Physics report
aaa6j
physics_4.pptxBoy-Antsysp
Chase H.
Ali A.
Kadarius F.
Delta Group
Statement of the Problem
Problem: According to our lab professor, the determining factor of whether or not an object sinks or floats is not due to your ability to swim but because of boy-antsysp. Before they come up with another pre-written pre-examined experiment to prove me wrong, we plan on proving them wrong first.
Purpose: The purpose of this examination is to determine what factors truly influence the floatation of an object.
Equipment: Mass Set, Beaker, spring, Unknown Liquid, and Scale
What You Did and Why?
Procedure: Various masses will be suspended by a spring and placed in a container of a liquid. The masses will be changed in order to create variation in the results. For each mass change the density of the object will be calculated using the displacements method to determine volume and using the labeled and confirmed mass given any uncertainties present and using the equation below. 𝜌=𝑚𝑣
Mass may not touch the bottom of the beaker
Mass is made of brass and the density must be determined
400 mL is the initial volume of liquid
.
Results
| Xf Spring | ΔL Spring | m (g) | m (kg) | vf | vsubmerged | |
| δ (xf)) = .2 | δ (L) = .2 | δ (m) = .06 | δ (m) = .06 | δ (vf) = 5 | δ (v submerged) = 5 | |
| 42.1 cm | 18.1 cm | 200 g | 0.2 kg | 415 mL | 15 mL | |
| 52.0 cm | 33.9 cm | 300 g | 0.3 kg | 430 mL | 30 mL | |
| 61.6 cm | 37.2 cm | 400 g | 0.4 kg | 450 mL | 50mL | |
| 71.5 cm | 47.1 cm | 500 g | 0.5 kg | 450 mL | 50 mL | |
| 80.9 cm | 56.5 cm | 600 g | 0.6 kg | 465 mL | 65 mL | |
| 103.0 cm | 78.6 cm | 1000 g | 1.0 kg | 500 mL | 100 mL | |
| Average: | 68.6 cm | 45.2 cm | 500 g | 0.5 kg | 451.7 mL | 51.7 mL |
Mass of liquid: 298.4 g
Intial Volume: 400 mL
Density of alcohol: 0.7851 g/cm3
Initial Spring Length: 24.4 cm
Mass of liquid is calculated by measuring 100mL multiplied by 4 for 400mL
5
Graphical Analysis
Mass vs. Submerged Volume
15 30 50 50 65 100 200 300 400 500 600 1000Submerged Volume (mL)
Mass (g)
Graphical Analysis
15 30 50 50 65 100 18.100000000000001 33.9 37.200000000000003 47.1 56.5 78.599999999999994
Submerged Volume (mL)
Change in Legnth (cm)
Evaluation
In order to determine the buoyancy force and spring force active on the object which should both be constant as long as the liquid and spring remains the same, the manipulation of force equations and conservation of matter will produce the equation ∆𝑦= which would serve as the theoretical equation of this examination which is further simplified to ∆𝑦= as a substitution for mass . Thus the below equation is the Theoretical Equation for the evaluation.
Evaluation
The variables solved for using the theoretical equation would be used to evaluate the following force equations:
Explanation of Uncertainties
Conclusion
Using the given analysis and evaluations, the spring constant (k) was determined to be 1012.53 N/cm or 101253.0 N/m given
The spring force active on the system is 45766.36 N given . The buoyancy force active on the system is 0.40 N given . As a result, in this experiment the spring force is more active than the buoyancy force but the buoyancy force does exist based on the theoretical evaluation.
