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1. (TCO 1) The signal is 5 sin (2 pi 2000 t + 60 degrees). The amplitude of this signal is(Points : 5)
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5 VPP
3.535 VPP
3.535 VRMS
3.535 VPK
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Question 2.2. (TCO 1) The signal is 5 sin (2 pi 2000 t + 60 degrees). The frequency of this signal is(Points : 5)
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2000 Hz
1000 Hz
6280 Hz
10 kHz
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Question 3.3. (TCO 1) The signal is 1 sin (2 pi 500 t - 45 degrees). The phase shift of this signal is(Points : 5)
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-60 degrees
+45 degrees
-45 degrees
-90 degrees
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Question 4.4. (TCO 1) The signal is 10 sin (2 pi 1000 t + 30 degrees). The voltage displayed on the DMM is (Points : 5)
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10 V PP
7.07 V PP
7.07 VRMS
10 VPK
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Question 5.5. (TCO 1) Inductive reactance XL is (Points : 5)
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directly related to only frequency.
directly related to only inductance.
directly related to the product of 2 , times the inductance L and frequency f.
No correct answer listed
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Question 6.6. (TCO 2) In an AC circuit with reactance XC in series with a resistor the circuit current(Points : 5)
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leads the applied voltage.
lags the applied voltage.
voltage and the current are in phase.
No correct answer is listed
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Question 7.7. (TCO 2) For the following series AC circuit, the angle of the circuit impedance is
(Points : 5)
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0 degrees
+90 degrees
-45 degrees
+45 degrees
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Question 8.8. (TCO 2) For the following series AC circuit, the phase angle of the circuit current is
(Points : 5)
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0 degrees
+90 degrees
+45 degrees
-45 degrees
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Question 9.9. (TCO 2) For the following series AC circuit, the total circuit impedance is:
(Points : 5)
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200 - j 100
200 + j 100
200 - j 200
200 + j 300
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Question 10.10. (TCO 3) For the parallel AC circuit shown below, find the circuit current IS . Note thatVin AC is mislabeled, it should be 10V, NOT 10 sin(ω t).
(Points : 5)
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0.1 + j 0.1 A
0.1 - j 0.1 A
0.1 A
j 0.1 A
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Question 11.11. (TCO 3) The total admittance for the following circuit is
Hint: YT = G + j (BC - BL) siemens; G = 1/R siemens; BC = C siemens and BL = 1/[ L ] Siemens
(Points : 5)
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0.005 - j 0.015 siemens
0.005 + j 0.015 siemens
0.01 - j 0.005 siemens
0.01 + j 0.005 siemens
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