Prove that for all real numbers a and b, at least one of which is not 0, a^2 + ab + b^2 > 0. ...
guru2009 (Not rated)
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Prove that for all real numbers a and b, at least one of which is not 0,
a^2 + ab + b^2 > 0.
8 years ago
We need to show that a^2 + ab + b^2 > ab That is, a^2 + b^2 + 2ab - ab > 0 ...
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Provethatforallrealnumbersaandbatleastoneofwhichisnot0.doc
