Operations CASE, SLP and TD

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Gantt chart

Critical Path Method (CPM)

Program Evaluation and Review Technique (PERT)

Project Management Techniques

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A Simple Gantt Chart

Time

J F M A M J J A S

Design

Prototype

Test

Revise

Production

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Service For A Delta Jet

Figure 3.4

Passengers

Baggage

Fueling

Cargo and mail

Galley servicing

Lavatory servicing

Drinking water

Cabin cleaning

Cargo and mail

Flight services

Operating crew

Baggage

Passengers

Deplaning

Baggage claim

Container offload

Pumping

Engine injection water

Container offload

Main cabin door

Aft cabin door

Aft, center, forward

Loading

First-class section

Economy section

Container/bulk loading

Galley/cabin check

Receive passengers

Aircraft check

Loading

Boarding

0 15 30 45 60

Minutes

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Project Control Reports

Detailed cost breakdowns for each task

Total program labor curves

Cost distribution tables

Functional cost and hour summaries

Raw materials and expenditure forecasts

Variance reports

Time analysis reports

Work status reports

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Network techniques

Developed in 1950’s

CPM by DuPont for chemical plants (1957)

PERT by Booz, Allen & Hamilton with the U.S. Navy, for Polaris missile (1958)

Consider precedence relationships and interdependencies

Each uses a different estimate of activity times

PERT and CPM

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Six Steps PERT & CPM

Define the project and prepare the work breakdown structure

Develop relationships among the activities - decide which activities must precede and which must follow others

Draw the network connecting all of the activities

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Six Steps PERT & CPM

Assign time and/or cost estimates to each activity

Compute the longest time path through the network – this is called the critical path

Use the network to help plan, schedule, monitor, and control the project

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When will the entire project be completed?

What are the critical activities or tasks in the project?

Which are the noncritical activities?

What is the probability the project will be completed by a specific date?

Questions PERT & CPM
Can Answer

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Is the project on schedule, behind schedule, or ahead of schedule?

Is the money spent equal to, less than, or greater than the budget?

Are there enough resources available to finish the project on time?

If the project must be finished in a shorter time, what is the way to accomplish this at least cost?

Questions PERT & CPM
Can Answer

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A Comparison of AON and AOA Network Conventions

Activity on Activity Activity on

Node (AON) Meaning Arrow (AOA)

Figure 3.5

A comes before B, which comes before C

(a)

A

B

C

B

A

C

A and B must both be completed before C can start

(b)

A

C

C

B

A

B

B and C cannot begin until A is completed

(c)

B

A

C

A

B

C

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A Comparison of AON and AOA Network Conventions

Activity on Activity Activity on

Node (AON) Meaning Arrow (AOA)

Figure 3.5

A

B

C

D

B

A

C

D

C and D cannot begin until A and B have both been completed

(d)

C

A

B

D

Dummy activity

A

B

C

D

C cannot begin until both A and B are completed; D cannot begin until B is completed. A dummy activity is introduced in AOA

(e)

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A Comparison of AON and AOA Network Conventions

Activity on Activity Activity on

Node (AON) Meaning Arrow (AOA)

Figure 3.5

A

C

D

B

A

B

C

D

Dummy activity

B and C cannot begin until A is completed. D cannot begin until both B and C are completed. A dummy activity is again introduced in AOA.

(f)

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AON Example

Milwaukee Paper Manufacturing's
Activities and Predecessors

Table 3.1

Activity Description Immediate Predecessors
A Build internal components
B Modify roof and floor
C Construct collection stack A
D Pour concrete and install frame A, B
E Build high-temperature burner C
F Install pollution control system C
G Install air pollution device D, E
H Inspect and test F, G

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AON Network for Milwaukee Paper

Figure 3.6

A

Start

B

Start Activity

Activity A

(Build Internal Components)

Activity B

(Modify Roof and Floor)

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AON Network for Milwaukee Paper

Figure 3.7

C

D

A

Start

B

Activity A Precedes Activity C

Activities A and B Precede Activity D

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AON Network for Milwaukee Paper

Figure 3.8

G

E

F

H

C

A

Start

D

B

Arrows Show Precedence Relationships

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AOA Network for Milwaukee Paper

Figure 3.9

H

(Inspect/ Test)

7

Dummy Activity

6

F

(Install Controls)

E

(Build Burner)

G

(Install Pollution Device)

5

D

(Pour Concrete/ Install Frame)

