Algartham
OMG
comments_needed.docxI am having some trouble getting this to compile, I have made several changes and still not having any luck. Can someone please give me some guidance on how to correct this. thank you in advance.
Chad
#include <stdio.h> #include <stdlib.h>
int main() {//Created by Chad Hartley //October 30, 2015 char Month;//Variable for the character the user will input. //Ask which month needs to be converted. //I used the third character in the months that had the same first letter, except for June I had to use the second character. //I included a Key for the user to reference to know which character is expected. printf("Please use the following letter to represent the month you want converted: \n"); printf("J=January,F=February,M=March,A=April,Y=May,U=June,L=July,G=August,S=September,O=October,N=November,D=December \n"); scanf("%c",&Month); switch(Month)//switching statement used to look for the character inputed { case J: printf("01"); printf("\n");//used to print a new line break;//I used break to not have a continuous output case F: printf("02"); printf("\n"); break; case M: printf("03"); printf("\n"); break; case A: printf("04"); printf("\n"); break; case Y: printf(“05"); printf("\n"); break; case U: printf("06"); printf("\n"); break; case L: printf("07"); printf("\n"); break; case G: printf("08"); printf("\n"); break; case S: printf("09"); printf("\n"); break; case O: printf("10"); printf("\n"); break; case N: printf("11"); printf("\n"); break; case D: printf("12"); printf("\n"); break; default: printf("Please enter a valid character.");//This is a default statement to cover any other character the user may input. printf("\n"); } return 0; }
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This program will allow a character value for a month to be entered and an output a number corresponding to the month. A switch statement will be used to convert from a character to a number the print out the result.
#include <stdio.h>
int main(void) {
/* variable definition */
int J = 1; 6; 7;
int F = 2;
int M = 3; 5;
int A = 4; 8;
int S = 9;
int O = 10;
int N = 11;
int D = 12;
/* the switch statement */
switch (1) <-------- The switch statement is where the number of the character will be placed to convert.
{
case 1: <-----The case scenario execute the conversion
case 6:
case 7:
printf ("J is equal to 1, 6 or 7\n"); <--------The switch is then printed out.
break; <------ This break ends case 1 etc.
case 2:
printf ("F is equal 2\n");
break;
case 3:
case 5:
printf ("M is equal 3 or 5\n");
break;
case 4:
case 8:
printf ("A is equal 4 or 8\n");
break;
case 9:
printf ("S is equal 9\n");
break;
case 10:
printf ("O is equal 10\n");
break;
case 11:
printf ("N is equal 11\n");
case 12:
printf ("D is equal 12\n");
return 0;
}
}
Inputs from Character to Number
· Success time: 0 memory: 2156 signal:0
· J is equal to 1, 6 or 7
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COMMENTBELOW
Overview: The program calculates the average prices of 3 products in 3 categories. Once you “enter category of products” (ex. category1), then it will ask to you to enter the price for product 1-3 within the same category. The program will not allow you to input more than 3 products in any category. The output will be the average price for all 3 products within the category. The program will continue to loop at this point and will begin back at “enter category of products.”
Pseudocode:
// This program will calculate the average prices of 3 products in 3 categories
// Declare variables
Declare categoryName as String
Declare productValue, sum, avg as Float
// Loop through 3 categories
While (categories < 3)
// reset sum to 0
Set Sum =0.0
Print “Enter category of products”
Input categoryName
//Nested Loop
//reset products
Set product = 0
While (products < 3)
Print “Enter price for “ +(products+1)+“ product in this category: ”
Input productValue
Set Sum = Sum + productValue
End While
Set avg = Sum/3.0
Print “Average price for “ + categoryName + “ is “ + avg
End While
C Code:
Program: This program will calculate the average prices of 3 products in 3 categories
#include <stdio.h>
int main() {
/* variable definition: */
char categoryName[100];
float productValue, sum, avg;
int categories = 0, products = 0;
// Loop through 3 categories
while (categories < 3) {
// reset Sum to 0
sum = 0.0;
printf("Enter category of products \n");
scanf("%s", categoryName);
products = 0;
// Nested Loop for products
while (products < 3) {
printf ("Enter price for %d product in this category: \n", products+1);
scanf("%f", &productValue);
sum += productValue;
++products;
}
++categories;
avg = sum/3.0;
printf( "Average price for %s is %f\n",categoryName,avg);
}
return 0;
}
Flowchart:
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//Psuedocode
declare long ints: term1, term2, sum, evenSum
set term1 and term2 = 1
while term1 <= 4000000
sum = term1 + term2
term1 = term2
term2 = sum
if term1%2 == 0
add term1 to evenSum
/*
* File: main.c
* Author: JaiEllRei
*
* Created on October 29, 2015, 9:03 PM
*/
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char** argv) {
// Terms within Fib Seq get large very quickly
long term1=1;
long term2=1;
long sum=0;
long sumEven=0;
printf("This program will display only the even terms of the\nFibonacci Sequence, that are less than 4000000, \nthen provide the sum of those terms.");
printf("\nPress enter to continue...");
getchar();
// Begin LOOP
while(term2<4000000){
sum = term1 + term2;
term1 = term2;
term2 = sum;
if( term1%2 == 0) // An even number has no remainder; add it to sumEven
printf("%li\n", term1);
sumEven = sumEven + term1;
}
printf("\nThe sum of the Even Terms equals %li", sumEven);
return (EXIT_SUCCESS);
}
::::OUTPUT::::
This program will display only the even terms of the
Fibonacci Sequence, that are less than 4000000,
then provide the sum of those terms.
Press enter to continue...
2
8
34
144
610
2584
10946
46368
196418
832040
3524578
The sum of the Even Terms equals 9227463
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