engineering

Consider applying the simple electronic polarizability and Clasius-Mossotti equations to diamond.

Neglecting losses,

α

ω ω e

e o

Ze

m

=

−

2

( 2 2 )

and ε

ε ε ω ω

r

r o e o

NZe

m

−

+

=

−

1

2 3

2

( 2 2 )

Dispersion in diamond

For diamond we can take Z = 4 (valence electrons only as these are the most responsive),

N = 1.8 × 1029 atoms m-3, εr(DC) = 5.7. Find ωo and then find the refractive index at λ = 0.5 μm and

5 μm.