4

C

(Construct Stack)

1

3

2

B

(Modify Roof/Floor)

A

(Build Internal Components)

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Determining the Project Schedule

Perform a Critical Path Analysis

  • The critical path is the longest path through the network
  • The critical path is the shortest time in which the project can be completed
  • Any delay in critical path activities delays the project
  • Critical path activities have no slack time

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Determining the Project Schedule

Perform a Critical Path Analysis

Table 3.2

Activity Description Time (weeks)

A Build internal components 2

B Modify roof and floor 3

C Construct collection stack 2

D Pour concrete and install frame 4

E Build high-temperature burner 4

F Install pollution control system 3

G Install air pollution device 5

H Inspect and test 2

Total Time (weeks) 25

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Determining the Project Schedule

Perform a Critical Path Analysis

Table 3.2

Activity Description Time (weeks)

A Build internal components 2

B Modify roof and floor 3

C Construct collection stack 2

D Pour concrete and install frame 4

E Build high-temperature burner 4

F Install pollution control system 3

G Install air pollution device 5

H Inspect and test 2

Total Time (weeks) 25

Earliest start (ES) = earliest time at which an activity can start, assuming all predecessors have been completed

Earliest finish (EF) = earliest time at which an activity can be finished

Latest start (LS) = latest time at which an activity can start so as to not delay the completion time of the entire project

Latest finish (LF) = latest time by which an activity has to be finished so as to not delay the completion time of the entire project

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Determining the Project Schedule

Perform a Critical Path Analysis

Figure 3.10

Activity Name or Symbol

A

Earliest Start

ES

Earliest Finish

EF

Latest Start

LS

Latest Finish

LF

Activity Duration

2

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Forward Pass

Begin at starting event and work forward

Earliest Start Time Rule:

If an activity has only one immediate predecessor, its ES equals the EF of the predecessor

If an activity has multiple immediate predecessors, its ES is the maximum of all the EF values of its predecessors

ES = Max (EF of all immediate predecessors)

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Forward Pass

Begin at starting event and work forward

Earliest Finish Time Rule:

The earliest finish time (EF) of an activity is the sum of its earliest start time (ES) and its activity time

EF = ES + Activity time

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ES/EF Network for Milwaukee Paper

Start

0

0

ES

0

EF = ES + Activity time

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ES/EF Network for Milwaukee Paper

Start

0

0

0

A

2

2

EF of A =
ES of A + 2

0

ES
of A

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ES/EF Network for Milwaukee Paper

B

3

Start

0

0

0

A

2

2

0

3

EF of B =
ES of B + 3

0

ES
of B

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ES/EF Network for Milwaukee Paper

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

*

ES/EF Network for Milwaukee Paper

7

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

D

4

= Max (2, 3)

3

*

ES/EF Network for Milwaukee Paper

D

4

3

7

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

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ES/EF Network for Milwaukee Paper

Figure 3.11

E

4

F

3

G

5

H

2

4

8

13

15

4

8

13

7

D

4

3

7

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

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Backward Pass

Begin with the last event and work backwards

Latest Finish Time Rule:

If an activity is an immediate predecessor for just a single activity, its LF equals the LS of the activity that immediately follows it

If an activity is an immediate predecessor to more than one activity, its LF is the minimum of all LS values of all activities that immediately follow it

LF = Min (LS of all immediate following activities)

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Backward Pass

Begin with the last event and work backwards

Latest Start Time Rule:

The latest start time (LS) of an activity is the difference of its latest finish time (LF) and its activity time

LS = LF – Activity time

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LS/LF Times for
Milwaukee Paper

Figure 3.12

E

4

F

3

G

5

H

2

4

8

13

15

4

8

13

7

D

4

3

7

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

LF = EF
of Project

15

13

LS = LF – Activity time

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LS/LF Times for
Milwaukee Paper

Figure 3.12

E

4

F

3

G

5

H

2

4

8

13

15

4

8

13

7

13

15

D

4

3

7

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

LF = Min(LS of following activity)

10

13

*

LS/LF Times for
Milwaukee Paper

Figure 3.12

E

4

F

3

G

5

H

2

4

8

13

15

4

8

13

7

13

15

10

13

8

13

4

8

D

4

3

7

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

LF = Min(4, 10)

4

2

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LS/LF Times for
Milwaukee Paper

