Operations Management. Due Thursday 4pm
C ontrolling P
rocesses
“C ontrol” = ?
1. M
onitoring –
Looking for _ _ ? •
A bnorm
alities –
S uch as?
» P
oor perform ance, increased accidents, drop
in orders, etc
2. M
aking adjustm ents
– W
hat kind of adjustm ents?
3. D
eploying the new standard w
ay –
Involves _ _ ?
4. R
epeating the “w heel”
“C ontrol” = ?
1. M
onitoring –
Looking for _ _ ? •
A bnorm
alities –
S uch as?
» P
oor perform ance
2. M
aking adjustm ents
– W
hat kind of adjustm ents?
3. D
eploying the new standard w
ay –
Involves _ _ ?
4. R
epeating the “w heel”
The “W hat, W
hy, and W hen” of C
ontrol - -
1) W hat do you w
ant/need to control? 2) W
hy? -
insights into ___ 3) W
hen abnorm al conditions exist, w
hat A
C TIO
N S
are w arranted?
E xam
ple: N ew
P roduct D
evelopm ent
1)W hat to control?
2)W hy? W
hat are you looking for?
“C ontrol” = ?
• “S
ituational A w
areness” –
F rom
m ilitary
– P
art of “S ituational U
N D
E R
S TA
N D
IN G
” •
D ifference?
= O n-going know
ledge of conditions in G em
ba –
“N orm
al”? “A bnorm
al”? –
H ow
do you acquire S ituational A
w areness?
• E
ffective aw areness?
• E
fficient acquisition?
A pproaches
to S ituational A
w areness
1. The “Lean P roduction S
ystem ” approach = ?
– V
isual m anagem
ent –
G em
ba m anagem
ent –
100% participation
• E
x: T otal P
roductive M aintenance
Latent flaw s
2. S tatistics and D
ata
= “S P
C ”
S tatistical P
rocess C ontrol
O utline:
• T
argets of S P
C –
A nalyzing
a process for _ _ _ ?
“C ontrol” = ?
1. M
onitoring –
Looking for _ _ ? •
A bnorm
alities –
S uch as?
» P
oor perform ance
2. M
aking adjustm ents
– W
hat kind of adjustm ents?
3. D
eploying the new standard w
ay –
Involves _ _ ?
4. R
epeating the “w heel”
Targets of S P
C ?
S tatistical P
rocess C ontrol
O utline:
• T
argets of S P
C –
A nalyzing
a process for _ _ _ ?
• S
trategies and T actics of S
P C
– D
escriptive S tatistics, A
cceptance S am
pling, D
O E
, etc
– C
ontrol C harts
T he M
eaning of Q uality in a B
usiness
D efinition: 2. Q
uality of a w ork process:
W hether or not the process is in
a “desirable state”
D im
ensions of “desirable state” of a process = ?
D im
ensions of the
desirable state of a process
• T
he process is:
1.A ccurate
2.C onsistent
C onsistency
• A
“consistent” process _ _ _ –
H as “basically” the sam
e resultfrom one cycle
to the next
= Is precise
= Is stable
= Is predictable
– It’s output m
ay be good, or m
ay be bad
– Lack of consistency
is due to variability in the
process over tim e
Is the process of kicking field goals a consistent process?
Is there variability in it?
C an it be consistent and yet still be off the m
ark?
C ontrol C
harts T
opics: •
G oals/uses
• S
ources of V ariability
– C
om m
on causes, A ssignable causes
• S
tate of a process –
In-control, out-of-control
• T
ools - -
C ontrol C
harts –
T ype of data being tracked
– T
ype of charts (X bar, R
, P )
– Interpretation of results
G oals of C
ontrol C harts (3)
1. M
easure the variation
in the key characteristic •
A ssign a specific m
etric
“V ariation” of w
hat ?
O f one or m
ore key characteristics of the process
V ariation of? M
etric?
G oals of C
ontrol C harts
1. M
easure the variation
2. U
nderstand the causes and sources of
variation
S ources
of V ariation
• C
om m
on causes of variation
– R
andom causes that w
e cannot identify –
U navoidable
– e.g. slight
differences in process variables like diam
eter, w eight, service tim
e, tem perature
• A
ssignable causes of variation
– C
auses can be identified and elim inated
– e.g. w
orn tool, O T
H E
R S
?
