decision analysis
When simple alternatives to Bayes formula work well: Reducing the cognitive
load when updating probability forecasts
Paul Goodwin
23 June 2014
The Management School, University of Bath, Bath, BA2 7AY,United Kingdom
Email: [email protected].
Acknowledgements
Kesten Green, Scott Armstrong, Konstantinos Katsikopoulos and two anonymous
reviewers provided helpful comments enabling the author to make improvements to
the paper. Gerd Gigerenzer provided very useful suggestions for improving the
section on natural frequencies.
The author confirms that he has read each of the original studies cited. Where there
was any doubt as to the interpretation of a cited paper he attempted to contact the
authors to confirm the interpretation and to ascertain whether any other publications
should be cited.
2
When simple alternatives to Bayes formula work well: Reducing the cognitive
load when updating probability forecasts
Abstract
Bayes theorem is the normative method for revising probability forecasts when
new information is received. However, for unaided forecasters its application can be
difficult, effortful, opaque and even counter-intuitive. Two simple heuristics are
proposed for approximating Bayes formula while yielding accurate decisions. Their
performance was assessed: i) where a decision is made on which of two events is
most probable and ii) where a choice is made between an option yielding an
intermediate utility for certain or a gamble which will result in either a worse or better
utility (‘certainty or risk’ decisions). For ‘most probable event’ decisions the first
heuristic always results in the correct decision when the reliability of the new
information does not depend on which event will occur. In other cases the second
heuristic typically led to the correct decision for about 95% of ‘most probable event’
decisions and 86% of ‘certainty or risk’ decisions.
Keywords: Bayes theorem, forecasting, heuristics, probability estimation
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When simple alternatives to Bayes formula work well: Reducing the cognitive
load when updating probability forecasts
1.1 Introduction
Forecasts are often expressed as probabilities and, when new information is
received, Bayes theorem provides the normative way of revising these prior
probabilities. For example, economic forecasters may revise their subjective
probabilities of a recession upwards if an economic leading indicator suggests that a
decline in growth is on the horizon (Schnader and Stekler 1998). Similarly, estimates
of the probability of success of a potential new product may be revised upwards when
encouraging market research results become available. Many situations involve
estimating probabilities for two mutually exclusive and exhaustive events, A and A
(e.g., recession or no recession or rain or no rain). In this case Bayes theorem can be
stated as:
P(A|N) = Po(A) x P(N|A) (1)
Po(A) x P(N|A) + (1-Po(A)) x P(N| A )
Where: Po(A) is the prior probability of event A
P(A|N) is the posterior probability of A
A is the event which is complementary to A
N = the new information
P(N|A) is the likelihood of the new information, or the probability of getting
the new information given that A will occur
4
Where p(N|A) = 1 –p(N| A ) the new information will be referred to as a
‘symmetric indicator’. For example, suppose that a test will indicate whether a
manufactured component is defective or non-defective. If it has the same probability
of giving a correct indication irrespective of whether or not a component is defective
then it will provide a symmetric indication of the component’s condition. If this
condition does not apply then the new information is an ‘asymmetric indicator’.
Applying Bayes theorem can pose difficulties for unaided forecasters. The
cognitive effort involved in using the formula may make it unacceptable when a quick
decision needs to be made or when a calculator is unavailable. To those unfamiliar
with probability theory the formula may lack transparency and hence there may be a
distrust of the posterior probability produced by it. For example, suggestions that
jurors should use Bayes theorem to determine the probability of a defendant’s guilt
have never been widely implemented because of the difficulties involved in getting
people to apply it, or accept it, even when they are provided with a structured format
(Balding 1997). There is also plenty of evidence that, in many circumstances, people
do not naturally revise probabilities according to Bayes theorem.
These factors suggest that it may be worth trying to develop simple, but reliable,
approximations to Bayes theorem, which people could be encouraged to employ when
use of the exact formula is impractical. This paper therefore addresses two questions.
1. Is it possible to identify simple and intuitively appealing heuristics that will
approximate Bayes theorem and lead to the same decisions in a wide range of
circumstances?
