c++
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Chapter 3 Selections
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Motivations
If you assigned a negative value for radius in Listing 2.1, ComputeArea.cpp, the program would print an invalid result. If the radius is negative, you don't want the program to compute the area. How can you deal with this situation?
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Objectives
- To declare bool variables and write Boolean expressions using relational operators (§3.2).
- To implement selection control using one-way if statements (§3.3).
- To program using one-way if statements (GuessBirthday) (§3.4).
- To implement selection control using two-way if statements (§3.5).
- To implement selection control using nested if and multi-way if-else statements (§3.6).
- To avoid common errors and pitfalls in if statements (§3.7).
- To program using selection statements for a variety of examples (BMI, ComputeTax, SubtractionQuiz) (§§3.8–3.10).
- To generate random numbers using the rand function and set a seed using the srand function (§3.9).
- To combine conditions using logical operators (&&, ||, and !) (§3.10).
- To program using selection statements with combined conditions (LeapYear, Lottery) (§§3.11–3.12).
- To implement selection control using switch statements (§3.13).
- To write expressions using the conditional operator (§3.14).
- To examine the rules governing operator precedence and operator associativity (§3.15).
- To debug errors (§3.16).
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The bool Type and Operators
Often in a program you need to compare two values, such as whether i is greater than j. C++ provides six relational operators (also known as comparison operators) in Table 3.1 that can be used to compare two values.
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Relational Operators
Operator Name Example Result
< less than 1 < 2 true
<= less than or equal to 1 <= 2 true
> greater than 1 > 2 false
>= greater than or equal to 1 >= 2 false == equal to 1 == 2 false
!= not equal to 1 != 2 true
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One-way if Statements
if (booleanExpression)
{
statement(s);
}
if (radius >= 0)
{
area = radius * radius * PI;
cout << "The area for the circle of " <<
" radius " << radius << " is " << area;
}
Boolean
Expression
true
Statement(s)
false
false
area = radius * radius * PI;
cout << "The area for the circle of " <<
" radius " << radius << " is " << area;
true
(radius >= 0)
(a)
(b)
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Note
(a)
if ((i > 0) && (i < 10))
{
cout << "i is an " <<
"integer between 0 and 10";
}
if ((i > 0) && (i < 10))
cout << "i is an " <<
"integer between 0 and 10";
Equivalent
Braces can be omitted if the block contains a single statement
(b)
Outer parentheses required
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Examples
Listing 3.1 gives a program that checks whether a number is even or odd. The program prompts the user to enter an integer (line 9) and displays “number is even” if it is even (lines 11-12) and “number is odd” if it is odd (lines 14-15).
TestBoolean
Run
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Caution
Adding a semicolon at the end of an if clause is a common mistake.
This mistake is hard to find, because it is not a compilation error or a runtime error, it is a logic error.
This error often occurs when you use the next-line block style.
(a)
if (radius >= 0);
{
area = radius * radius * PI;
cout << "The area "
<< " is " << area;
}
if (radius >= 0) { };
{
area = radius * radius * PI;
cout << "The area "
<< " is " << area;
}
Equivalent
Empty Body
(b)
Logic Error
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Lab #1 – Hand In
C++ Program
Write a program that accepts as input first one integer into a variable named intValue1.
Next input a character into a variable named chrValue1.
If the intValue1 is even, then output to the screen “Integer is even”.
If the chrValue1 is greater than ‘G’, then output to the screen “Character is greater than G”.
