Probability
STAT 4351: Homework 8 Due by July 27, 2020
Yuly Koshevnik
First Name Last Name
Problem 1 2 3 4 5 6 7 8 Total
Points
Maximum 10 10 10 10 15 15 15 15 100
Please submit the front page with your solutions!
1
Problem 1 [10 points = 5 + 5]
A continuous non-negative random variable, Y has density function
fY (y) = 4y2 · exp(−2y)
Given Y = y, another non-negative random variable, W has conditional density
fW |Y (w|y) = y2 ·w · exp(−wy)
1. Determine the marginal density for W, fW (w) =
2. Derive the conditional density for (Y |W = w), fY |W (y|w) =
Solution
2
Problem 2 [10 points = 4 + 6]
A continuous non-negative random variable, Y has density function
fY (y) = 4y2 · exp(−2y)
Given Y = y, another non-negative random variable, W has conditional density
fW |Y (w|y) = y2 ·w · exp(−wy)
Evaluate marginal first and second moments listed below
1. E [W ] =
2. Var [W ] =
Solution
3
Problem 3 [10 points = 5 + 5]
A continuous non-negative random variable, Y has density function
fY (y) = 4y2 · exp(−2y)
Given Y = y, another non-negative random variable, W has conditional density
fW |Y (w|y) = y2 ·w · exp(−wy)
Evaluate conditional moments listed below.
1. E [Y |W = w] =
2. Var [Y |W = w] =
Solution
4
Problem 4: [10 points = 5 + 5]
Two non-negative random variables, T and W, are independent with density functions
fT (t) = 37
720 t6 · exp(−3t) and fW w =
35
24 w4 · exp(−3w)
Derive expected values listed below.
1.
E [ W
T
] =
2.
E [ T
W
] =
Solution
5
Problem 5 [15 points = 5 + 5 + 5]
A sample X = {Xi : 1 ≤ i ≤ 7} of size n = 7 was drawn from a uniform distribution with density
f(x) = 1
5 for (0 < x < 5)
Consider the third order statistic, W = X[3] based on this sample.
1. Derive density function, fW (w) =
2. Evaluate expectation, E [W ] =
3. Find the variance, Var [W ]
Please, simplify your answers!
Solution
6
Problem 6 [15 points = 5 + 5 + 5]
A sample X = {Xi : 1 ≤ i ≤ 7} of size n = 7 was drawn from a uniform distribution with density
f(x) = 1
5 for (0 < x < 5)
Consider the third and seventh order statistics, W = X[3] and Y = X[7]
1. Derive the density function for the transformed variable,
T = Y −W
W
2. Determine E [T ]
3. Find expectation of the ratio,
Z = Y
W
Solution
7
Problem 7 [15 points = 5 + 5 + 5]
A three-dimensional random vector X = (X1, X2, X3) has independent components such that
X1 ∼ N [1, 2], X2 ∼ N [−2, 4], and X3 ∼ N [1, 3]
Consider a bivariate random vector Y = (Y1, Y2) with components defined as follows:
Y1 = X1 + X2 + X3 and Y2 = X1 −X3
1. Derive expectations, E [Y1] and E [Y2]
2. Evaluate variances, Var [Y1] and Var [Y2]
3. Determine the covariance, Cov [Y1, Y2]
Solution
8
Problem 8 [15 points = 5 + 5 + 5]
A non-negative continuous random variable, Y has density function defined as follows:
fY (y) = 39
8! ·y8 · exp(−3y)
Given Y = y, a non-negative integer-valued random variable, N has probability mass function
fN|Y (n|y) = P [N = n|Y = y] = yn
n! · exp(−y)
1. Evaluate marginal moments E [N] = and Var [N] =
2. Derive the conditional density function for (Y |N)
3. Evaluate the moments for (Y |N = 3) E [Y |N = 3] =
and Var [Y |N = 3]
Solution
9