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2. Under what conditions, if any, would the use of these heuristics lead to serious
errors?
2.1 Background
Some researchers have assumed in their models of human prediction and decision
making that people revise their prior beliefs according to (1) (e.g., Schnader and
Stekler 1998). However, a substantial body of research has found that in many
circumstances this is not the case. A predominant finding of the literature of the 1960s
was that people are conservative in that they insufficiently revise their prior
probabilities when they receive diagnostic new information when compared to the
revisions prescribed by the theorem (e.g., Phillips and Edwards 1966; Phillips et al.
1966; Edwards 1968). Later work has suggested the opposite in that people
underweight prior probabilities and make their judgment primarily on how
representative the new information appears to be of either A or A (Grether 1992;
Mahmoud and Grether 1995; Charness, Karni and Levin, 2007; Holt and Smith 2009).
The difference between these findings may, in part, reflect whether the prior
probabilities were estimated by the forecaster themselves or whether they were
supplied to them (other factors, like incentives for accurate judgment, may also have
played a role). A self-estimated prior probability would be likely to carry greater
salience and hence greater weight in the revision process than a supplied probability
(e.g. Phillips and Edwards 1966; Evans, Handley and Over 2002). Indeed, it may act
as an anchor in an “anchor and adjustment” process (Tversky and Kahneman 1974).
Recent research by Goodwin et al. (2013) suggests a simple model can represent
people’s revisions to their own prior probabilities. This model is a weighted average
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of the prior probability and the likelihood associated with the new information when
A occurs:
P(A|N) = 0.66 Po(A) + 0.41 P(N|A) (2)
In all cases examined by Goodwin et al. (2013) the new information was a symmetric
indicator. The estimated weights of 0.66 and 0.41 were obtain by applying
generalized estimating equations to the prior and posterior probability estimates of 54
participants in an experiment. Each participant judged the probability of a recession in
nine scenarios both before and after receiving information from an economic
indicator.
Barbey and Sloman (2007) discuss a number of theoretical accounts of how
Bayesian estimation can be facilitated. There is strong evidence that people are likely
to revise their prior probabilities more accurately when information is presented in a
natural frequency, rather than a probability, format (Gigerenzer and Hoffrage 1995;
Cosmides and Tooby 1996; Koehler 1996; Gigerenzer, Gaissmaier, Kurz-Milcke,
Schwartz and Woloshin 2007). Goodwin and Wright (1991) demonstrated this
method and it was discussed by Kleiter (1992). Gigerenzer (2011) defines a natural
frequency as a joint frequency of two events. For example, it could be the number of
components manufactured in a factory that are both defective and have been found to
be defective in a quality control test that is not perfectly reliable. Figure 1 shows how
1000 typical components could lead to four natural frequencies depending on whether
or not they are defective and whether or not they have failed the test (the natural
frequencies are at the bottom of the tree). The probability that a component is
defective, given that it has failed the test, can be easily determined from the diagram.
Of the 140 components that failed the test, 110 are defective. Hence the required
probability is simply calculated as 110/140 = 78.6%.
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Figure 1 here
Why do natural frequencies make Bayesian revision easier? One theory is that
humans have evolved a component of their brain that efficiently processes natural
frequency information (Gigerenzer 2000) (Chapter 4). The frequency with which
events are experienced has been the natural way in which humans (and even animals)
have obtained information on the risks they face throughout their evolution, while the
use of probabilities is relatively recent (Gigerenzer 2002). In addition, the natural
frequency format may allow decision makers to have an accurate perception of the set
structure underlying the necessary calculation (see Evans, Handley, Perham, Over and
Thompson 2000; Barbey and Sloman 2007). The use of Euler diagrams to represent
the set structure has also been found to aid Bayesian inference (Sloman, Over, Slovak
and Stibel 2003).
