Only expert needed
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Equations for Black Oil Properties from Flash, Differential and Separator Data |
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At bubble point (pb) |
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Let Bob = BoSb and Rsb = RsSb , taking the Separator Test values to be correct at the bubble point. |
Bob = BoSb Rsb = RsSb |
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Above bubble point (pb) |
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Use Flash Expansion Data (Vt/Vb)f and BoSb to obtain Bo above pb. |
Bo = BoSb(Vt/Vb)f Rs = RsSb = constant |
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Bo below bubble point (pb) |
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Use Differential Expansion Data (Bod/Bodb) and BoSb to obtain Bo below pb. |
Bo = BoSb(Bod/Bodb) |
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Rs below bubble point (pb) |
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Where, RsSb = total gas in solution at bubble point (pb), Rs = (Rsdb – Rsd) = solution gas liberated while dropping pressure from pb to p in a differential test (this will be different than if done as a flash or separator test) (BoSb/Bodb) is used to correct the differential-test-obtained Rs to what would have been obtained from a separator test for oil at pressure p. |
Rs = RsSb – (Rsdb – Rsd)(Bosb/Bodb) |
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Oil Compressibility Equations |
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In terms of ordinary derivative [Eqn (1)] |
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Obtaining co from Flash Expansion Test data………[Eqn (2)] |
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Integrated form of Eqn (2) [Eqn (3)] |
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Integrated form of Eqn (3) [Eqn (4)] |
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Test Data
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Flash Data (p ≥ pb ) |
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Differential Data (p ≤ pb ) |
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Separator Test Data |
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p |
(Vt/Vb)f |
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p |
Bod = (Vo/VResid)d |
Rsd |
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(Separator p = 200 psig) |
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5000 |
0.9639 |
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pb = 2620 |
Bodb = 1.600 |
854.0 |
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BoSb = 1.474 RVB/STB |
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4500 |
0.9703 |
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2350 |
1.554 |
763.0 |
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RsSb = 768 SCF/STB |
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4000 |
0.9771 |
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2100 |
1.515 |
684.0 |
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3500 |
0.9846 |
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1850 |
1.479 |
612.0 |
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3000 |
0.9929 |
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1600 |
1.445 |
544.0 |
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2900 |
0.9946 |
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1350 |
1.412 |
479.0 |
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2800 |
0.9964 |
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1100 |
1.382 |
416.0 |
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2700 |
0.9983 |
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850 |
1.351 |
354.0 |
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pb = 2620 |
1.000 |
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600 |
1.320 |
292.0 |
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350 |
1.283 |
223.0 |
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159 |
1.244 |
157.0 |
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0 |
1.075 |
0.0 |
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0 |
1.000 |
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In class problems:
1. At p = 2800 psig, determine: Bo, Rs.
2. At p = pb = 2620 psig, determine: Bob, Rsb.
3. At p = 1850 psig, determine: Bo, Rs.
Homework problems:
4. At p = 4500 psig, determine: Bo, Rs.
5. At p = pb = 2620 psig, determine: Bob, Rsb.
6. At p = 23500 psig, determine: Bo, Rs.
7. Determine the oil compressibility (co) between the bubble point pressure (pb = 2620) and p = 3500 psi.
Answers: 1. Bo = 1.4687 RVB/STB; Rs = 768 SCF/STB. 2,5. Bo = 1.474 RVB/STB; Rs = 768 SCF/STB.
3. Bo = 1.3625 RVB/STB; Rs = 545 SCF/STB. 4. Bo = 1.4302 RVB/STB; Rs = 768 SCF/STB.
6. Bo = 1.4316 RVB/STB; Rs = 684.17 SCF/STB 7. 0.0000176 1/psi
A. Informational Questions on Black Oil, Correlations and the Regression Process
1. What is a correlation? Give one example for gas and two for oil.
2. Regression is a process that involves several steps: (a) Determine which variables are significant; (b) Determine a functional form; (b) Determine constants for that function to minimize error.
For black oil correlations, which three quantities appear in all correlations as the basic three variables?
Give three example functional forms:
3. Explain a “black oil” model for reservoir fluid properties. How is it a simplification of the “true” or “actual” fluid properties?
4. What is the best source of fluid data for a given field? Give two ways to sample a reservoir fluid.
5. When must you use fluid correlations?
6. How do you choose an oil correlation? (Give three considerations.)
7. Which pressure is the most important point at which to determine a fluid’s properties? How is this value found in a lab PVT cell?
8. If you or your company prefers to use a particular fluid correlation but it is slightly off on known bubble point fluid properties for a particular reservoir, can you still use this correlation? How? What must you be careful about?
B. Basic Black Oil Calculations using Standing and Vasquez/Beggs Correlations (See correlation equations in the accompanying handout)
Use this basic data for all calculations:
Basic three input variables:
Gas Gravity g = 0.86
Oil Gravity o = 0.94 = 19.03 °API (check this!)