Make sure you contain at least 2 comments
Variables are named correctly
The use of the if statement is done twice
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The if...else Statement
if (booleanExpression)
{
statement(s)-for-the-true-case;
}
else
{
statement(s)-for-the-false-case;
}
false
Boolean
Expression
Statement(s) for the true case
true
Statement(s) for the false case
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Nested if Statements
if (i > k)
{
if (j > k)
cout << "i and j are greater than k";
}
else
cout << "i is less than or equal to k";
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Multiple Alternative if Statements
(a)
if (score >= 90.0)
cout << "Grade is A";
else
if (score >= 80.0)
cout << "Grade is B";
else
if (score >= 70.0)
cout << "Grade is C";
else
if (score >= 60.0)
cout << "Grade is D";
else
cout << "Grade is F";
(b)
Equivalent
This is better
if (score >= 90.0)
cout << "Grade is A";
else if (score >= 80.0)
cout << "Grade is B";
else if (score >= 70.0)
cout << "Grade is C";
else if (score >= 60.0)
cout << "Grade is D";
else
cout << "Grade is F";
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Trace if-else statement
if (score >= 90.0)
cout << “Grade is A";
else if (score >= 80.0)
cout << “Grade is B";
else if (score >= 70.0)
cout << “Grade is C";
else if (score >= 60.0)
cout << “Grade is D";
else
cout << “Grade is F";
Suppose score is 70.0
The condition is false
animation
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Trace if-else statement
if (score >= 90.0)
cout << “Grade is A";
else if (score >= 80.0)
cout << “Grade is B";
else if (score >= 70.0)
cout << “Grade is C";
else if (score >= 60.0)
cout << “Grade is D";
else
cout << “Grade is F";
Suppose score is 70.0
The condition is false
animation
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Trace if-else statement
if (score >= 90.0)
cout << “Grade is A";
else if (score >= 80.0)
cout << “Grade is B";
else if (score >= 70.0)
cout << “Grade is C";
else if (score >= 60.0)
cout << “Grade is D";
else
cout << “Grade is F";
Suppose score is 70.0
The condition is true
animation
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Trace if-else statement
if (score >= 90.0)
cout << “Grade is A";
else if (score >= 80.0)
cout << “Grade is B";
else if (score >= 70.0)
cout << “Grade is C";
else if (score >= 60.0)
cout << “Grade is D";
else
cout << “Grade is F";
Suppose score is 70.0
grade is C
animation
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Trace if-else statement
if (score >= 90.0)
cout << “Grade is A";
else if (score >= 80.0)
cout << “Grade is B";
else if (score >= 70.0)
cout << “Grade is C";
else if (score >= 60.0)
cout << “Grade is D";
else
cout << “Grade is F";
Suppose score is 70.0
Exit the if statement
animation
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Note
The else clause matches the most recent if clause in the same block.
(a)
int i = 1;
int j = 2;
int k = 3;
if (i > j)
if (i > k)
cout << "A";
else
cout << "B";
(b)
Equivalent
int i = 1;
int j = 2;
int k = 3;
if (i > j)
if (i > k)
cout << "A";
else
cout << "B";
This is better with correct indentation
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Note, cont.
Nothing is printed from the preceding statement. To force the else clause to match the first if clause, you must add a pair of braces:
int i = 1; int j = 2; int k = 3;
if (i > j)
{
if (i > k)
cout << "A";
}
else
cout << "B";
This statement prints B.
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TIP
(a)
if (number % 2 == 0)
even = true;
else
even = false;
(b)
Equivalent
This is better
bool even
= number % 2 == 0;
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CAUTION
(a)
if (even == true)
cout <<"It is even.";
(b)
Equivalent
if (even)
cout << "It is even.";
This is better
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Common Errors in Selection Statements
Common Error 1: Forgetting Necessary Braces
(a) Wrong
if (radius >= 0)
area = radius * radius * PI;
cout << "The area "
<< " is " << area;
if (radius >= 0)
{
area = radius * radius * PI;
cout << "The area "
<< " is " << area;
}
(b) Correct
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Common Errors in Selection Statements
Common Error 2: Wrong Semicolon at the if Line
(a)
if (radius >= 0);
{
area = radius * radius * PI;
cout << "The area "
<< " is " << area;
}
if (radius >= 0) { };
{
area = radius * radius * PI;
cout << "The area "
<< " is " << area;
}
Equivalent
Empty Body
(b)
Logic Error
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Common Errors in Selection Statements
Common Error 3: Mistakenly Using = for ==
if (count = 1)
cout << "count is zero" << endl;
else
cout << "count is not zero" << endl;
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Common Errors in Selection Statements
Common Error 4: Redundant Testing of Boolean Values
(a)
if (even == true)
cout <<"It is even.";
(b)
Equivalent
if (even)
cout << "It is even.";
This is better
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Problem: Body Mass Index
Body Mass Index (BMI) is a measure of health on weight. It can be calculated by taking your weight in kilograms and dividing by the square of your height in meters. The interpretation of BMI for people 16 years or older is as follows:
ComputeBMI
BMI Interpretation
below 16 serious underweight
underweight
normal weight
overweight
29-35 seriously overweight
above 35 gravely overweight
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Example: Computing Taxes
The US federal personal income tax is calculated based on the filing status and taxable income. There are four filing statuses: single filers, married filing jointly, married filing separately, and head of household. The tax rates for 2002 are shown in Table 3.6.
