A newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers ...

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     A newspaper selected a simple random sample   of 1,600 readers from their list of 100,000 subscribers. They asked whether   the paper should increase its coverage of local news. Forty percent of the   sample wanted more local news. What is the 99% confidence interval for the   proportion of readers who would like more coverage of local news?    

    • 8 years ago
    Standard Error, SE = √{p(1 - p)/n} = ...
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      Anewspaperselectedasimplerandomsample.xls