410256
0.662554 0.410256
How many engines were repaired in week 8?
Select one:
a. 5
b. 3
c. 4
d. 2
e. 1
To inspect the utilization of in-house mechanics for engine repair,
United Parcel Delivery (UPD) is now doing a simulation. Each engine
costs $900 to repair. The holding cost for an engine that is being
repaired is $80. The probability of new repair for engine for each
week is given by:
Probability New Repair
15% 1
20% 2
30% 3
35% 4
While the weekly probability engine finished with the repair process
is given by:
Probability Repaired
50% 1
20% 2
10% 3
20% 4
Use the random numbers provided: column A for new repair and column B
for repaired. Do not use rand() function.
Random 1 Random 2
0.166119 0.393304
0.087571 0.31857
0.260241 0.822331
0.044354 0.167577
0.390011 0.595165
0.414265 0.848542
0.672457 0.658607
0.454708 0.048241
0.279303 0.698857
0.662554 0.410256
0.662554 0.410256
Which statement is true?
Select one:
a. Based on a decreasing trend of the number of end inventory of
engine being repaired (p-value=0.48), UPD doesn't to hire additional
mechanics.
b. Based on a decreasing trend of the number of end inventory of
engine being repaired (p-value=0.24), UPD doesn't to hire additional
mechanics.
c. Based on an increasing trend of the number of end inventory of
engine being repaired (p-value=0.24), UPD needs to hire additional
mechanics.
d. Based on no trend of the number of end inventory of engine being
repaired (p-value=0.008), UPD does not need to hire additional
mechanics.
e. Based on an increasing trend of the number of end inventory of
engine being repaired (p-value=0.48), UPD needs to hire additional
mechanics.
To inspect the utilization of in-house mechanics for engine repair,
United Parcel Delivery (UPD) is now doing a simulation. Each engine
costs $900 to repair. The holding cost for an engine that is being
repaired is $80. The probability of new repair for engine for each
week is given by:
Probability New Repair
15% 1
20% 2
30% 3
35% 4
While the weekly probability engine finished with the repair process
is given by:
Probability Repaired
50% 1
20% 2
10% 3
20% 4
Use the random numbers provided: column A for new repair and column B
for repaired. Do not use rand() function.
Random 1 Random 2
0.166119 0.393304
0.087571 0.31857
0.260241 0.822331
0.044354 0.167577
0.390011 0.595165
0.414265 0.848542
0.672457 0.658607
0.454708 0.048241
0.279303 0.698857
0.662554 0.410256
0.662554 0.410256
Which statement is true?
Select one:
a. Based on the cost, UPD doesn’t need to hire additional mechanics
since there is sufficient evidence that cost is decreasing
(p-value=0.003)
b. Based on the cost, UPD does not need to hire additional mechanics
since there is sufficient evidence that cost is decreasing
(p-value=0.08)
c. Based on the cost, UPD doesn’t need to hire additional mechanics
since there is no sufficient evidence that cost is increasing
(p-value=0.008)
d. Based on the cost, UPD doesn’t need to hire additional mechanics
since there is no sufficient evidence that cost is increasing
(p-value=0.01)
e. Based on the cost, UPD needs to hire additional mechanics since
there is sufficient evidence that cost is increasing (p-value=0.08)
Replication Days
1 55
2 52
3 55
4 55
5 52
6 50
7 55
8 50
9 54
10 53
We want to see if the mean is equal to 52 or not. Do an appropriate
hypothesis testing.
What is the sample standard deviation?
Select one:
a. 2.0248
b. 1.5055
c. We don’t know the sample standard deviation for this type of testing
d. 1.5239
e. 1.4944
Suppose that 10 replications of a simulation give these results:
Replication Days
1 53
2 52
3 54
4 50
5 50
6 54
7 52
8 54
9 52
10 53
We want to see if the mean is equal to 52 or not. Do an appropriate
hypothesis testing.
What is the σ?
Select one:
a. 1.5239
b. 1.5055
c. 2.0248
d. 1.4944