Cost Estimation Question
Cost Estimation
Lecture 12
Chapter 5
Methods to Estimate Cost Behavior
Account analysis
Engineering estimates
Statistical methods
Recap of what we covered last class
Engineering Estimates
Cost estimates are based on measuring and then pricing the work involved in a task.
Identify the activities involved
Estimate the time and cost for each activity.
Labor
Rent
Insurance
Recap of what we covered last class
Account Analysis
Review each
account comprising
the total cost being
analyzed.
Identify each cost as either fixed or variable.
Activity level
Costs
($)
Fixed
Variable
Cost
($)
Activity level
Recap of what we covered last class
Statistical Cost Estimation
The limits within which a cost estimate may be valid.
Relevant range for a projection is usually between
the upper and lower limits (bounds)of past activity
levels for which data is available.
Analyze costs within a relevant range.
Relevant range?
Recap of what we covered last class
Statistical Cost Estimation
Statistical procedure to determine the relationship between variables.
High-Low Method
Regression
Uses two data points.
Uses all the data points.
3C Overhead
Example: Overhead Costs for 3C
The following information is used throughout this chapter:
Month Overhead Costs Repair-Hours
1 9,891 248
2 9,244 248
3 13,200 480
4 10,555 284
5 9,054 200
6 10,662 380
7 12,883 568
8 10,345 344
9 11,217 448
10 13,269 544
11 10,830 340
12 12,607 412
13 10,871 384
14 12,816 404
15 8,464 212
High-Low Cost Estimation
3C Overhead
Repair-Hours
A method to estimate costs based on two cost observations, usually at the highest and lowest activity level.
Choose two data
points.
Use the two points to
determine the line
representing the cost-
activity relation.
Draw a total cost line.
The highest and lowest activity.
Recap of what we covered last class
Highest
Activity
Level
Lowest
Activity
Level
Ɵ
Slop = tan Ɵ
M
N
Slop = M
N
Δ Total Cost
Δ Activity Slop =
Cost
Activity
Level
High-Low Cost Estimation
TC = VC(X) + FC
Recap of what we covered last class
Example: High-Low Cost Estimation, Contd .
A method to
estimate cost based
on two cost
observations, the
highest and lowest
activity level.
Month Overhead Costs Repair-Hours
1 9,891 248
2 9,244 248
3 13,200 480
4 10,555 284
5 9,054 200
6 10,662 380
7 12,883 568
8 10,345 344
9 11,217 448
10 13,269 544
11 10,830 340
12 12,607 412
13 10,871 384
14 12,816 404
15 8,464 212
Example: High-Low Cost Estimation, Contd .
A method to estimate cost based on two cost
observations, the highest and lowest activity level.
Month
OH Cost
Repair-
Hours
High 12,883 568
Low 9,054 200
Change 3,829 368
By definition, the change in cost due to a
change in activity is variable cost. So, to
calculate unit variable cost:
Δ Total Cost
Δ Activity =
3,829
368 =
10.40
VC per unit
TC = VC(X) + FC
9,054 = VC(200) + FC
9,054 = 10.40(200) + FC
9,054 = 2,080 + FC
FC = 6,974
TC = 10.40(X) + 6,974
Recap of what we covered last class
Statistical Cost Estimation
Statistical procedure to determine the relationship between variables.
High-Low Method
Regression
Uses two data points.
Uses all the data points.
3C Overhead
Independent variable Dependent variable
The X term, or predictor.
The activity that predicts
(causes) the change in
costs.
The Y term. The
dependent variable. The
cost to be estimated.
Repair-hours (X)
Overhead costs (Y)
The relationship between activities and costs
Costs
Activities
Y = a + b X
Statistical Cost Estimation Using Regression Analysis
Regression, Continued. . .
Y = a + b X
Y Intercept Slope X
Repair-hours OH Fixed costs V
The Regression Equation
= +
= +
Regression, Continued. . .
