Precalculus

profilebdadio
precalc.pdf

1. -/1 points

What is the value of In e2? LarATRMRP6 4.4.003.

"? n;c;~cln=:l]f1Rhai-ili(;ldlfjJ

·------------------------------------------------------------------------------------------------------------------------· 2. -/1 points

Can you solve 3x = 27 using a One-to-One Property? 0 Yes

0 No

[r~ ·RiiliinO_ffchal ~

LarATRMRP6 4.4.004.

"------------------------------------------------------------------------------------------------------------------------· 3. -/2 points

Determne whether each x-value is a solution of the equation.

2 3 X + 1 = 128 (a) x = -2

0 Yes, this is a solution.

0 No, this is not a solution.

(b) X= 5

0 Yes, this is a solution.

0 No, this is not a solution.

•.v.ebassign.netMeYStudent/Assignment-Responsesflast?clep=7445672

LarATRMRP6 4.4.008.

1/12

~--------~-------------------------------------------------------------------------------------------------------·

I J

;i points

Fill in the blank.

An -Select- v 1 solution does not satisfy the original equation.

_ . rr·- R.tati'li··- !JJ@citAt~Ga.t!lJ

5. -/1 points

Do you solve log4 x = 2 by using a One-to-One Property or an Inverse Property? 0 Inverse Property

0 One-to-One Property

rr=·"Ri~d"~t=u_Kc=t;.t •. Ui iilJ

6. -/3 points

Determine whether each x-value is a solution of the equation"\

4eX- 1 = 60 (a) x = 1 + In 15

0 Yes, this is a solution.

0 No, this is not a solution.

(b) X~ 3.708

0 Yes, this is a solution.

0 No, this is not a solution.

(c) x =In 16

0 Yes, this is a solution.

0 No, this is not a solution.

rr=·· MUd It . ]_tt . ··w;w. It ... lj ~JcttaiiiiCHit li}j

WNN.v.ebassign.llElt/\wbiStudent/~signment-Responses/last?dep=7445672

LarATRMRP6 4.4.002.

LarATRMRP6 4.4.006.

LarATRMRP6 4.4.010.

2/12

129-4.4 ~--------------------~--------------------------------------------------------------------------------------------·

;3 points LarATRMRP6 4.4.012.

/ Determine whether each x-value is a solution of the equation. /

log 2(; x) = 2 (a) X:::: 2.4800

0 Yes, this is a solution.

0 No, this is not a solution.

(b) X=..!!_ 3

0 Yes, this is a solution.

0 No, this is not a solution.

(c) x = 2.2 0 Yes, this is a solution.

0 No, this is not a solution.

~· [ ..... d It tiJ!ChaliiiGilt-itN

WNN.v.ebassign.net/v>..e:YStudent/Assigrvnent-Responses/last?dep=7445672 3112

129-4.4 I ~-------------------------------------------------------------------------------------------------------------------·

/~/3 points LarATRMRP6 4.4.014. I

/ Detemine whether each x-value is a solution of the equation.

In (2 + x) = 8. 7

(a) x = e8 ·7 - 2

0 Yes, this is a solution.

0 No, this is not a solution.

(b) X~ 600091/100

0 Yes, this is a solution.

0 No, this is not a solution.

(c) x = 1/2 0 Yes, this is a solution.

0 No, this is not a solution.

------] l r ') 1r·· R8acfit A !fct.atibOufti[

WNN.v.ebassign.net/v.eb'Student/Assigi'YTIElllt-ResponsesJiast?dep=7445672 4/12

I 1~-4A ·-------------------------------------------------------------------------------------------------------------------·

-/2 points LarATRMRP6 4.4.016.Ml.

Approximate the point of intersection of the graphs off and g. Then solve the equation f(x) = g(x) algebraically to verify your approximation.

f(x) = 125x g(x) = 625

ex, v) = c I I , I I >

eoo

g •300

y

400

200

0 ~------,----1~5----2 --- "i:S 3 )(

L , ~ lf -~" --. ji_U wltch}L]IC...._• -~ ficl;rM;di11

10.-/2 points LarATRMRP6 4.4.018.

Use a graphing utility to graph f and g in the same viewing window.

f(x) = 3-x + 1 - 4 g(x) = 77

Approximate the point of intersection of the graphs off and g. (Round your answers to three decimal

places).

(x, y) = ( )

Solve the equation f(x) = g(x) algebraically.

x=l I

i(=~c~~:=·llliCi*-... ftll ~~L2-'·., r"

WNN.v.ebassign.netlv.eb'Student/~signment-Responses/last?dep=7445672 5112

129-4.4 ~-------------------------------------------------------------------------------------------------------------------·

,~-11 points I

Solve the exponential equation.

5x = 3125 X= I I

He 1 lr-·FiltaCI D_Rciiit .MOUi.tt}f

12.-/1 points

Solve the exponential equation.

1 gx = 729

X= I I

lr Aud It ij_ltchit Allout •Ill

13.-/1 points

Solve the exponential equation.

(1/6)x = 1296 x= I I

r·~peu I tr--·Riiad-lt -:-BJfchaiAaiOUtiill

14.-/1 points

Solve the exponential equation.

(..±.)X = ..!.§_ 5 25 x= I I

H I p 11 . AudIt tUlCJ.t Allout ttlJ

WMN.It\00assign.netf\t.d:l/Student/Assignment-Responsesllast?clep=7445672

LarATRMRP6 4.4.024.

LarATRMRP6 4.4.026.

LarATRMRP6 4.4.028.

LarATRMRP6 4.4.030.

6/12

129-4.4

;.-/1 points I

J Solve the exponential equation. (Round your answer to three decimal places.) ex= 54

X= I I

N ih_; t r~~~-] [J---~-··1 ru~---r .....,. r_~"'*"•J~Ct.t~E

16.-/1 points

Solve the exponential equation.

3x- 1 = _1_ 27

X ::: r-1 ------.~

(.' » ·c·--c~~- c·crl [jQaiM;datjJ ~ . ' . ' ,._ ' . t. t .;

p

17.-/1 points

Solve the logarithmic equation.

In x = -17

x==

He P lr···rt;aci-ii -H fiCild-AI.o..tf~l!

18.-/1 points

Solve the logarithmic equation.

logx 64 = 3 x= I I

He I i) w-~R.ai!CJ_~ctiaf Al.ol.tJill

WNN.v.ebassign.netlv.eb'Studeni/Assignment-Responsesllast?dep=7445672

LarATRMRP6 4.4.032.

LarATRMRP6 4.4.036.

LarATRMRP6 4.4.040.

LarATRMRP6 4.4.042.

7/12

j

129-4.4 ·-------------------------------------------------------------------------------------------------------------------·

l-/1 points

Solve the logarithmic equation. (Round your answer to three decimal places.)

ln(6x + 3) = 4 X= I I

f-~--,-----cc--·a r~. -... -;-··-. --::·-c:--.:ti ,;:! / 1 · Reldu . _i.C!*.~•·rj

LarATRMRP6 4.4.046.

·------------------------------------------------------------------------------------------------------------------------· 20.-/1 points LarATRMRP6 4.4.050.

Sirl"plify the expression.

t.ln( !'" 1 \ :•

: ~ .. ,. ~ :- [-=ccr;;alt!lu~•o " ; . dJ_ ;H - . - t '

21.-/1 points LarATRMRP6 4.4.052.

Sifllllify the expression.

~-I + ,_.lu r

1 ' 11. ---AUdia-- tljfchai-N.Outl•ll

22.-/1 points LarATRMRP6 4.4.056.MI.

Solve the exponential equation algebraically. Approximate the result to three decimal places. (If there is

no solution, enter NO SOLUTION.)

64 x = 2000

x= I I

He! lr-a.;dit'·-ll f:l Wlddltt lllf iiast~~ri-]1 &chal·:u.o.,tutl

WJIW.v.ebassig n.netlweb'Student/Assignment-Responsesllast?dep= 7 445672 8112

129-4.4 --------------------------------------------------------------------------------------------------------------------·

J.-/1 points LarATRMRP6 4.4.062.

Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing

utility to verify your answer.

1100e- 2x = 75 x=l I

II RMd It -Jl [@f;t AbOut i!] I

24.-/1 points LarATRMRP6 4.4.066.

Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing

utility to verify your answer.

12(2 - l-x) + 11 == 2501

X= I I

:J 1r· ..ue~ ••. · I]Jc~U~t AIKnd ••l'l

25.-/1 points LarATRMRP6 4.4.070.

Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing

utility to verify your answer.

(1 + 0.04)X == 250,000 30Q...:._ __ _ 0.04

X== I I

H i 0 ; IQ;---:d1•:lf&tiit AliOut lti:l

26.-/1 points LarATRMRP6 4.4.078.

Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing

utility to verify your answer.

47"5 = 325

x= I I

W ·· Ra'atiKJl !fch.tiiiOirt@

.NNN.vvebassign.l'1et/'Mb'StudenUAssigiYJlellt-Responsesllast?dep=7445672 9112

_!

129-4.4

I

/1.-11 points I

LarATRMRP6 4.4.090.

Use a graphing utility to graph the function and approximate its zero accurate to three decimal places.

h(t) = e0.140t _ 6 t =I I

.d t:p If RNcln ]_[~~]

28.-/1 points LarATRMRP6 4.4.098.

Solve the logarithmic equation algebraically. Round the result to three decimal places. Verify your

answer using a graphing utility. (Enter your answers as a conTT'la-separated list. If there is no solution,

enter NO SOLUTION.)

3 + 41n x = 12

x=

el H _· -.... dlt - tj_KCh.t*.~t•1l

·------------------------------------------------------------------------------------------------------------------------· 29.-/1 points LarATRMRP6 4.4.110.MI.

Solve the logarithmc equation algebraically. Approximate the result to three decimal places. (If there is

no solution, enter NO SOLUTION.)

ln(x + 3) - ln{x - 3) = ln{x) ..--, ----.,

~, p') [. RUCi·,.·]j f[·Mits.-rit···fj f!C:~.AbO.Itllfl

-.v.ebassig n.netMebiStudent/Assignment-Responses/last?dep= 7445672 10112

129-4. ·---------------------------------------------------------------------------------------------------------------~

. -/8 points LarATRMRP6 4.4.118 .

Consider the following.

, ..

5 log10(x- 6) = 11

(a) Coll'l>lete the table to find an interval containing the solution of the equation. Round your

results to three decimal places.

I X

II 150

I II 155

I II 160

I II 165

I II 170

5 loglo(x- 6)

What is the smallest open interval based on the table above that contains the solution of the

equation? (Use the x-values given by the table.)

(b) Use a graphing utility to graph both sides of the equation to estimate the solution. Round your result to three decimal places.

}f = I I

Cc) Solve the eauation algebraically. Round your result to three decimal places. X= I I

}) I lrcc Rlt;d'lt:J_[~~!j]

·------------------------------------------------------------------------------------------------------------------------· 31.-/1 points

LarATRMRP6 4.4.130.

Use a graphing utility to approximate the point of intersection of the graphs. Round your result to three decimal places.

Y1 = 1.07

I ,-Y2 = n y X- 7

(x, y) = ( )

L~iiJJ_~~till

w.v.v.v.OOassig n.net/webiStuden!JAssignment- Responses/last?dep= 7445672

11/12

.I

129-4.4

/ ,-/1 points LarATRMRP6 4.4.136.

So\ve the equation algebraically. Round the result to three decimal places. Verify your answer using a

graphing utility.

3 -In X = O x2

x=

lr -,_cfitJ !Jct.t Atlout itll

_.,;.

WNN.'Mlbassig n.l"'etti..Eb/Student/Assig nment-Responsesllast?dep= 7445672 12112