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Example: Computing Taxes, cont.
ComputeTax
if (status == 0)
{
// Compute tax for single filers
}
else if (status == 1)
{
// Compute tax for married file jointly
}
else if (status == 2)
{
// Compute tax for married file separately
}
else if (status == 3)
{
// Compute tax for head of household
}
else
{
// Display wrong status
}
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Example: A Simple Math Learning Tool
SubtractionQuiz
Run
This example creates a program for a first grader to practice subtractions. The program randomly generates two single-digit integers number1 and number2 with number1 >= number2 and displays a question such as “What is 9 – 2?” to the student, as shown in the sample output. After the student types the answer, the program displays a message to indicate whether the answer is correct.
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C++ Programming: From Problem Analysis to Program Design, Fourth Edition
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Lab #2 – Hand In
C++ Program
Write a program that accepts as input first one integer into a variable named intValue1.
Accept a second integer from input into a variable named intValue2.
If the intValue1 is even, then output to the screen “Value 1 is even”, otherwise say “Value 1 is odd”.
If the intValue2 is even, then output to the screen “Value 2 is even”, otherwise say “Value 2 is odd”.
If intValue2 is greater than intValue1, than output to the screen “Value2 is greater than Value1” and then also output another line saying “If part is true”, otherwise output to the screen “Value1 is greater than Value2” and then also output another line saying “else part is true”.
Make sure you contain at least 2 comments
Variables are named correctly
The use of the if-else statement is used 3 times.
C++ Programming: From Problem Analysis to Program Design, Fourth Edition
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Logical Operators
Operator Name Description
! not logical negation
&& and logical conjunction
|| or logical disjunction
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Truth Table for Operator !
p !p
true false
false true
Example (assume age = 24, weight = 140)
!(age > 18) is false, because (age > 18) is true.
!( weight == 150) is true, because (weight == 150) is false.
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Truth Table for Operator &&
Example (assume age = 24, weight = 140)
(age > 28) && (weight < 140) is false, because (age > 28) and (weight < 140) are both false.
(age > 18) && (weight >= 140) is true, because both (age > 18) and (weight >= 140) are true.
p1 p2 p1 && p2
false false false
false true false
true false false
true true true
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Truth Table for Operator ||
Example (assume age = 24, weight = 140)
(age > 34) || (weight < 140) is false, because both (age > 34) and (weight < 140) are false.
(age > 18) || (weight >= 150) is false, because (age > 18) is true.
p1 p2 p1 || p2
false false false
false true true
true false true
true true true
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Examples
Listing 3.3 gives a program that checks whether a number is divisible by 2 and 3, whether a number is divisible by 2 or 3, and whether a number is divisible by 2 or 3 but not both:
TestBooleanOperators
Run
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Short-Circuit Operator
When evaluating p1 && p2, C++ first evaluates p1 and then evaluates p2 if p1 is true; if p1 is false, it does not evaluate p2. When evaluating p1 || p2, C++ first evaluates p1 and then evaluates p2 if p1 is false; if p1 is true, it does not evaluate p2. Therefore, && is referred to as the conditional or short-circuit AND operator, and || is referred to as the conditional or short-circuit OR operator.
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Examples
Write a program that lets the user enter a year and checks whether it is a leap year.
