Math mcqs...Correct answer pls

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Online MATH 275 Homework 01 Due : 9/2/2015

Please show all steps and submit scanned copy of your work on Blackboard by 9/2 before 11:59 pm.

1. The order of the differential equation d2y

dx2 + 4x

dy

dx + y cos x =

d3(e2x)

dx3 is:

(a) 1

(b) 2

(c) 3

(d) 4

(e) None of the above.

2. The order of the differential equation ∂2u

∂x2 +

∂3u

∂x2∂y + ∂u

∂y = xyu4 is:

(a) 1

(b) 2

(c) 3

(d) 4

(e) None of the above.

3. The set of all solutions of y′ − 6x = 4e2x is:

(a) y = 3x2 + 2e2x + C

(b) y = 3x2 + 2e2x

(c) y = 3x2 + 2e2x + Cx

(d) y = 2e2x − 3x2 + C (e) None of the above.

4. The set of all solutions of dy

dx = 3y is:

(a) y = e3x

(b) y = Ce−3x

(c) y = e3x + C

(d) y = Ce3x

(e) None of the above.

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5. The set of all solutions of y′′ = 12x2 − 4 cos 2x + 6 is:

(a) y = x4 − cos 2x + 6x + Cx (b) y = x4 + sin 2x + 3x2 + C

(c) y = x4 + cos 2x + 3x2 + C1x + C2

(d) y = x4 − sin 2x + 6x2 + C1x2 + C2x (e) None of the above.

6. The value(s) of λ such that y = eλx is a solution of

y′′ − 5y′ + 6y = 0

are:

(a) λ = 5

(b) λ = 3, λ = 2

(c) λ = −1, λ = 5 (d) λ = −3, λ = −2 (e) None of the above.

7. The value(s) of λ such that y = eλx is a solution of

d2y

dx2 + 8

dy

dx + 16y = 0

are:

(a) λ = 4, λ = −4 (b) λ = 4

(c) λ = −4 (d) λ = −8, λ = −2 (e) None of the above.

8. The differential equation which has y2 = Cx3 − 2 as its general solution is:

(a) y′ = 3y2 + 6

2xy

(b) y′ = y2 + 2

2x

(c) y′′ = 2yy′

3x2

(d) x2y′′ − 2xy′ + 2y = 0 (e) None of the above.

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9. The differential equation which has y = C1e x + C2e

3x as its general solution is:

(a) y′ − 3y = 0 (b) y′′ − 2y′ − 3y = 0 (c) x2y′′ − 3xy′ + 3y = 0 (d) y′′ − 4y′ + 3y = 0 (e) None of the above.

10. The differential equation which has y = C1x + C2x 3 as its general solution is:

(a) y′ − 3x2y = 0 (b) x2y′′ − 3xy′ + 3y = 0 (c) x2y′′ − 4xy′ + 6y = 0 (d) y′′ − 4y′ + 3y = 0 (e) None of the above.

11. The value(s) of r such that y = xr is a solution of

d2y

dx2 −

1

x

dy

dx −

8

x2 y = 0

are

(a) r = −2 (b) r = −4, r = 2 (c) r = 4, r = −2 (d) r = 4

(e) None of the above.

12. The value(s) of r such that y = xr is a solution of

x2y′′ − 3xy′ + 5y = 0

are

(a) r = 5

(b) r = −2, r = 5 (c) r = −5, r = 1 (d) r = −2, r = 2 (e) None of the above.

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