all_7_wrong.docx

6

Power transmitted through conductor of cross sectional area A and thermal conductivity is

P=KAdT/L

=>Pcopper=Paluminium

KCA(TC-T)/L =KAlA(Tal-T)/L

=>Tc=[(Kc-Kal)T+KalTal]/Kc

Tc=[(397-238)*100+238*177]/397

Tc=146.2oC

5

Speed of sound in air is 343.06 m/s and frequency f = 349.23Hz. Wavelength λ = c / f. The wavelength λ = 343.06 / 349.23 = 0.98233 m = 98.233 cm.

4

At t=0s the center of pulled is 1m from origin and at t-1.8s center of pulse is 4 m from the origin.

So in a time interval of 1.8s it travelled a distance of 4m-1m =3m.

    So velocity v = distance travelled by wave/ time taken

                           = 3m/1.8s

                            = 30/18

                            = 5/3 =1.66m/s

3

A. According to statistical mechanics, where air has greater kinetic energy it has a greater probability to occupy a higher gravitational potential than less energetic air. That is, the system tends toward maximal entropy. B. Actually, because of the modern seal and insulation systems on refrigerators and freezers, the flow of hot and cold air no longer matters. Freezers are effectively isolated and so can be top, bottom, or side and will not be affected by hot air flow. In fact, many R/F now have interconnecting passageways so you can use the coldness of the freezer to enhance your vegetable and meat drawer temperature.

2

1

Joint movement can be estimated by the following equation:

ormula 1

Where:

elta L= The expected change in slab length, in inches.

C = the base/slab frictional restraint factor (0. 65 for stabilized bases, 0. 8 for granular bases).

L = the slab length, in inches.

mega= The PCC coefficient of thermal expansion (see Table 1 for typical values).

elta T= The maximum temperature range (generally the temperature of the concrete at the time of placement minus the average daily minimum temperature in January, in °F) .

C:\Users\abdullah\AppData\Local\Microsoft\Windows\INetCache\Content.Word\7.jpg

We know that the time period means time taken by the wave to complete one complete cycle.

So here in the problem, time period T = (2 s)/3

            = 0.667 s

From this frequency is f = 1 / T

        = 1.5 Hz

Speed of wave is v = 1.00 m/s

Then the distance between two adjacent crests on the waves is = v / f

                     = (1.00m/s) /(1.5Hz)

                     = 0.667 m