A year is a leap year if it is divisible by 4 but not by 100 or if it is divisible by 400. So you can use the following Boolean expression to check whether a year is a leap year:
(year % 4 == 0 && year % 100 != 0) || (year % 400 == 0)
LeapYear
Run
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Problem: Lottery
Randomly generates a lottery of a two-digit number, prompts the user to enter a two-digit number, and determines whether the user wins according to the following rule:
Lottery
- If the user input matches the lottery in exact order, the award is $10,000.
- If the user input matches the lottery, the award is $3,000.
- If one digit in the user input matches a digit in the lottery, the award is $1,000.
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C++ Programming: From Problem Analysis to Program Design, Fourth Edition
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Lab #3 – Hand In
C++ Program
Write a program that accepts as input first one integer into a variable named intValue1.
Accept a second integer from input into a variable named intValue2.
If the intValue1 is even, then output to the screen “Value 1 is even”.
If intValue1 is not even, then test to see if the intValue2 is even, then output to the screen “Value 2 is even”, otherwise say “Both values is odd”.
Make sure you contain at least 2 comments
Variables are named correctly
The use of the if-else statement is used 3 times.
C++ Programming: From Problem Analysis to Program Design, Fourth Edition
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switch Statements
switch (status)
{
case 0: compute taxes for single filers;
break;
case 1: compute taxes for married file jointly;
break;
case 2: compute taxes for married file separately;
break;
case 3: compute taxes for head of household;
break;
default: cout << "Errors: invalid status“ << endl;
}
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switch Statement Flow Chart
status is 0
Compute tax for single filers
break
Compute tax for married file separately
break
Compute tax for married file jointly
status is 1
status is 2
break
Compute tax for married file separatly
status is 3
break
Compute tax for head of household
default
Next Statement
Default actions
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switch Statement Rules
switch (switch-expression) {
case value1: statement(s)1;
break;
case value2: statement(s)2;
break;
…
case valueN: statement(s)N;
break;
default: statement(s)-for-default;
}
The switch-expression must yield a value of char, byte, short, or int type and must always be enclosed in parentheses.
The value1, ..., and valueN must have the same data type as the value of the switch-expression. The resulting statements in the case statement are executed when the value in the case statement matches the value of the switch-expression. Note that value1, ..., and valueN are constant expressions, meaning that they cannot contain variables in the expression, such as 1 + x.
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switch Statement Rules
The keyword break is optional, but it should be used at the end of each case in order to terminate the remainder of the switch statement. If the break statement is not present, the next case statement will be executed.
switch (switch-expression) {
case value1: statement(s)1;
break;
case value2: statement(s)2;
break;
…
case valueN: statement(s)N;
break;
default: statement(s)-for-default;
}
When the value in a case statement matches the value of the switch-expression, the statements starting from this case are executed until either a break statement or the end of the switch statement is reached.
The default case, which is optional, can be used to perform actions when none of the specified cases matches the switch-expression.
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Trace switch statement
switch (day)
{
case 1: // Fall to through to the next case
case 2: // Fall to through to the next case
case 3: // Fall to through to the next case
case 4: // Fall to through to the next case
case 5: cout << "Weekday"; break;
case 0: // Fall to through to the next case
case 6: cout << "Weekend";
}
Suppose day is 3:
animation
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Trace switch statement
switch (day)
{
case 1: // Fall to through to the next case
case 2: // Fall to through to the next case
case 3: // Fall to through to the next case
case 4: // Fall to through to the next case
case 5: cout << "Weekday"; break;
case 0: // Fall to through to the next case
case 6: cout << "Weekend";
}
Suppose day is 3:
animation
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Trace switch statement
switch (day)
{
case 1: // Fall to through to the next case
case 2: // Fall to through to the next case
case 3: // Fall to through to the next case
case 4: // Fall to through to the next case
case 5: cout << "Weekday"; break;
case 0: // Fall to through to the next case
case 6: cout << "Weekend";
}
Suppose day is 3:
animation
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Trace switch statement
switch (day)
{
case 1: // Fall to through to the next case
case 2: // Fall to through to the next case
case 3: // Fall to through to the next case
case 4: // Fall to through to the next case
case 5: cout << "Weekday"; break;
case 0: // Fall to through to the next case
case 6: cout << "Weekend";
}
Suppose day is 3:
animation
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Trace switch statement
switch (day)
{
case 1: // Fall to through to the next case
case 2: // Fall to through to the next case
case 3: // Fall to through to the next case
case 4: // Fall to through to the next case
case 5: cout << "Weekday"; break;
case 0: // Fall to through to the next case
case 6: cout << "Weekend";
}
Suppose day is 3:
animation
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Problem: Chinese Zodiac
Write a program that prompts the user to enter a year and displays the animal for the year.