Figure 3.12

E

4

F

3

G

5

H

2

4

8

13

15

4

8

13

7

13

15

10

13

8

13

4

8

D

4

3

7

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

4

2

8

4

2

0

4

1

0

0

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Computing Slack Time

After computing the ES, EF, LS, and LF times for all activities, compute the slack or free time for each activity

Slack is the length of time an activity can be delayed without delaying the entire project

Slack = LS – ES or Slack = LF – EF

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Computing Slack Time

Table 3.3

Earliest Earliest Latest Latest On
Start Finish Start Finish Slack Critical
Activity ES EF LS LF LS – ES Path

A 0 2 0 2 0 Yes

B 0 3 1 4 1 No

C 2 4 2 4 0 Yes

D 3 7 4 8 1 No

E 4 8 4 8 0 Yes

F 4 7 10 13 6 No

G 8 13 8 13 0 Yes

H 13 15 13 15 0 Yes

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Critical Path for
Milwaukee Paper

Figure 3.13

E

4

F

3

G

5

H

2

4

8

13

15

4

8

13

7

13

15

10

13

8

13

4

8

D

4

3

7

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

4

2

8

4

2

0

4

1

0

0

*

ES – EF Gantt Chart
for Milwaukee Paper

A Build internal components

B Modify roof and floor

C Construct collection stack

D Pour concrete and install frame

E Build high-temperature burner

F Install pollution control system

G Install air pollution device

H Inspect and test

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

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LS – LF Gantt Chart
for Milwaukee Paper

A Build internal components

B Modify roof and floor

C Construct collection stack

D Pour concrete and install frame

E Build high-temperature burner

F Install pollution control system

G Install air pollution device

H Inspect and test

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

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CPM assumes we know a fixed time estimate for each activity and there is no variability in activity times

PERT uses a probability distribution for activity times to allow for variability

Variability in Activity Times

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Three time estimates are required

Optimistic time (a) – if everything goes according to plan

Most–likely time (m) – most realistic estimate

Pessimistic time (b) – assuming very
unfavorable conditions

Variability in Activity Times

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Estimate follows beta distribution

Variability in Activity Times

Expected time:

Variance of times:

t = (a + 4m + b)/6

v = [(b – a)/6]2

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Estimate follows beta distribution

Variability in Activity Times

Expected time:

Variance of times:

t = (a + 4m + b)/6

v = [(b − a)/6]2

Probability of 1 in 100 of
< a occurring

Probability of 1 in 100 of > b occurring

Probability

Optimistic Time (a)

Most Likely Time (m)

Pessimistic Time (b)

Activity Time

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Computing Variance

Table 3.4

Most Expected
Optimistic Likely Pessimistic Time Variance
Activity a m b t = (a + 4m + b)/6 [(b – a)/6]2

A 1 2 3 2 .11

B 2 3 4 3 .11

C 1 2 3 2 .11

D 2 4 6 4 .44

E 1 4 7 4 1.00

F 1 2 9 3 1.78

G 3 4 11 5 1.78

H 1 2 3 2 .11

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Probability of Project Completion

Project variance is computed by summing the variances of critical activities

s2 = Project variance

= (variances of activities
on critical path)

p

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Probability of Project Completion

Project variance is computed by summing the variances of critical activities

Project variance

s2 = .11 + .11 + 1.00 + 1.78 + .11 = 3.11

Project standard deviation

sp = Project variance

= 3.11 = 1.76 weeks

p

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Probability of Project Completion

PERT makes two more assumptions:

  • Total project completion times follow a normal probability distribution
  • Activity times are statistically independent

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Probability of Project Completion

Standard deviation = 1.76 weeks

Figure 3.15

15 Weeks

(Expected Completion Time)

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Probability of Project Completion

What is the probability this project can be completed on or before the 16 week deadline?

Where Z is the number of standard deviations the due date lies from the mean

Z = – /sp

= (16 wks – 15 wks)/1.76

= 0.57

due expected date
date of completion

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Probability of Project Completion

What is the probability this project can be completed on or before the 16 week deadline?

