Cost Estimation Question
Cost Estimation
Lecture 13
Chapter 5
Implementation Problems with Regression Data
1. Curvilinear costs
2. Outliers
3. Spurious relations
4. Assumptions
Implementation Problems, Continued. . .
1. Curvilinear costs
Relevant
Range
Problem: Attempting to fit a linear model to nonlinear data. Likely to occur near full- capacity.
Solution: Define a more limited relevant range (example: from 25 – 75% capacity) or design a nonlinear model.
Implementation Problems, Continued. . .
2. Outliers
True regression
line
Regression line
with outlier
outlier
Problem: Outlier moves the regression line.
Solution: Prepare a scatter-graph, analyze the graph and eliminate highly unusual observations before running the regression.
Implementation Problems, Continued. . .
3. Spurious relations
Problem: Using too many variables in the regression. For example, using direct labor to explain materials costs. Although the association is very high, actually both are driven by output.
Solution: Carefully analyze each variable and determine the relationship among all elements before using in the regression.
Data Problems
Missing data
Outliers
Inflation
Mismatched time periods
Practice Problems
Chapter 5
Methods to Estimate Cost Behavior
Account analysis
Engineering estimates
Statistical methods
Recap of what we covered last class
Account Analysis
Review each
account comprising
the total cost being
analyzed.
Identify each cost as
either fixed or
variable.
Activity level
Costs ($)
Fixed
Variable
Cost ($)
Activity level
Recap of what we covered last class
Example: Account Analysis
3C Cost Estimation Using Account Analysis
Costs for 360 Repair Hours
Account Total
Office Rent $3,375
Utilities 310
Administration 3,386
Supplies 2,276
Training 666
Other 613
Total $10,626
Per Repair Hour
Variable Cost Fixed Cost
$1,375 $2,000
100 210
186 3,200
2,176 100
316 350
257 356
$4,410 $6,216
12.25* Number of Repair Hours6,216 +Total Cost =
$12.25
Recap of what we covered last class
Practice Problem 1 – Account Analysis
Practice Problem 1 – Account Analysis
Practice Problem 1 – Account Analysis
Practice Problem 2 – Account Analysis
Practice Problem 2 – Account Analysis
Practice Problem 2 – Account Analysis
Statistical Cost Estimation
Statistical procedure to determine the
relationship between variables.
High-Low Method
Regression
Uses two data points.
Uses all the data points.
3C Overhead
Recap of what we covered last class
High-Low Cost Estimation
V Cost at highest activity Cost at lowest activity
Highest activity Lowest activity
F Highest activityTotal cost at highest activity level
V
or
Lowest activityTotal cost at lowest
activity level V
Recap of what we covered last class
Practice Problem 3 – High-Low Cost Estimation
Practice Problem 3 – High-Low Cost Estimation
Maintenance costs = Fixed Costs + 1(number of visitors)
Month Labor-Hours Machine-HoursOverhead Costs
1 725 1355 102687
2 715 1407 103792
3 680 1520 109915
4 740 1453 108280
5 780 1591 116229
6 755 1579 114464
7 740 1390 107022
8 725 1306 102094
9 710 1454 106439
10 795 1545 113067
11 675 1298 100755
12 710 1604 112842
Practice Problem 4 – High-Low Cost Estimation A
Practice Problem 4 – High-Low Cost Estimation
Month Labor-Hours Machine-HoursOverhead Costs
1 725 1355 102687
2 715 1407 103792
3 680 1520 109915
4 740 1453 108280
5 780 1591 116229
6 755 1579 114464
7 740 1390 107022
8 725 1306 102094
9 710 1454 106439
10 795 1545 113067
11 675 1298 100755
12 710 1604 112842
Practice Problem 4 – High-Low Cost Estimation A
Month Labor-Hours Machine-Hours Overhead Costs
1 725 1355 102687
2 715 1407 103792
3 680 1520 109915
4 740 1453 108280
5 780 1591 116229
6 755 1579 114464
7 740 1390 107022
8 725 1306 102094
9 710 1454 106439
10 795 1545 113067
11 675 1298 100755
12 710 1604 112842
Practice Problem 5 – Simple Regression
Considering the machine-hours as predictor, what is the simple regression equation?
A
Practice Problem 5 – Simple Regression
Month Labor-Hours Machine-HoursOverhead Costs
1 725 1355 102687
2 715 1407 103792
3 680 1520 109915
4 740 1453 108280
5 780 1591 116229
6 755 1579 114464
7 740 1390 107022
8 725 1306 102094
9 710 1454 106439
10 795 1545 113067
11 675 1298 100755
12 710 1604 112842
Practice Problem 5 – Simple Regression
Considering the labor-hours as predictor, what is the simple regression equation?
A
Practice Problem 5 – Simple Regression
Multiple Regression
Multiple Regression: When more than one predictor (x)
is in the model.
Equation: TC = V1 (X1) + V2 (X2) + FC
Recap of what we covered last class
Month Labor-Hours Machine-HoursOverhead Costs
1 725 1355 102687
2 715 1407 103792
3 680 1520 109915
4 740 1453 108280
5 780 1591 116229
6 755 1579 114464
7 740 1390 107022
8 725 1306 102094
9 710 1454 106439
10 795 1545 113067
11 675 1298 100755
12 710 1604 112842
Considering both labor-hours and machine-hours, what is the simple regression equation?
Practice Problem 6 – Multiple Regression A
Practice Problem 6 – Multiple Regression