S ources
of V ariation
• C
om m
on causes of variation
– R
andom causes that w
e cannot identify –
U navoidable
– e.g. slight differences in process variables like diam
eter, w eight, service tim
e, tem perature
• A
ssignable causes of variation
– C
auses can be identified and elim inated
– e.g. poor em
ployee training, w orn tool, m
achine needing repair
T he process is “in control”
T he process is “out of control”
A n “O
ut of C ontrol” process -
- •
Im plies that there is a correctable
cause of variability
• M
anagem ent action called for
• T
herefore, a key value or utility of a control chart is1.
S ignaling
that m anagem
ent intervention is now
w
arranted
2. T
here is statistical evidence that som
ething is “out of the ordinary”
3. “M
anagem ent by E
xception” (of the quality of a w
ork process)
G oals of C
ontrol C harts
1. M
easure the variation
2. U
nderstand the causes and sources of
variation
3. R
educe the variation w
hen called for
K eeping a process in control:
S P
C C
ontrol C harts
T he tool or chart -
-
T he C
ontrol C hart
• E
lem ents of a control chart:
1. C
enter Line (C
L): central tendency of the sam ple
data (m ean, average)
O ften, the data for the center line com
es from
sam ples over tim
e _ _ _
P rocess: H
am ner-C
ole real estate office -
- volum
e of business brought in by agents (4)
• G
oal: intervene w hen agents
productivity becom es “too low
” –
or “too high”?
• F
irstsnapshot: m onth 1
A gent
1 2
3 4
S ales
($1000) 60
200 120
180
A v
140
P rocess: H
am ner-C
ole real estate office -
- volum
e of business brought in by agents (4)
• G
oal: intervene w hen agents
productivity becom es “too low
” –
O r “too high”?
• N
ext snapshot: m onth 2
A gent
1 2
3 4
A v
S ales
($1000) 130
500 300
280 302
Individual M easurem
ents (m
onthly $ sales)
Sam ple M
eans
T im
e O
rd e
re d
Q u
a lity
C o
n tro
l D a
ta
X bar = $250,000
and S
igm a = $80,000
$40K $60K
$70K $50K
etc
$140K
T he C
ontrol C hart
• E
lem ents of a control chart:
1. C
enter Line (C
L): central tendency of the sam ple
data (m ean, average)
T he C
ontrol C hart
• E
lem ents of a control chart:
1. C enter line
2. U
pper and Low er C
ontrol Lim its
P urpose of C
ontrol Lim its:
– S
erve as a signalw hen the process has changed
U pper C
ontrol Lim it (U
C L):
– “too big to be like the others”
Low er C
ontrol Lim it (LC
L): –
“too sm all to be like the others”
Individual M easurem
ents
T im
e O
rd e
re d
Q u
a lity
C o
n tro
l D a
ta
L C
L U
C L
Individual M easurem
ents
Sam ple M
eans
T im
e O
rd e
re d
Q u
a lity
C o
n tro
l D a
ta
X bar = $250,000
and S
igm a = $80,000
L C
L U
C L
T he C
ontrol C hart
• E
lem ents of a control chart:
2. C ontrol Lim
its
T he C
ontrol C hart
• E
lem ents of a control chart:
2. C ontrol Lim
its
0.0 3.0
6.0 9.0
12.0 M
ean
Low er 95%
C onfidence
Lim it
U pper 95%
C onfidence
Lim it
C onfidence Lim
its “like” C ontrol Lim
its
S am
ple m eans
are inside these lim
its 95% of the tim
e,
O utside
lim its 5%
of the tim e
2.5 % 2.5 %
X bar
Sam ple M
eans
T im
e O
rd e
re d
Q u
a lity
C o
n tro
l D a
ta
2 sigm a
control lim
its
X bar = $250,000
and S
igm a = $80,000
LC L
U C
L = $250K + (2)($80k)
2.5 % 2.5 %
95.0 %
“z” --your callValue to use?
T im
e
m ean
+ z s
-z s
U C
L
L C
L
W hy “2” sigm
a? W hy “3”%
?