ChineseZodiac
rabbit
tiger
ox
rat
dragon
snake
horse
sheep
monkey
rooster
dog
pig
0: monkey
1: rooster
2: dog
3: pig
4: rat
5: ox
6: tiger
7: rabbit
8: dragon
9: snake
10: horse
11: sheep
year % 12 =
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Conditional Operator
if (x > 0)
y = 1
else
y = -1;
is equivalent to
y = (x > 0) ? 1 : -1;
(booleanExpression) ? expression1 : expression2
Ternary operator
Binary operator
Unary operator
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Conditional Operator
cout << ((num % 2 == 0) ? "num is even" : "num is odd");
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Conditional Operator, cont.
(booleanExp) ? exp1 : exp2
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C++ Programming: From Problem Analysis to Program Design, Fourth Edition
*
Lab #4 – Hand In
C++ Program
Write a program that accepts as input a character variable called chrValue1.
If chrValue1 is ‘G’ or ‘g’ then write out to the screen “You entered a g”, if chrValue1 is ‘T’ or ‘t’ then write out to the screen “You entered a t”, if chrValue1 is ‘P’ or ‘p’ then write out to the screen “You entered a p”, otherwise output “You tricked me”.
Make sure you contain at least 3 comments
Variables are named correctly
Make sure that you use the switch statement and do not use any if statements.
C++ Programming: From Problem Analysis to Program Design, Fourth Edition
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Operator Precedence
How to evaluate 3 + 4 * 4 > 5 * (4 + 3) – 1?
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Operator Precedence
- var++, var--
- +, - (Unary plus and minus), ++var,--var
- (type) Casting
- ! (Not)
- *, /, % (Multiplication, division, and remainder)
- +, - (Binary addition and subtraction)
- <, <=, >, >= (Comparison)
- ==, !=; (Equality)
- && (Conditional AND) Short-circuit AND
- || (Conditional OR) Short-circuit OR
- =, +=, -=, *=, /=, %= (Assignment operator)
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Enumerated Types
enum Day {MONDAY, TUESDAY, WEDNESDAY, THURSDAY, FRIDAY};
Once a type is defined, you can declare a variable of that type:
Day day;
The variable day can hold one of the values defined in the enumerated type. For example, the following statement assigns enumerated value MONDAY to variable day:
day = MONDAY;
Companion Website
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Enumerated Types
As with any other type, you can declare and initialize a variable in one statement:
Day day = MONDAY;
Furthermore, C++ allows you to declare an enumerated type and variable in one statement. For example,
enum Day {MONDAY, TUESDAY, WEDNESDAY, THURSDAY, FRIDAY} day = MONDAY;
Run
Companion Website
Operator Name Example Result
< less than 1 < 2 true
<= less than or equal to 1 <= 2 true
> greater than 1 > 2 false
>= greater than or equal to 1 >= 2 false
== equal to 1 == 2 false
!= not equal to 1 != 2 true
Boolean
Expression
true
Statement(s)
false
(radius >= 0)
true
area = radius * radius * PI;
cout <<
"The area for the circle of "
<<
" radius "
<<
radius
<<
" is "
<< area
;
false
(
a
)
(
b
)
if
(
(i >
0
) && (i <
10
)
)
{
cout <<
"i is an "
<<
"integer between 0 and 10"
;
}
(
a)