Where Z is the number of standard deviations the due date lies from the mean

Z = − /sp

= (16 wks − 15 wks)/1.76

= 0.57

due expected date
date of completion

.00 .01 .07 .08

.1 .50000 .50399 .52790 .53188

.2 .53983 .54380 .56749 .57142

.5 .69146 .69497 .71566 .71904

.6 .72575 .72907 .74857 .75175

From Appendix I

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Probability of Project Completion

Figure 3.16

Time

Probability
(T ≤ 16 weeks)
is 71.57%

0.57 Standard deviations

15 16
Weeks Weeks

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Determining Project Completion Time

Figure 3.17

Probability of 0.01

Z

From Appendix I

Probability of 0.99

2.33 Standard deviations

0

2.33

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Variability of Completion Time for Noncritical Paths

Variability of times for activities on noncritical paths must be considered when finding the probability of finishing in a specified time

Variation in noncritical activity may cause change in critical path

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What Project Management Has Provided So Far

The project’s expected completion time is 15 weeks

There is a 71.57% chance the equipment will be in place by the 16 week deadline

Five activities (A, C, E, G, and H) are on the critical path

Three activities (B, D, F) have slack time and are not on the critical path

A detailed schedule is available

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Trade-Offs And Project Crashing

The project is behind schedule

The completion time has been moved forward

It is not uncommon to face the following situations:

Shortening the duration of the project is called project crashing

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Factors to Consider When Crashing A Project

The amount by which an activity is crashed is, in fact, permissible

Taken together, the shortened activity durations will enable us to finish the project by the due date

The total cost of crashing is as small as possible

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Steps in Project Crashing

  • Using current activity times, find the critical path and identify the critical activities

(Crash cost – Normal cost)

(Normal time – Crash time)

Crash cost

per period

=

  • Compute the crash cost per time period. If crash costs are linear over time:

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Steps in Project Crashing

If there is only one critical path, then select the activity on this critical path that (a) can still be crashed, and (b) has the smallest crash cost per period. If there is more than one critical path, then select one activity from each critical path such that (a) each selected activity can still be crashed, and (b) the total crash cost of all selected activities is the smallest. Note that a single activity may be common to more than one critical path.

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Steps in Project Crashing

Update all activity times. If the desired due date has been reached, stop. If not, return to Step 2.

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Crashing The Project

Table 3.5

Time (Wks) Cost ($) Crash Cost Critical
Activity Normal Crash Normal Crash Per Wk ($) Path?

A 2 1 22,000 22,750 750 Yes

B 3 1 30,000 34,000 2,000 No

C 2 1 26,000 27,000 1,000 Yes

D 4 2 48,000 49,000 1,000 No

E 4 2 56,000 58,000 1,000 Yes

F 3 2 30,000 30,500 500 No

G 5 2 80,000 84,500 1,500 Yes

H 2 1 16,000 19,000 3,000 Yes

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Crash and Normal Times and Costs for Activity B

Figure 3.18

| | |

1 2 3 Time (Weeks)

$34,000 —

$33,000 —

$32,000 —

$31,000 —

$30,000 —

Activity Cost

Crash

Normal

Crash Cost

Normal Cost

Crash Time

Normal Time

Crash Cost/Wk =

Crash Cost – Normal Cost

Normal Time – Crash Time

=

$34,000 – $30,000

3 – 1

= = $2,000/Wk

$4,000

2 Wks

*

Critical Path And Slack Times For Milwaukee Paper

Figure 3.19

E

4

F

3

G

5

H

2

4

8

13

15

4

8

13

7

13

15

10

13

8

13

4

8

D

4

3

7

C

2

2

4

B

3

0

3

Start

0

0

0

A

2

2

0

4

2

8

4

2

0

4

1

0

0

Slack = 1

Slack = 1

Slack = 0

Slack = 6

Slack = 0

Slack = 0

Slack = 0

Slack = 0

*

Advantages of PERT/CPM

Especially useful when scheduling and controlling large projects

Straightforward concept and not mathematically complex

Graphical networks help to perceive relationships among project activities

Critical path and slack time analyses help pinpoint activities that need to be closely watched

*

Advantages of PERT/CPM

Project documentation and graphics point out who is responsible for various activities

Applicable to a wide variety of projects

Useful in monitoring not only schedules but costs as well

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Project activities have to be clearly defined, independent, and stable in their relationships

Precedence relationships must be specified and networked together

Time estimates tend to be subjective and are subject to fudging by managers

There is an inherent danger of too much emphasis being placed on the longest, or critical, path

Limitations of PERT/CPM

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Using Microsoft Project

Program 3.1

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Using Microsoft Project

Program 3.2

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Using Microsoft Project

Program 3.3

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Using Microsoft Project

Program 3.4

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Using Microsoft Project

Program 3.5

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Using Microsoft Project

Program 3.6

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Using Microsoft Project

Program 3.7

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