However, in some circumstances in may be difficult or unnatural to conceive the
problem in terms of a large population of repeated similar events. For example,
consider the task of estimating the probability that an innovative new product will
make a profit, given that market research has indicated that it will, or the probability
that a specific construction project will be delayed given that geological tests have
indicated problems with the local rock structure. On other occasions decision makers
may not have the time, commitment or even the need to estimate perfectly accurate
Bayesian posterior probabilities, particularly as decision problems often have a wide
degree of tolerance to errors in the underlying probability estimates (von Winterfeldt
and Edwards 1986). Also, the importance of getting the decision right may not be
regarded as crucial, so the need to avoid an erroneous choice does not justify the
effort required to estimate correct probabilities (Payne, Bettman and Johnson 1993).
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Indeed, in some circumstances where judgments are applied to decisions greater effort
may even lead to less accurate judgments (e.g., see Katsikopoulos (2011) for a
review). All of this suggests that there may be a useful role for heuristics that can
handle information in the form of probabilities and yet be cognitively less demanding
than Bayes formula. Ideally, the heuristics should be intuitively reasonable and carry
an acceptably low risk of yielding the wrong decision.
When the heuristic (2) reported in Goodwin, et al. (2013) was applied to a range of
decisions, discrepancies between decisions based on probabilities revised according to
Bayes theorem and those based on the heuristic were relatively rare. Moreover, when
they occurred they were generally inconsequential in that the differences between the
expected utilities of the decision based on Bayes theorem and those of the discrepant
decision were small. This finding raises the possibility of being able to recommend to
decision makers a simple rule or rules that will accord with their natural way of
thinking and will give them a high probability of making a correct decision. This
possibility is explored next in the context of two types of decision.
2.1 Deciding which event is most probable
On many occasions people have to decide which of two mutually exclusive and
exhaustive events is most likely to occur. Is it more probable that the price of a stock
will rise rather than fall over the next month? Is economic growth over the next three
years more probable than a decline in GDP? Is a default by a debtor more probable
than no default? Is it more probable that tomorrow will be a rain-free day or a day
when some precipitation will occur?
This choice is shown in the simple decision tree in figure 2 where a forecast of A,
F(A), would be chosen if event A is most probable and a forecast of A (i.e., F( A ) )
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would be chosen otherwise. The probability of A is w and the 0’s and 1’s are the
decision maker’s utilities for the worst and best outcomes respectively (assume that
utilities are measured on a 0 to 1 scale throughout this paper). These utilities assume
that correctly forecasting the event is equally good irrespective of which option is
chosen. For example, it assumes that the forecaster will be just as satisfied with a
correct forecast of rain and a correct forecast of fine weather. Similarly, choosing the
wrong option is assumed to be equally bad, irrespective of which event actually
occurs. When new information is received let w = pB if the Bayesian posterior
probability is used to make the decision and w = pE if the decision maker’s estimate of
the posterior probability is used. The decision will differ only if pE >0.5 when pB
<0.5 or when pE <0.5 when pB >0.5, that is when the decision maker’s probability and
the Bayesian posterior probability are on ‘opposite’ sides of 0.5.
Figure 2 here
When the decisions do differ how serious will this be? Expected utility loss is the
expected loss in the decision maker’s satisfaction caused by the discrepancy. It is the
difference between the expected utility of the best option and the option selected, with
both expected utilities calculated using the correct Bayes posteriors. For ‘most
probable event’ decisions it is |2pB -1| . This is because if F(A) is the correct decision
then the expected utility is pB. An incorrect choice of F( A ) would yield an expected
utility of 1- pB so the difference (or utility loss) is pB-(1-pB) = 2pB-1. When F( A ) is
the correct choice the utility loss is 1-2pB.