Equivalent
(b)
if
(
(i >
0
) && (i <
10
)
)
cout <<
"i is an "
<<
"integer between 0 and 10"
;
Outer parentheses required
Braces can be omitted if the block contains a single
statement
if
(radius >=
0
)
;
{
area = radius * radius * PI;
cout <<
"The area "
<<
" is "
<<
area;
}
(a
)
Equivalent
Logic Error
if
(radius >=
0
)
{ }
;
{
area = radius * radius * PI;
cout <<
"The area "
<<
" is "
<<
area;
}
(b)
Empty Body
Boolean
Expression
false
true
Statement(s) for the false case
Statement(s) for the true case
if
(score >=
90.0
)
cout <<
"Grade is
A
"
;
else
if
(score >=
80.0
)
cout <<
"Grade is
B"
;
else
if
(score >=
70.0
)
cout <<
"Grade is
C"
;
else
if
(score >=
60.0
)
cout <<
"Grade is
D"
;
else
cout
<<
"Grade is
F"
;
(a
)
Equivalent
if
(score >=
90.0
)
cout <<
"Grade is
A
"
;
else if
(score >=
80.0
)
cout <<
"Grade is
B"
;
else if
(score >=
70.0
)
cout <<
"Grade is
C"
;
else if
(score >=
60.0
)
cout <<
"Grade is
D"
;
else
cou
t <<
"Grade is
F"
;
(b
)
This is better
int
i =
1
;
int
j =
2
;
int
k =
3
;
if
(i > j)
if
(i > k)
cout <<
"A"
;
else
cout <<
"B"
;
(a
)
Equivalent
(
b
)
int
i =
1
;
int
j =
2
;
int
k =
3
;
if
(i > j)
if
(i > k)
cout <<
"A"
;
else
cout <<
"B"
;
This i
s better
with correct
indentation
if
(number %
2
==
0
)
even =
true
;
else
even =
false
;
(a
)
Equivalent
bool
even
= number %
2
==
0
;
(
b
)
This is better
if
(even ==
true
)
cout <<
"It is even."
;
(
a
)
Equivalent
if
(even)
cout <<
"It is even."
;
(b)
This is better
if
(radius >=
0
)
area = radius * radius * PI;
cout <<
"The area "
<<
" is "
<<
area;
(a
)
Wrong
if
(radius >=
0
)
{
area = radius * radius * PI;
cout <<
"The area "
<<
" is "
<<
area;
}
(b)
Correct
Run
BMI
Interpretation
below 16
serious underweight
16
-
18
underweight
18
-
24
normal weight
24
-
29
o
verweight
29
-
3
5
seriously overweight
above 35
gravely overweight
Operator Name Description
! not logical negation
&& and logical conjunction
|| or logical disjunction
p !p
true false
false true
Example
(
assume
age = 24,
weight = 140
)
!(
age > 18
)
is
false
, because
(
age
>
18
)
is
true
.
!(
weight =
=
150
)
is
true
, because
(
weight
=
= 150
)
is
false
.
p1 p2 p1 && p2
false false false
false true false
true false false
true true true
Example
(assume age = 24,
weight = 140
)
(
age
>
2
8
) && (
weight <
140
)
is
false
, because
(age
>
2
8)
and
(
weight <
140
)
are bo
th
false
.
(age > 18) && (
weight >
=
140
)
is
true
, because
both (age > 18) and
(
weight >
=
140
)
are true
.
p1 p2 p1 || p2
false false false
false true true
true false true
true true true
Example (assume age = 24,
weight = 140
)
(age > 34) || (
weight <
140
)
is
false
, because
both
(age
> 34) and
(
weight <
140
)
are false
.
(age >
18
) ||
(
weight >= 1
5
0
)
is
false
, because
(age >
18
)
is true
.
status is 0
Compute tax for single filers
break
Compute tax for married file jointly
break
status is 1
Compute tax for married file separatly
break
status is 2
Compute tax for head of household
break
st
atus is 3
Default actions
default
Next Statement
rat
ox
tiger
rabbit
dragon
snake
horse
sheep
monkey
rooster
dog
pig
0: monkey
1: rooster
2
: dog
3
: pig
4
: rat
5
: ox
6
: tiger
7
: rabbit
8
: dragon
9
: snake
10
: horse
11: sheep
year % 12
=