Reservoir Temperature, TR = 150 °F
Additional input variables (depends on case):
Pressure, p = pb = 5200 psi
Solution Gas Oil Ratio, Rs = 940 SCF/STB
8. If Rsb = 940 SCF/STB, determine the bubble point pressure of this oil system, using:
(a) Standing [Answer = 4769.2 psi ];
(b) Vasquez and Beggs [Answer = 5990.3 psi ]
9. If pb = 5200 psi, determine the solution GOR (Rs) of this oil system, using:
(a) Standing [Answer = 1043.8 SCF/STB ];
(b) Vasquez and Beggs [Answer = 805.4 SCF/STB ]
10. If pb = 5200 psi and Rsb = 940 SCF/STB, determine the oil FVF (Bob) of this oil system, using:
(a) Standing [Answer = 1.515 RVB/STB ];
(b) Vasquez and Beggs [Answer = 1.441 RVB/STB]
11. If pb = 5200 psi and Rsb = 940 SCF/STB, determine the oil compressibility (co) of this oil system at pb, using Vasquez and Beggs. [Answer: co = 9.754∙10-6 1/psi]
12. If pb = 5200 psi and Bob = 1.515 RVB/STB, determine the oil FVF (Bo) of this oil system at p = 6000 psi. (Use the co from problem 11). [Answer: Bo = 1.5032 RVB/STB]
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Oil Compressibility Equations |
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In terms of ordinary derivative (understanding that T = const) [Eqn (2)] |
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In terms of V and p….(this is a(n) (useful) approximation) [Eqn (3)] |
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Integrated form of Eqn (2) [Eqn (4)] |
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Integrated form of Eqn (3) [Eqn (5)] |
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Expansion (V) of fluid of volume V which has undergone an average p (over the entire volume V) (rearranged Eqn (3)) [Eqn (6)] |
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Oil Compressibility Equations |
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(Thermodynamic) Definition of Isothermal Compressibility [Eqn (1)] (units are 1/pressure; for petroleum engineers, usually 1/psi) |
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In terms of ordinary derivative (understanding that T = const) [Eqn (2)] |
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In terms of V and p….(this is a(n) (useful) approximation) [Eqn (3)] |
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Integrated form of Eqn (2) [Eqn (4)] |
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Integrated form of Eqn (3) [Eqn (5)] |
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Expansion (V) of fluid of volume V which has undergone an average p (over the entire volume V) (rearranged Eqn (3)) [Eqn (6)] |
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Series representation of ex….. |
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1. Draw a p-V diagram for a pure component with one isotherm. Label the liquid, two-phase, and vapor regions. Explain how the concept of compressibility (both for liquid and vapor) is represented in that picture.
2. Give four examples of volume changes that occur in an oil/free gas/water reservoir as pressure drops.
3. Draw a Bo vs. p curve. Explain which part of the curve illustrates isothermal compressibility. What is the slope of this part of the curve? What feature on this picture illustrates thermal expansion (volume change due to temperature change)?
4. At bubble point pressure pBP = 4450 psi, B0BP = 1.5 RVB/STB, and co = 8.8·10-6 psi-1. Find Bo at p = 5000 psi using (a) Eqn. (4) and (b) Eqn. (5). (c) Draw the Bo vs. p curve for this oil. [ Bo = 1.49 RVB/STB ]
5. Equations (4) and (5) look different but give essentially the same answer. Why?
6. Is co constant for an oil above its bubble point?
7. An oil reservoir (with a fluid filled pore volume of 85 million bbls) is discovered at an initial average pressure pi = 6000 psi. Fluid tests indicate that the oil has a bubble point of 4860 psi. The averaged compressibility of both the connate water and the oil present is c = 8.8·10-6 psi-1. Assume the rock and formation pore volume remains constant. As oil is produced from the reservoir, assume that pressure changes occur instantly over the entire reservoir. (Not true, since pressures will be lower near wells.) When the average pressure in this reservoir has dropped to the bubble point (4860 psi), how many RVB of oil have been removed from the reservoir? If Bo = 1.30 RVB/STB and Rs = 800SCF/STB for this oil, how many STB of oil have been removed? How many MCF of gas has been produced at the surface? (Hint: Use Eqn. (6)) [ RVB produced = 852.7·103 RVB oil; Np = 655.9·103 STB; Gp = 524.75 MMCF gas ]
1. Define the following: (a) Dead Oil; (b) Live Oil
2. Sketch a graph of o vs. p. Why does o increase above the bubble point?
3. For a 32 °API oil at TR = 160° F, with Rs = 800 SCF/STB, please determine: (a) od; (b) o .Perform the calculations on another page (show your work), and write answers in the chart below: Check your calculations with the Excel viscosity project I sent you. Do not just write in numbers below from the Excel project.
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Method |
od |
o |
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1. Beal (Chart) |
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2. Beal (Equations) |
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Use this Beal Eqns. od for the live oil calc’s below. |
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3. Egbogah and Ng (Equations) |
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4. Beggs and Robinson ((Equations) |
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5. Chew and Connally (Graph) |
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6. Chew and Connally (Equations) |
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7. Beggs and Robinson (Equations) |
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4. Let the same oil as in Problem 3 (32 °API oil at TR = 160 °F, with Rsb = 800 SCF/STB) be at its bubble point pressure (pb = 3500 psi). (Use ob from the Beggs and Robinson equations above.) Please determine o at p = 4000 psi using Vasquez and Beggs, (a) Graph; (b) Equations.
