i have a beam individual design due after 4 hours. i did everything but the sizes i used were not in the listed sizes that our professor handed out. could you change the sizes with their calculations
DESIGN WORK:
DRAWING
SECTION B 2 X 2.3 DETAILS
SECTION B 2 X 2.4 DETAILS
SECTION B 2 X 2.5 DETAILS
ANALYSIS RESULTS:
Load Diagram
Shear Force Diagram
Bending Moment Diagram
For the shear discontinuity equation, the following units are displayed:
Length units = in
Force units = lb
Moment units = lb-in
Shear discontinuity equation using symbolic notations:
Shear = Ay<x-1.50>0 +By<x-22.50>0 - P1<x-12.00>0
Shear discontinuity equation showing actual numeric values:
Shear = +150.00<x-1.50>0 +150.00<x-22.50>0 - 300.00<x-12.00>0
When using discontinuity functions, if the term in the <> brackets is negative for a particular value of x, the quantity in the <> brackets is defined to have a value of zero.
For the moment discontinuity equation, the following units are displayed:
Length units = in
Force units = lb
Moment units = lb-in
Moment discontinuity equation using symbolic notations:
Moment = Ay<x-1.50>1 +By<x-22.50>1 - P1<x-12.00>1
Moment discontinuity equation showing actual numeric values:
Moment = +150.00<x-1.50>1 +150.00<x-22.50>1 - 300.00<x-12.00>1
When using discontinuity functions, if the term in the <> brackets is negative for a particular value of x, the quantity in the <> brackets is defined to have a value of zero.
Resisting Moment of Beam (MR)
MR = Fb x S
S for a rectangular Section = bd2/6
Design Bending Stress at Extreme Fiber = Fb
RESULTS TABLE
|
S.No |
Section (in) |
Section Modulus (S) in3 |
Length (in) |
Load (lb) |
B.M (lb-in) |
Fb (lb-in) |
MR (lb-in) |
Status |
|
|
|
b |
d |
|
|
|
|
|
|
|
|
1 |
1 |
1 |
0.17 |
21 |
300 |
1575 |
900 |
153 |
Fail |
|
2 |
2 |
2 |
1.33 |
21 |
300 |
1575 |
900 |
1197 |
Fail |
|
3 |
2 |
2.1 |
1.47 |
21 |
300 |
1575 |
900 |
1323 |
Fail |
|
4 |
2 |
2.2 |
1.61 |
21 |
300 |
1575 |
900 |
1449 |
Fail |
|
5 |
2 |
2.3 |
1.76 |
21 |
300 |
1575 |
900 |
1584 |
Pass |
|
6 |
2 |
2.4 |
1.92 |
21 |
300 |
1575 |
900 |
1728 |
Pass |
|
7 |
2 |
2.5 |
2.08 |
21 |
300 |
1575 |
901 |
1874 |
Pass |
So in viewing the above results of table section 2 in x 2.3, 2 x2.4 and 2.5 are suitable for design
Using Wood type Aspen having weight per unit cubic ft is 26.6 lb (12065 g)
E = 1885490 Psi
Deflection due to Load P = 300 lb. = PL3/48EI
=300 x 213/ (48x1885490.59 x 96.6)
= 0.01513 in
L/360 = 21/360 = 0.0583 in
As our Deflection is 0.01513 in, Design is safe against deflection for section B 2 x 2.3, which concludes also that it will also be saved for sections B 2 x 2.4 and B 2 x 2.5 as well
CALCULATION TABLE
|
Beam Configuration on Primary Axis (e.g. Solid Box, Hollow Box, I-Beam, or H-Beam) |
Calculated Mass |
Calculated Volume |
Total Cost of Wood and Glue Joints ($) Rate 30$ /ft3 |
X-Axis Calculations |
Y-Axis Calculations |
||||
|
|
lbm |
g |
ft3 |
in3 |
|
I (in4) |
A (in)* |
I (in4) |
A (in)* |
|
B 2 x2.3 |
1.49 |
675.86 |
0.056 |
96.6 |
1.68 |
2.03 |
4.6 |
2.03 |
4.6 |
|
B 2 x2.4 |
1.55 |
703.08 |
0.058 |
100.8 |
1.75 |
2.3 |
4.8 |
2.3 |
4.8 |
|
B 2 x2.5 |
1.62 |
734.83 |
0.061 |
105 |
1.82 |
2.6 |
5 |
2.6 |
5 |