1 / 6100%
hlt
)
17
73.5
15.61
5.
61
6.
67
8.
56
2.
56
f(
19403=2861
1.16
0.93
g
/
18907=2
hll
880
)
=
¥
=
fgff%÷
,
=
17
The
#
of
Phd
's
awarded
to
men
was
17
times
as
large
as
the
#
of
h
/
1890
)
=
73.5
phd
's
awarded
to
women
h(
19003
=
15.61
-
-
-
20
-
'
so
'aoÉ
'
to
do
to
Jo
IoT
#
of
Phd
's
<
#
of
Phd
's
Men
Women
No
,
a
negative
#
of
Phd
's
does
not
possible
.
Fi
i
as
-
1
9
2000
-
2
20
-
zo
/
"
°
/
,
-
200
12
-
2000
o
-
"
approaches
1
'
2-
Ot
4.
St
to
-
-
5-
-
zt
0
21=8
-
I
1000
-
2
100
-
10
10
-
100
-
1000
}
8-
g-
(
×
,
is
deer
w/o
bound
8
+
f-
(
x
)
incr
w/o
bound
coeff
:
Real
#
powers
:
whole
+#
's
All
values
of
such
The
values
of
that
rcx
)=o
.
Such
that
pcx
)
--
0
.
negative
and
negative
&
positive
and
constant
increasing
increasing
hc
-
2)
=
P)
=
¥
undefined
re
-
2)
negative
&
positive
and
negative
and
constant
increasing
increasing
no
)=P
=
-
¥
V.
A
.
@
=
-2
since
pcx
)
is
negative
&
constant
,
and
the
value
of
rcx
)
is
1
positive
and
increasing
from
1
=o
to
71=5
,
then
hcx
)
I
will
be
negative
and
approach
]
"
0
.
I
we
can
sketch
the
,
-
-2
graph
based
on
the
answers
,
-
from
parts
(a)
ii.
(b)
,
&
(e)
.
!
=
:¥.*
V.
A
.
@
=
-1
V.
A
.
@
X=4
V.
A
.
@
=3
,
-1
=
+3
V.
A.
do
not
=
-
he
is
(
+
g)
(
x
-
1)
exist
since
not
a
vertical
2+1=0
only
asymptote
,
but
instead
v.
A-
@
=
-5,1
when
=
if
__
i.
is
called
a
hole
.
t
A
hole
exists
on
thegraph
of
a
rational
function
at
any
input
value
that
causes
both
the
numerator
and
denominator
to
be
equal
to
zero
.
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