2.1.1 Symmetric indicator
Consider first situations where the new information is a symmetric indicator. The
model in (2) suggests a very simple heuristic: Take the Average:
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P(A|N) = 0.5 Po(A) + 0.5 P(N|A) (3)
Here the revised probability is just the mean of the prior probability and the likelihood
associated with the event in question. If the result exceeds 0.5 then A is considered to
be the most probable event. For example, suppose that a forecaster estimates the prior
probability of a recession in the next year, Po(A) to be 0.2. An economic forecast is
then published which predicts that there will be a recession in the next year. Suppose
also that the probability of the forecast predicting a recession given that there will be
a recession, P(N|A), is 0.7. The simple heuristic yields an estimated posterior
probability of a recession of 0.45. Since this probability is less than 0.5, a person
using the heuristic would conclude that “no recession” is the more probable event. If
the economic forecast is a symmetric indicator, Bayes theorem yields a posterior
probability of 0.37 so a person using the theorem would agree that “no recession” is
more probable.
How well would Take the Average work in general when applied to a ‘most
probable event’ decision and when the indication is symmetric? In fact, it would give
the same decision as Bayes theorem 100% of the time, as shown below. When the
posterior probability P(A|N) is greater than 0.5, according to Bayes theorem:
Po(A) P(N|A) > 0.5 (4)
Po(A) P(N|A) + [1-Po(A)][1- P(N|A)]
So: 2 Po(A) P(N|A) > Po(A) P(N|A) + [1-Po(A)] [1- P(N|A)] (5)
This expression simplifies to:
Po(A) + P(N|A) > 1 or 0.5 Po(A) + 0.5 P(N|A) > 0.5 (6)
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2.1.2 Asymmetric indicator
Take the Average cannot be guaranteed to yield the correct decision when an
indicator is asymmetric. This is because it is ignoring the value of P(N| A ) so it would
give the same result irrespective of what this likelihood is. For example, consider the
forecasting problem referred to above, where the prior probability of a recession is
0.2. Suppose that the economic forecast has a 0.7 probability of forecasting a
recession when there will be a recession, but only a 0.05 probability of forecasting a
recession when “no recession” will occur so that P(N|A) = 0.7 but P(N| A ) = 0.05.
The heuristic’s posterior probability of 0.45 will be on the ‘opposite side’ of 0.5 when
compared to the Bayes posterior of 0.78.
In this case is it possible to derive an alternative heuristic which takes into account
all of the information? When an indicator is asymmetric a perfectly correct decision
can be guaranteed if the following procedure is followed.
1. Divide P(N| A ) by the sum of the likelihoods
2. Choose A as being most probable only if the prior probability Po(A) exceeds this
ratio.
In the last version of the recession forecasting problem this procedure would result
in 0.05/0.75 = 0.07. Hence a recession would be considered to be the most probable
event as Po(A) = 0.2 so the decision would agree with that based on Bayes formula.
This works because, when the posterior probability, P(A|N), exceeds 0.5.
Po(A) P(N|A) > [1-Po(A)] P(N| A ) (7)
so: Po(A) > P(N| A )/[ P(N|A) + P(N| A )] (8)
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Although these steps are guaranteed to give the correct decision and involve less
effort that the application of the Bayes formula they may still be too complex for an
unaided decision maker. If this is the case a simpler heuristic, Sum the Pros, Sum the
Cons, will often give good approximate results as shown below.
Note that the left hand side of the inequality in (4) is the product of the
probabilities ‘favouring’ A. For example the second term is the probability of
obtaining the new information if A will occur. The right hand side is the product of
the probabilities ‘disfavouring’ A. The comparison in (4) will be easier if sums
replace the products, that is if the sum of ‘favouring’ probabilities (the ‘pros’) exceed
the ‘disfavouring’ probabilities (the ‘cons’). This approximation should work well
because if:
a.b>(1-a)c
it is likely that a +b >(1-a) + c when 0< a,b,c < 1.0.
Indeed this proved to be the case in over 96% of cases when it was tested over all
combinations of a, b and c with the values varying in steps of 0.01 (Similarly when
a +b >(1-a) + c then a.b>(1-a)c in over 94% of cases). Thus the Sum the Pros, Sum
the Cons heuristic is: assume A is more probable than A if :
Po(A) + P(N|A) > [1-Po(A)] + P(N| A )] (9)
For the last version of the recession forecasting example the left hand side is 0.9
(0.2+0.7) and a right hand side of 0.85 (0.8 + 0.05) so the heuristic agrees with the
Bayes posterior that a recession is more probable than no recession. It can be seen
that Sum the Pros, Sum the Cons is a generalisation of Take the Average as, if the
indication from the new information is symmetric, the sum of all four probabilities in
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(6) will be two so the left hand side will have an average exceeding 0.5 when A is the
more probable event.
