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Question 1.

1. (TCO 1) The signal is 5 sin (2 pi 2000 t + 60 degrees). The amplitude of this signal is (Points : 5)

       5 VPP

       3.535 VPP

       3.535 VRMS

       3.535 VPK

Question 2.

2. (TCO 1) The signal is 5 sin (2 pi 2000 t + 60 degrees). The frequency of this signal is (Points : 5)

       2000 Hz

       1000 Hz

       6280 Hz

       10 kHz

Question 3.

3. (TCO 1) The signal is 10 sin (2 pi 1000 t + 30 degrees). The phase shift of this signal is (Points : 5)

       +60 degrees

       +30 degrees

       -30 degrees

       -90 degrees

Question 4.

4. (TCO 1) The signal is 5 sin (2 pi 2000 t + 60 degrees). The voltage displayed on the DMM is (Points : 5)

       5 VPP

       3.535 VPP

       3.535 VRMS

       3.535 VPK

Question 5.

5. (TCO 1) Inductive reactance is the opposition that an inductor shows to _______. (Points : 5)

       alternating current

       direct current

       AC and DC

       none of the above

Question 6.

6. (TCO 2) In an AC circuit a resistor, a reactance XC and a reactance XL are connected in series. The circuit current (Points : 5)

       leads the applied voltage.

       lags the applied voltage.

       is in phase with the voltage.

       leads or lags the applied depending on the reactance that dominates in the circuit.

Question 7.

7. (TCO 2) For the following series AC circuit, the angle of the circuit impedance is

(Points : 5)

       0 degrees

       +90 degrees

       +45 degrees

       -45 degrees

Question 8.

8. (TCO 2) For the following series AC circuit, the phase angle of the circuit current is

(Points : 5)

       0 degrees

       +90 degrees

       +45 degrees

       -45 degrees

 

Question 9.

9. (TCO 2) For the following series AC circuit, the total circuit impedance is:

(Points : 5)

       100 - j 100

       100 + j 100

       100 - j 200

       100 + j 300

Question 10.

10. (TCO 3) For the parallel AC circuit shown below, find the circuit current IS . Note that Vin AC is mislabeled, it should be 10V, NOT 10 sin(ω t).

(Points : 5)

       0.1 + j 0.1 A

       0.1 - j 0.1 A

       0.1 A

       j 0.2 A

Question 11.

11. (TCO 3) The total admittance for the following circuit is

Hint: YT = G + j (BC - BL) siemens; G = 1/R siemens; BC = C siemens and BL = 1/[ L ] siemens

(Points : 5)

       0.005 - j 0.005 siemens

       0.005 + j 0.005 siemens

       0.01 - j 0.005 siemens

       0.01 + j 0.005 siemens