Normal Distribution
NOTE: THE CURVES AND AREAS THAT FOLLOW ARE NOT DRAWN TO SCALE
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Problem
Notes
POINT VALUE
YOUR ANSWER(S)
1
DELETED
2
In figure b-2, if the right tail = 16.6%, how much area
(probability) is in the non-tail ?
4 place decimal
Like 0.2563
B-2
3
3
DELETED
4
In figure b-2, if the large area (probability) = 77.1%, how much area is in the right tail ?
2 place %
3
5
DELETED
6
If a z score is found to be 0.78, what is the resulting probability (AREA) TO THE LEFT OF THE Z SCORE ?
4 place decimal
Like 0.7563
3
7
If a probability or area is found to be 0.7190, what is the z score ?
2 place decimal like 0.77 or 1.35
3
8
If a probability or area is found to be 0.3399, what is the z score ?
2 place decimal like 0.77 or - 1.09
3
9
If a probability or area is found to be 0.7370, what is the z score ? USE THE FIGURE FOR #7 ABOVE
2 place decimal like 0.77 or 2.59
3
10
If a z score is found to be -2.56 , what is the resulting probability ? USE THE FIGURE FOR #8
4 place decimal
Like 0.2563
3
11
If a z score is found to be – 1.0 , what is the resulting probability ?
4 place decimal
Like 0.2563
USE THE FIGURE FOR # 8
3
12
If a probability or area is found to be 0.0283, what is the z score ?
2 place decimal like 0.77
USE FIGURE FOR #8
3
13
If a probability or area is found to be 0.5697, what is the z score ?
2 place decimal like 0.77
USE #7 FIGURE
3
PART 2
#
Problem
Notes
POINT VALUE
YOUR ANSWER(S)
1
Find the area ( probability ) to the left of a z score of 2.16
Round to 4 decimal places or a % to 2 decimal places
2.16
3
2
Find the area ( probability ) to the right of a z score of -1.90
Round to 4 decimal places or a % to 2 decimal places - figure not drawn to scale
3
3
Find the area ( probability ) in a right tail where the z score is 1.59
Round to 4 decimal places or a % to 2 decimal places - draw your own figure if necessary
4
Find the area of the shaded region between the z scores
Round to 4 decimal places
-2.32 1.09
5
If the area of the shaded region is 31.05% or .3105, find the z score at the question mark.
Round to 2 decimal places
3
6
Find the z score if the NON-shaded region indicated by the arrow is .0293
Round to 4 decimal places
3
7
When a bell curve is shaded from a
z score of ZERO (0) all the way to positive infinity, what is the area (probability) covered ?
3
8
Find the z score if the area of the shaded region is .7172
Round to 2 decimal places
3
9
Find the z score if the area of the shaded region is .0298
Round to 2 decimal places
3
PART 3
10.
NOTE: THE ANSWER IS NOT A ZSCORE—IT IS A %
THIS IS A BELL CURVE PROBLEM
This is a typical bag of broken pretzels—the pretzels are purposely broken to provide a surface for various flavor coatings. It is found that the average number of pieces (after whole pretzels are broken) is 301.68 pieces with a stdev of 32.8 pieces. If a random bag is selected, find the probability that the bag will contain less than 265 broken pieces.
ROUND TO 2 DECIMAL PLACES
5
11.
The answer is a value—not a probability.
The garbage service truck is known to wake us early in the morning. This company’s truck is almost always on time---the average difference in their times is 13.26 minutes with a stdev = 8.22 minutes. The company requires the crews to be 97.22% efficient—meaning that any time below the 97.22% cutoff will result in a warning for driver and crew. Find the lowest value that will not result in a warning—I am looking for the cutoff score. Round to 2 decimal places.
THIS IS A BELL CURVE CUTOFF SCORE PROBLEM
5
12.
This is a tank less water heater; it has advantages and some disadvantages. Theoretically, a tankless water heater will provide your home with a limitless supply of hot water with next to no warmup time. For this problem, the average tankless takes 7.24 minutes to heat water with a stdev = 1.03 minutes ( depending on several factors). Find the probability that a randomly selected tankless will take BETWEEN 5.98 minutes and 8.09 minutes to heat up.
Leave answer at 2 decimal places.
5
13.
Your parents and/or grandparents may have told you about their old television set ( “we only had 3 channels and the set had to warm-up”). It has been researched and reported that these old tvs took an average of 15.6 seconds to warm up with a stdev= 6.08 seconds. If a sample of 16 old tvs is selected at random, find the probability that it will take MORE than 13.07 seconds to warm up. Answer to 2 decimal places
And we didn’t have remotes either !
5
CHAOTER 7 PROBLEMS
SHARKS
5 POINTS
DOLLS
5 POINTS
Bonus problem: Not covered by the instructor
#
Problem
Notes
POINT VALUE
YOUR ANSWER(S)
Bonus
The average size of a rhododendron tree is 19.4 feet; if 20.5% of all rhododendrons are higher than 22.79 feet, find the stdev. Round answer to 2 decimal places.
7 years ago
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- StatsND.docx