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Method |
o |
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1. Vasquez and Beggs (Graph) |
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2. Vasquez and Beggs (Equations) |
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1. Give an approximate viscosity at reservoir conditions (T = 140 F, p = 5000 psi) for the following fluids:
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Type of Fluid |
Your Intuition |
Quick Check of Chart and/or Excel Calcs |
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(a) Reservoir water: |
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(b) Light oil (API 35-40) |
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(c) Heavy oil (API 15-20): |
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(c) Gas |
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(First pick numbers from your head. I hope your intuition is right. Then, look at your correlation charts and/or plug basic numbers into the Excel calculations to get a more firm idea. For both oils, consider moderate values of Rs of 600-800 SCF/STB.)
2. How does reservoir water viscosity vary with temperature? Pressure? Salinity? (Sketch three small graphs of w vs. T, w vs. Pressure (p), and w vs. Salinity (S).)
3. Water viscosity: Determine the viscosity of a formation water with these properties: (p = 6000 psi, T = 180 F, and Salinity S = 4 wt % salinity) Use the McClain charts, check with Excel.
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Method |
w1 |
(w/w1) |
w |
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Chart |
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Excel |
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4. Gas viscosity (Lee, Gonzalez and Eakin): For a gas with gravity = 0.9, at p = 5000 psi and T = 160 F, please determine: (a) AMW; (b) Gas Density, g ; (c) Gas viscosity, g . (Use Z from Excel. Show your calculations on another piece of paper.)
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Excel |
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AMW |
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Z |
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g |
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g |
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5. Sketch a graph of how gas viscosity varies with pressure, p.
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Formation Compressibility Equations |
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(Thermodynamic) Definition of Isothermal Compressibility [Eqn (1)] (units are 1/pressure; for petroleum engineers, usually 1/psi) |
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In terms of ordinary derivative (understanding that T = const) [Eqn (2)] |
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In terms of V and p….(this is a(n) (useful) approximation) [Eqn (3)] |
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Integrated form of Eqn (2) [Eqns (4a) and (4b)] |
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Truncated series approximations to Eqns (4) [Eqn (5a) and (5b)] |
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Reduction (V) of pore volume V in a reservoir which has undergone an average p (over the entire volume V) (rearranged Eqn (3)) [Eqn (6)] |
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Series representation of ex….. |
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1. Look at the graph of the Hall data. (a) From the graph, read the cf for = 10%.
(b) From Hall’s equation (1) which takes as a percent, calculate cf for = 10%.
(c) From Hall’s equation (2) which takes as a fraction, calculate cf for = 10%. How close are these three values?
2. Give four examples of volume changes that occur in an oil/free gas/water reservoir as pressure drops.
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Formation Compressibility Correlations |
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1. Hall Correlation (porosity as a PERCENT) (in other words, if = 16%, use 16, not 0.16)
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2. Newman Correlation for Consolidated Sandstones: (porosity as a fraction)
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3. Newman Correlation for Limestones: (porosity as a fraction)
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3. Look at the Newman Consolidated Sandstone graph. (a) From the graph, read the cf for = 10%.
(b) From Newman’s SS equation (3), calculate cf for = 10%. How close are these two values?
4. Look at the Newman Limestone graph. (a) From the graph, read the cf for = 15%.
(b) From Newman’s LS equation (4), calculate cf for = 15%. How close are these two values?
5. A reservoir with an initial pressure of p1 = 7800 psi has a porosity 1 = 17.0%. If the reservoir has a formation compressibility of cf = 8·10-6 1/psi, determine the porosity 2 of the formation after the average pressure has declined to 6500 psi. Use both the “exact” equation and the equation using the truncated series approximation for ex. [Answers: 16.823% and 16.823%]
6. Below is a graph of measured values of cf for friable sandstones. Does the Hall correlation fit this data? Would any correlation fit this data set? Why is this data so scattered?
From Newman’s paper: Measured values of cf for friable sandstones.
Petr 241: Formation Compressibility Correlations
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1. Hall Correlation (porosity as a PERCENT) (in other words, if = 16%, use 16, not 0.16)
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2. Hall Correlation (porosity as a fraction) (in other words, if = 16%, use 0.16)
(I do not know the origin of this version of Hall’s. Most books give the first version of Hall’s. Both give fairly similar results (but not identical). Note: The Hall correlations are based on only 12 rock data points! Sandstones and limestones. This is a very limited set of data. |
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3. Newman Correlation for Consolidated Sandstones: (porosity as a fraction)
This was based on data for 79 SS samples, ranging in porosities from 2-23%. The average error of the correlation is 2.6%. Note that this equation (and the one below) are of the general hyperbolic form:
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4. Newman Correlation for Limestones: (porosity as a fraction)
This was based on data for LS samples (not sure the number) ranging in porosities from 2-33%, with average error of 11.8%. (A poorer correlation for LS.)
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