Data driven decisions

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Week_9_Data-Set_MKT_rev.xlsx

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Sample Number Daily Sales Minimum 8037.00
1 13,337 Maximum 15934.00
2 $10,337 Q 1 9341.5
3 $9,337 Q 2 10337
4 $9,977 Q 3 10356.75
5 $12,786
6 $10,337
7 $10,345
8 $10,359
9 $11,048
10 $8,037
11 $10,340
12 $11,340
13 $10,350
14 $9,356 Student should Use t-test
15 $9,900 Mean 10344.17
16 $15,934 Median 10337.0000
17 $9,334 Sample Standard Deviation 1575.629619
18 $8,999 n= 30
19 $10,453 df= 29
20 $10,337 Confidence Level= 0.95
21 $10,336 t= 2.045
22 $9,339 E= 588.349769
23 $10,339 Confidence Interval Lower Limit 9755.81690
24 $8,903 Confidence Interval Upper Limit 10932.5164
25 $9,454 Null Hypothesis µ=10,000
26 $8,346 Alternative Hypothesis µ>10,000
27 $9,349 What type of Test Statistic did you use and why? Hint: We use a t-test if the population standard deviation is unknown and we use a z-test if the population standard deviation is known.
28 $9,338
29 $10,339
30 $12,339
Conclusion: Is the claim supported? Why or why not? Hint: If the p-value is greater than the significance level, we fail to reject the null so there is not enough evidence to reject the hypothesis; we cannot support this claim. If the p-value is less than the significance level, we reject the null hypothesis so we can support this claim.
If student uses z-test; provide feedback and grade for content.
Hypothesis Test
Null Hyp: m = 10000
= Alt Hyp: m > 10000
significance level = 0.05
test statistic = 1.19640
< critical value = 1.69913
> p-value = 0.12062
Since 0.1206159025 > 0.05 we fail to reject the null: m = 10000