Y = a + b X
The Regression Equation
Where
Month Overhead Costs (y) Repair-Hours (x)
1 9,891 248
2 9,244 248
3 13,200 480
4 10,555 284
5 9,054 200
6 10,662 380
7 12,883 568
8 10,345 344
9 11,217 448
10 13,269 544
11 10,830 340
12 12,607 412
13 10,871 384
14 12,816 404
15 8,464 212
Excel
Regression, Continued. . .
Month Overhead Costs Repair-Hours
1 9,891 248
2 9,244 248
3 13,200 480
4 10,555 284
5 9,054 200
6 10,662 380
7 12,883 568
8 10,345 344
9 11,217 448
10 13,269 544
11 10,830 340
12 12,607 412
13 10,871 384
14 12,816 404
15 8,464 212
Regression Using Excel. . .
Excel
Interpreting Regression
Y = Intercept Slope X
Y = F + V X
Learning Objectives:
1. Understand the reasons for estimating fixed and variable costs.
3. Estimate costs using account analysis.
2. Estimate costs using engineering estimates.
4. Estimate costs using statistical analysis.
5. Interpret the results of regression output.
6. Identify potential problems with regression data.
7. Evaluate the advantages and disadvantages of alternative
cost estimates.
Interpreting Regression, Continued. . .
Correlation
coefficient
“R” measures the linear relationship between
variables. The closer R is to 1.0 the closer the
points are to the regression line. The closer R is to
zero, the poorer the regression line.
Coefficient of
determination
“R2” The square of the correlation coefficient. The
proportion of the variation in the dependent
variable (Y) explained by the independent
variable(s)(X).
T-Statistic The t-statistic is the value of the estimated coefficient divided by its standard error.
Generally, if it is over 2, then it is considered
significant. If significant, the cost is NOT totally
fixed.
Interpreting Regression, Continued. . .
Correlation Coefficient Coefficient of Determination
A linear relationship does exist between repair hours and overhead costs.
82.8% of the changes in overhead costs can be explained by changes in repair-hours.
.91
.828
Both have t-statistics that are greater than 2, so the cost is not totally fixed.
10.7 & 7.9
T-Statistic
Example: Regression
X
Estimate 3C’s overhead with 520 repair hours.
TC = 6,472 + 12.52
TC = F + V X
Multiple Regression
Multiple Regression: When more than one predictor (x)
is in the model.
Is repair-hours the only activity that drives
overhead costs at 3C?
Predictors: X1: Repair-hours
X2: Parts Cost
Equation: TC = V1 (X1) + V2 (X2) + FC
Multiple Regression, Continued. . .
Month OH Costs Repair-Hours (X1) Parts (X2)
1 9,891 248 1,065
2 9,244 248 1,452
3 13,200 480 3,500
4 10,555 284 1,568
5 9,054 200 1,544
6 10,662 380 1,222
7 12,883 568 2,986
8 10,345 344 1,841
9 11,217 448 1,654
10 13,269 544 2,100
11 10,830 340 1,245
12 12,607 412 2,700
13 10,871 384 2,200
14 12,816 404 3,110
15 8,464 212 752
3C Cost Information
Multiple Regression Output
Correlation coefficient squared and adjusted for the number of
independent variables used to make the estimate.
.89
Adjusted Correlation Coefficient
89% of the changes in overhead costs can be explained by
changes in repair-hours and parts costs.
Adjusted R Square
Multiple Regression Output, Continued. . .
3,500 520
TC = F + V1
= 6,416 + 8.61
+
0.77 +
= 13,588
X1 V2 X2
TC
TC
Can you use this regression output to estimate overhead costs for 520 repair-hours and 3,500 cost of parts?
Statistical Cost Estimation
Advantages
Reliance on historical data is relatively inexpensive.
Computational tools allow for more data to be used
than for non-statistical methods.
Disadvantages
Reliance on historical data may be the only cost-
effective basis for estimating costs.
Choosing an Estimation Method
High-Low
Estimated manufacturing overhead with 520 repair-hours.
Regression
12,384
12,982
Multiple Regression
Account Analysis 12,586
13,588*
520 repair-hours and 3,500 parts costs
* The more sophisticated methods yield more
accurate cost estimates than the simple methods.