Sum the Pros, Sum the Cons was tested for ‘most probable event’ decisions across
the following ranges of values (these will be referred to as the test set for most
probable event decisions):
prior probabilities, Po(A), from 0 to 1 in steps of 0.01
values of P(N|A) from 0.01 to 0.99 in steps of 0.01
values of P(N| A ) from 0.01 and 0.99 in steps of 0.01.
Figure 3 shows the percentage of times the heuristic led to a discrepancy with
decisions based on Bayes for different prior probabilities.
Figure 3 here
The heuristic performed at its worst if the prior probability is 0.3 or 0.7, when
about 8.5% of decisions were discrepant (i.e., about 91.5% of decisions were still
correct). Overall, only 5.5% of decisions differed from those based on Bayes theorem
(i.e., 94.5% agreed). Note that the disagreements are minimised when the prior
probability is at the extremes or close to 0.5. Extreme priors will tend to lead to
posterior probabilities which are either well below or well above 0.5 using both
Bayes formula and the heuristic so there will usually be no disagreement between the
two on which is the most probably event. If the prior probability for event A is 0.5
then, according to Bayes rule, A will be more probable than A if P(N|A) >P(N| A ).
Under these circumstances, Sum the Pros, Sum the Cons is always bound to agree
with Bayes rule because it would indicate that A is more probable if 0.5 + P(N|A) >
0.5 + P(N| A ) which will only be true if P(N|A) >P(N| A ).
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These results suggest that the risk of wrongly identifying the most probable event
when using this heuristic is low. But how serious are the discrepancies? When
discrepancies occurred the expected utility loss was, on average, 0.21 indicating that
typically the loss of satisfaction by the decision maker was 21% of the difference
between the utilities of the worst and best possible outcomes. However, given that
discrepancies were rare, over all decisions the expected utility loss was only 0.01.
2.2 Choosing between a certain or risky alternative
Figure 4 displays a decision tree for a second commonly encountered type of
decision problem. Here the decision maker has to choose between a ‘risk free’ option
and a gamble which will result in either a worse or better outcome than the risk free
option. Specifically the decision involves two alternative courses of action D1 and D2.
Alternative D1 can result in two outcomes A and A . The utilities that can be obtained
are shown at the ends of the branches and range from 0 (the worst outcome) to 1 the
best with 0<U<1. Note that D2 always leads to a utility of U. The probability of the
best outcome, A , is x.
Figure 4 here
If the decision maker receives new information relating to the probability of
outcome A then let x = pB if the Bayesian posterior probability is used to make the
decision and x = pE if the decision maker’s estimate of the posterior probability is
used. According to the axioms of utility theory (e.g., see Goodwin and Wright
(2014)) the decision maker will be indifferent between D1 and D2 when U = x.
Discrepant decisions will therefore be made if: pE > U when pB < U or vice versa,
that is when pE and pB are on ‘opposite sides’ of U. The expected utility loss of a
discrepant decision will be the difference between expected utilities of the correct and
15
incorrect decisions based on the Bayes probabilities, that is: |U - pB|. For example, if
D1 is the correct decision and D2 is chosen then the utility loss will be: 1.pB +0.(1- pB)
–U = pB –U.
