Algebra Question (Logarithm)

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Solve

Therefore either or

If

Or ,

If

Hence possible values of x are

log(25)0

x

+=

log(25)log1 log 1 =

0

x

®+=

Q

(25)1 24

xorx

+=®=-

2

x

=-

22

log(9)0log(9)log1

xx

=®=

2

91

x

®=

2

1

9

x

®=

1

3

x

®=±

1

2 or

3

x

®=-±

2

log(25)log(9)0

xx

+´=

log(25)0

x

+=

2

log(9)0

x

=