Mathematics - Statistics Lab Assignment
Empirical Rule
| Enter the data in the blue highlighted area and the results will show in the yellow highlighted area. | |||||||||
| ANSWER | |||||||||
| Empirical Rule | 68-95-99.7 | ||||||||
| mean | 598.4 | Lower number | Upper number | ||||||
| standard deviation | 86.7 | 68% | 511.7 | 685.1 | |||||
| 95% | 425 | 771.8 | |||||||
| 99.70% | 338.3 | 858.5 |
Normal probability
| Enter input in blue cells; See answers in yellow cells | |||||||
| Example: Given the first divorce distribution is normally distributed with an average of 28 years and a standard deviation of 5 years we can find the probability that their age is at most 32 (x)using Excel. Answer: 0.7881 | |||||||
| ANSWER | |||||||
| Z score | x | 85 | Z score | 2.5714285714 | |||
| mean | 58 | ||||||
| standard deviation | 10.5 | ||||||
| LESS THAN(At most) | AREA LESS THAN | ENTER | Z score | 0.8 | |||
| Asked to find x | 32 | Probability Less than F7 | 0.7881 | ||||
| Mean | 28 | ||||||
| Stdev | 5 | ||||||
| MORE THAN (at least) | AREA MORE THAN | ENTER | Z score | -0.6666666667 | |||
| Asked to find x | 12 | Probability more than F13 | 0.7475 | ||||
| Mean | 14 | ||||||
| Stdev | 3 | ||||||
| Probability INBETWEEN | ENTER | ANSWER | |||||
| INBETWEEN | Asked to find Large value | 55.4 | Probability between F19 and F20 is | 0.0927 | |||
| Asked to find smaller value | 55.2 | ||||||
| Mean | 55 | ||||||
| Stdev | 0.8006 | ||||||
Find x given probability
| Enter input in blue cells; See answers in yellow cells | ||||||
| Example: Assume laptop prices are normally distributed with a average of $965 and a standard deviation of $100. The least expensive 5% of laptops cost less than what amount. Answer: $800.52 | ||||||
| Find x given Area/Probability to Right or Left | Enter | |||||
| Area to the left | yes | If area to the left is given enter yes; otherwise say no | ||||
| Area given | 0.05 | enter decimal | SUMMARY | |||
| Enter Mean | 175 | z | -1.644853627 | |||
| Enter Standard deviation | 11 | Find x | 156.9066101035 | |||
| Find X given Area/Probablity in the middle | Enter | |||||
| Area | 0.5 | enter decimal | SUMMARY | |||
| Enter Mean | 81 | Lower x | 78.3020409992 | |||
| Enter Standard deviation | 4 | Upper x | 83.6979590008 |
Central Limit for Means
| Enter the data in the blue highlighted area and the results will show in the yellow highlighted area. | |||||||||
| Example: Assume that the game playthrough times for a newly released puzzle game has a mean of 49.8 min and a standard deviation of 4.2 minutes. Given a sample size of n= 39 what is the probability that the sample mean is between 50 and 51 minutes | |||||||||
| Answer: 0.34 | |||||||||
| CENTRAL LIMIT THEOREM OF MEANS (CLT) | |||||||||
| Step 1: | |||||||||
| ANSWER | |||||||||
| Given | Enter | ||||||||
| n | 90 | Standard deviation of sample means is SD/sqrt(n) | 0.5270 | ||||||
| Standard deviation(SD) | 5 | ||||||||
| Step 2: | |||||||||
| To Calculate Probability | LESS THAN(At most) | MORE THAN (at least) | INBETWEEN | ||||||
| AREA LESS THAN | ENTER | AREA MORE THAN | ENTER | Probability INBETWEEN | ENTER | ||||
| x given | 50 | x given | 51 | x Larger value | 51 | ||||
| Mean | 49.8 | Mean | 49.8 | x Smaller value | 50 | ||||
| Standard deviation | 4.2 | Standard deviation | 4.2 | Mean | 49.8 | ||||
| Sample Size(n) | 39 | Sample Size(n) | 39 | Standard deviation | 4.2 | ||||
| Sample size | 39 | ||||||||
| standard deviation of sample means | 0.6725 | standard deviation of sample means | 0.6725 | standard deviation of sample means | 0.6725 | ||||
| Z score | 0.2974 | Z score | 1.7843 | Z score for Larger | 1.7843 | ||||
| Probability Less than C23 | 0.6169 | Probability more than G23 | 0.0372 | Zscore for Smaller | 0.2974 | ||||
| Probability between I 18 and I 19 is | 0.3446 |
Central Limit for Proportions
| Enter the data in the blue highlighted area and the results will show in the yellow highlighted area. | |||||||||
| Example: According to a study 40% of people have more than $10,000 in credit card debt. Calculate the probability of 60 customers in a company between 21 and 23 have more than $10,000 credit card debt | |||||||||
| Answer by using in between probability: | |||||||||
| CENTRAL LIMIT THEOREM OF Proportion( CLT) | |||||||||
| Step 1: | |||||||||
| ANSWER | |||||||||
| Given | Enter | ||||||||
| p | Population proportion (Enter decimal = Count /n) | 0.4 | Standard deviation of sample proportion | 0.0632 | |||||
| n | Sample size n | 60 | |||||||
| IF COUNT IS GIVEN DIVIDE THIS BY SAMPLE SIZE n to get the PROPORTION | |||||||||
| Step 2: | INBETWEEN | ||||||||
| Calculate Probability | LESS THAN(At most) | MORE THAN (at least) | |||||||
| INBETWEEN | Enter | ||||||||
| LESS THAN | ENTER | MORE THAN | ENTER | Asked Large value Sample proportion | 0.38333 | ||||
| Sample proportion(If count is given then divide this by n) | 0.3500 | *If count is given = count / n | Sample proportion(count/ n) | 0.3833 | Asked Small value Sample proportion | 0.35000 | |||
| p | Population proportion | 0.4000 | Population proportion | 0.4000 | Population proportion | 0.4 | |||
| Sample Size (n) | 60.0000 | Sample Size (n) | 60.0000 | Sample Size (n) | 60.00000 | ||||
| standard deviation of sample proportion | 0.0632 | standard deviation of sample proportion | 0.0632 | standard deviation of sample proportion | 0.0632 | ||||
| Z score | -0.7906 | Z score | -0.2635 | Z-score of Larger | -0.2635 | ||||
| Probability Less than F7 | 0.2148 | Probability more than | 0.6026 | Z-score of smaller | -0.7906 | ||||
| Probability between I 18 and I 19 is | 0.1827 | ||||||||