A manufacturing process drills holes in sheet metal that are supposed to be .5000 cm in diameter ...
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A manufacturing process drills holes in sheet metal that are supposed to be .5000 cm in diameter. Before and after a new drill press is installed, the hole diameter is carefully measured (in cm) for 12 randomly chosen parts. At α = .05, do these independent random samples prove that the new process has smaller variance? Show the hypotheses, decision rule, and test statistic. Old drill: 0.5052 0.5053 0.4947 0.4907 0.5031 0.4923 0.54 0.5035 0.5601 0.4956 0.5035 0.4962 New drill: 0.5005 0.501 0.5024 0.4988 0.4997 0.4995 0.4976 0.5402 0.5104 0.4995 0.4898 0.4992
8 years ago
Ho: The variance in the hole diameters is the same for both the processes, that is σ1^2 = σ2^2 or σ1^2 - σ2^2 = 0 ...
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- a2.xlsx