2.2.1 Symmetric indicator
The performance of Take the Average was tested on ‘certainty or risk’ decisions
when the indication from the new information was symmetric. This testing was done
for all combinations of values of Po(A) and p(N|A) from 0.01 to 0.99 in steps of 0.01
when U =0.1, 0.3, 0.5, 0.7 and 0.9. The estimate of the posterior probability was
simply: 0.5 [(Po(A) + p(N|A) ]. Over all values the heuristic yielded a decision that
agreed with the one based on Bayes theorem on 86.3% of occasions (see figure 5) and
the mean expected utility loss was only 0.008. When U =0.5 there was 100%
agreement between the Bayes decision and the heuristic. Less than 70% agreement
occurred where both U and Po(A) were low (e.g., U<0.1 and Po(A)<0.2) or both high
(e.g., U>0.9 and Po(A)>0.8) with the agreement percentage getting worse as the pairs
of values became more extreme. In these situations the expected utilities of A and
A will tend to be close so there is a greater chance of a discrepancy, though the
expected utility loss of any discrepancy will be low. On average the mean expected
utility loss when discrepancies occurred was only 0.085. It is interesting to note the
weighted average heuristic (2) typically adopted by participants in the study by
Goodwin et al. (2013), which is similar to Take the Average, was well adapted to the
task.
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2.2.2 Asymmetric indicator
The performance of Sum the Pros, Sum the Cons was tested on ‘certainty or risk’
decisions when the indication from the new information was asymmetric. In this case
the posterior probability was obtained as:
P(A|N) = Po(A) + P(N|A) (10)
Po(A) + P(N|A) + [1-Po(A)] + P(N| A )]
This is Bayes formula (1) with sums replacing products. It may look complex for a
heuristic but it is simply:
Sum of the Pros
Sum of the Pros and Cons
When the indication is symmetric it simplifies to Take the Average. The heuristic
was tested on ‘certainty or risk’ decisions for all combinations of values of Po(A) ,
p(N|A) and P(N| A ) from 0.01 to 0.99 in steps of 0.01 when U =0.1, 0.3, 0.5, 0.7 and
0.9. Combinations where P(N|A) = 1 -P(N| A ) were excluded. The performance was
very similar to that when the indicator was symmetric. Over all values the heuristic
yielded a decision that agreed with the one based on Bayes theorem on 85.6% of
occasions and the mean expected utility loss was only 0.013. Figure 5 shows the
percentage of occasions when the heuristic disagreed with the Bayes decision for the
different values of Po(A). As before, levels of agreement were below 70% when both
U and Po(A) were low (e.g., U<0.1 and Po(A)<0.15) or both were high (e.g., U>0.9
and Po(A)>0.85). When there were discrepancies the mean expected utility loss was
0.091
Figure 5 here
3. Discussion and Conclusions
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Bayes theorem is the normative method for revising probabilities when new
information is received so the heuristics cannot surpass it in terms of accuracy.
However, they can be superior in terms of the cognitive effort that they require and in
their acceptability to decision makers. Decision makers seek to balance the cognitive
effort they put into their decisions against the desire to maximise the chances of
making the correct choice (Payne et al. 1993). If a heuristic has a high probability of
leading to an accurate choice and involves relatively little cognitive effort it is likely
to be acceptable. However, acceptability may also depend on the intuitive
reasonableness of the heuristic -does it appear to make sense? For example, it is
known that company sales forecasters tend to make too many judgmental adjustments
to the statistical forecasts generated by their computer systems (Fildes, Goodwin,
Lawrence and Nikolopoulos 2009). Yet the least effortful strategy would be merely to
accept these forecasts without change. It seems that many of the adjustments are made
because the forecasters do not understand the algorithms that have generated the
statistical forecasts or their rationale. They regard them as a ‘black box’. In particular,
they perceive patterns in the random movements in sales time series and see the
computer system’s discounting of these movements as lacking intuitive
reasonableness. As a result the forecasts are deemed to be unacceptable and they are
changed. The heuristics presented above do appear to meet the three requirements of
i) requiring less mental effort to implement than Bayes theorem, ii) providing a high
chance of yielding an accurate choice, and iii) being intuitively reasonable.
