Plane Surevying

COURSE: PLANE SURVEYING

MIDTERM EXAM

2 points

1. Three-wire leveling is

a. Leveling procedure using three horizontal lines of cross hairs

b. Leveling procedure using three rods

c. Neither of the above

2 points

2. Correction for the Az in 3rd quadrant is:

a. 180+ά

b. 180-ά

c. 270-ά

2 points

3. The azimuth has a range of:

a. 0° - 90°

b. 0 – 400grad

c. 1000 – 6400mils

2 points

4. Find the azimuth which is equal to bearing N 95°W

a. 75°

b. 275°

c. 95°

d. None of the above

2 points

5. The Two –Peg test is

a. A check for collimation error

b. A check for indexing of horizontal circle

c. To check the Level for vertical collimation error

2 points

6. The result of computing Inverse problem is:

a. Bearing and Distance

b. Azimuth and Distance

c. Hz and Distance

2 points

7. The automatic compensator is a device

a. That compensate human errors

b. That automatically adjust the instrument to the level surface

c. That automatically levels the line of sight

2 points

8. X,Y,Z are coordinates in

a. Geocentric coordinate system

b. Geodetic coordinate system

c. Grid coordinate system

2 points

9. Leveling is a process of

a. Finding orthometric height of a point

b. Finding the difference in elevation between points

c. Calculating the heights of a point

2 points

10. The collimation error exists if

a. The vertical axis is not perpendicular to the horizontal axis

b. The Line of sight is not perpendicular to the vertical axis

c. The Line of sight is not parallel to the line of plate vial

2 points

11. The Latitude is measured from

a. Equator

b. Great circle

c. Meridian

2 points

12. Conical map projection can be used to project:

a. Equator

b. Mid Latitude

c. North pole

3 points

13. Convergence of a meridian is

a. Angle between two meridians

b. Angle between tangents to two meridians

c. Adjusted value of a traverse azimuth

4 points

14. If RMS for a Leica TPS 400 is 5mm +2ppm calculate the expected error for a distance of 5000m

4 points

15. Find the angle if the readings from the horizontal circle are as follows: at point A = 352° 30’ 50”, and at point B = 184° 48’ 34”. Graduation of horizontal circle is “clock-wise” and point A is your left point.

a. 192° 17’ 44”

b. 177° 15’ 42”

c. 191.9314gon

4 points

16. Convert 1.8576rad to 118.25848891 5 grads, 106d25’57” DMS and 106.4326400235 DD

4 points

17. Compute the combined effect of the earth’s curvature and atmospheric refraction for distances of 1.8mi. and 14.5km.

= 0.667 * d^2/2R

= 0.667 * 1.8^2 / 2* 3,959

= 0.667 * 3.24 / 7918

= .0002729 mi

= 0.87 * 210.25 / 12470

= 0.1466 km

6 points

18. Find and adjust the vertical angle if the zenith angle was measured as 244( 25’ 25” in reversed position and 115( 34’ 30” in direct position

6 points

19. Calculate coordinates of point B if the TS was setup over point A ( X = 1524.78, Y = 2687.39) and following data was measured:

AzAB = 152.8672°, SD = 895.16ft, z = 89.6291°

9 points

20. Find the elevation of point B if TS is set over point A with H = 5802.48m and the measured data is:

hi = 1.56m, z = 76º 51’ 30”, SD = 2518.33m, hr= 2.49m

9 points

21. Having Geodetic coordinates for point A, Latitude = 39°20'40.00000" N, Longitude = 104°15'25.00000" W , Elevation = 1,658.000 m and using DATUM: GRS80

Calculate geocentric coordinates of the point (X, Y, Z)

9 points

22. Using given geodetic coordinates for point WRWA

Latitude = 39°50'52.4746"N, Longitude = 104°40'40.0826"W

Calculate SPCS for this point for Colorado Central zone and utilize GRS80 ellipsoid.

State Plane X Y (Meters) 0502 984768.623mE 528761.515mN

X Y (US Survey Feet) 0502 3230861.724ftUSE 1734778.405ftUSN

X Y (International Feet) 0502 3230868.185ftE 1734781.874ftN

9 points

23. Complete and check the following sets of level notes: