For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. A random sample of 5913 physicians in Colorado showed that 3035 provided at least some charity care (i.e., treated poor people at no cost).
(a) Let p represent the proportion of all Colorado physicians who provide some charity care. Find a point estimate for p. (Round your answer to four decimal places.)(b) Find a 99% confidence interval for p. (Round your answers to three decimal places.)
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Give a brief explanation of the meaning of your answer in the context of this problem.
1% of all confidence intervals would include the true proportion of Colorado physicians providing at least some charity care.
99% of the confidence intervals created using this method would include the true proportion of Colorado physicians providing at least some charity care.
1% of the confidence intervals created using this method would include the true proportion of Colorado physicians providing at least some charity care.
99% of all confidence intervals would include the true proportion of Colorado physicians providing at least some charity care.(c) Is the normal approximation to the binomial justified in this problem? Explain.
6 years ago
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