Calculas homework

extra_credit.pdf

Extra Credit……….. (counts as quiz grade) – Due Friday

Problem: Find the absolute maximum value of  210 xy on the interval 200  x

What is wrong with the following solution? How do you know that it is wrong? Correct what is wrong

and arrive at the correct solution.

102

1)10(2





x dx

Setting derivative equal to 0 and solving for x gives

0102 x

5x

When 25)5()105(,5 22  yx

So the absolute maximum value of  210 xy on the interval 200  x is 25. This maximum values occurs when x = 5.