Decisions often have what von Winterfeldt and Edwards (1986) refer to as ‘flat
maxima’, that is the optimum choice is relatively insensitive to errors in the estimates
of probabilities and utilities. The heuristics are able to exploit this property. This
tolerance is particularly evident for ‘most probable event’ decisions. In particular,
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when the indicator is symmetric it is just not worth going to the effort of applying the
Bayes formula. Take the average will guarantee perfect accuracy. In other cases the
use of the heuristics clearly would not be advisable. This will be the case in a
‘certainty or risk’ decision when both the prior probability, Po(A), and the utility, U
are both very low or both very high. For example, when Po(A) = 0.02 and U = 0.1
Sum the Pros, Sum the Cons has a 77% probability of indicating the wrong choice
(when averaged over all values of P(N|A) and p(N| A ). As a rule of thumb, if both
values are below 0.2 or both are above 0.8 the heuristic should be avoided. The extent
to which the heuristics should be used in between these extremes of good and bad
performance is, of course a judgment call. In many situations a heuristic providing an
85% probability of an accurate decision is likely to be acceptable, given the reduced
cognitive effort involved. It will clearly not be when decisions are of high importance
(e.g., life and death decisions).
Interestingly, this notion of using simple rules, based on averages and sums, to
update prior estimates was suggested in the 1950’s in the context of regression
analysis. Armstrong (1985) describes an approach which he terms the ‘poor man’s
Bayesian regression analysis’. It involves a first step where a priori estimates of a
model’s coefficients are averaged with those estimated using regression analysis (e.g.,
using least squares). When Tessier and Armstong (2014) applied the approach to sales
estimation in the US lodging market they found that it improved the accuracy of the
estimates, while at the same time incurring little cost.
The analysis presented in this paper has a number of limitations. It was assumed
that the new information, N, was received correctly, and more importantly, that
P(N|A) and P(N| A ) are also known correctly. Nevertheless, there are many
circumstances where P(N|A) and P(N| A ) are likely to be known. For example, the
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accuracy of medical tests or electronic tests used in quality control is often known,
while information on the accuracy of weather forecasts is widely available. Where
these values are not known exactly an error in their estimation would apply equally to
Bayes formula and to the heuristics so their relative accuracy would remain
unchanged. Nevertheless, there is potentially scope for the development of heuristics
to support the estimation of likelihoods. Secondly, for a given prior probability
Po(A), when the indication from the new information was asymmetric, the results
assumed that all combinations of values of P(N|A) and P(N| A ) between 0.01 and
0.99 were equally likely to apply (i.e., a bivariate uniform distribution was assumed).
In practical problems particular combinations of these values may be more common,
but it is of course, difficult, if not impossible, to establish this. In addition, the
research has only considered decisions with two options and up to two discrete
outcomes, though these types of decisions are likely to be commonly encountered in
practice.
Probability forecasts are important in many practical contexts. Taken together, the
results provide strong evidence that, when these forecasts involve revisions based on
new information, simpler can often be best.
20
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Figure 1. Using natural frequencies to estimate posterior probabilities
120
defective
880
OK
110
Test
indicates
defective
10
Test indicates
OK
30
Test
indicates
defective
850
Test indicates
OK
1000 components
25
A
1
F(A) w
0
1-w
A
0
w
1
1-w
A
A
F( A )
Figure 2 Decision tree for identifying the most probable event
26
Sum the Pros, Sum the Cons
0
10
20
30
40
50
60
70
80
90
100
0 0.2 0.4 0.6 0.8 1
Prior probability
% o
f d
is a g
re e m
e n
ts b
e tw
e e n
d e c is
io n
s
Figure 3 The performance of Sum the Pros, Sum the Cons when the indicator is
asymmetric
27
A
1
D1 x
0
1-x
D2
U
A
Figure 4. Decision tree for choosing between options with certain and risky
outcomes where D2 always leads to a utility of U.
28
Figure 5 The performance of Take the Average and Sum the Pros, Sum the Cons
for ‘certainty or risk’ decisions
0
10
20
30
40
50
60
70
80
90
100
0 0.2 0.4 0.6 0.8 1
Prior probability
P e rc
e n
ta g
e o
f ti
m e s d
e c is
io n
s
d is
a g
re e d
w it
h B
a y e s
Asymmetric
indicator Symmetric
indicator