C ontrol C
hart Z -V
alue z
= 3.00 is a standard value
= 99.7% C
onfidence Interval
C ontrol C
hart Z -V
alue z
= 2.00 is a standard value
= 95.4% C
onfidence Interval
C ontrol C
hart Z -V
alue S
m aller
Z-value m
akes the control chart:
M ore sensitive -
- m
ore intervention + m
ore investigation, m ore im
provem ent
- m
ore cost
C ontrol C
hart Z -V
alue S
m aller
Z-value m
akes the control chart:
B U
T -
- M
ore prone to “false alarm s”
C ontrol C
hart Z -V
alue S
m aller
Z-value m
akes the control chart:
B U
T -
- 2. M
ore prone to false alarm s
Im plication as to cause?
You deem the process to be have assignable causes
w hen in fact it turns out that
there are N O
special causes present
D eveloping
a C ontrol C
hart
D esign phase:
1. D
ecide on the level of control you w ant
2. S
et or com pute the param
eters of the chart
U se phase:
3. T
ake periodic sam ples; P
lot sam ple points
on control chart
4. Interpret the results A
S Y
O U
G O
1 2
3 4
5 6
7 8
9 10
S am
ple num ber
Values of the Variable of interest
S alt ( %
)
1 2
3 4
5 6
7 8
9 10
S am
ple num ber
U pper
control lim
it
P rocess
average
Low er
control lim
it
Values of the Variable of interest
1 2
3 4
5 6
7 8
9 10
S am
ple num ber
Values of the Variable of interest
B ag
S alt content
1 1.4 %
2 0.8
3 1.2
4 1.0
S alt ( %
)
1 2
3 4
5 6
7 8
9 10
S am
ple num ber --over tim
e
U pper
control lim
it
P rocess
average
Low er
control lim
it
1.25 %
1.80 %
1.10 %
W as this salt %
sam ple _ _ _
T he basis question:
1 2
3 4
5 6
7 8
9 10
S am
ple num ber --over tim
e
U pper
control lim
it
P rocess
average
Low er
control lim
it
1.80 %
1.10 %
G enerated by a the process that
had this distribution?
C onclusion?
Likelihood?
1.25 %
1 2
3 4
5 6
7 8
9 10
S am
ple num ber --over tim
e
U pper
control lim
it
P rocess
average
Low er
control lim
it
1.80 %
1.10 %
A fter 2
nd sam
ple_ _ _ C onclusion?
1.38 %
1.25 %
1 2
3 4
5 6
7 8
9 10
S am
ple num ber --over tim
e
U pper
control lim
it
P rocess
average
Low er
control lim
it
1.80 %
1.10 %
A fter 3
rd sam
ple_ _ _
C onclusion?
1.30 %
1.25 % 1.38
%
1 2
3 4
5 6
7 8
9 10
S am
ple num ber
W ere these salt %
sam ples _ _ _
C ontinuing -
-
1 2
3 4
5 6
7 8
9 10
S am
ple num ber
U pper
control lim
it
P rocess
average
Low er
control lim
it
M ean + 3σ
= 1.8 %
1.39 %
M ean -
3σ = 1.10 %
G enerated from
a process that had been producing chips that follow
ed this distribution
1 2
3 4
5 6
7 8
9 10
S am
ple num ber
U pper
control lim
it
P rocess
average
Low er
control lim
it
M ean + 3σ
= 1.8 %
1.39 %
M ean -
3σ = 1.10 %
G enerated from
a process that had been producing chips that follow
ed this distribution “S
om ething is going on”
Types of C
ontrol C harts
1. C
ontrol chart for variables •
are used to m onitor characteristics that can be
m easured, e.g. length, w
eight, diam eter, tim
e
– X
-bar C hart
– R
C hart
2. C ontrol charts for attributes
– P
C hart
– C
C hart
T ype of data?
• U
S P
ipe: –
T o m
onitor results of m elting?
– R
esults of casting?
• E
ngineering S ervices ?
C ontrol C
harts for V
ariables •
X -bar C
hart: M ean
– P
lots sam ple averages
– M
easures central tendency (location) of the process
• R
C hart: R
ange –
P lots sam
ple ranges –
M easures dispersion (variation) of the process
• M
U S
T use B
O T
H charts together to
effectively m onitor and control variable quality
characteristics
E xam
ple - -
C oral G
lass; Variable = cutting tool life
X bar C
hart
2
U C
L X
z or X
A R
s
2
L C
L X
z or X
A R
s
1 2
3 4
5 6
7 8
9 10
S am
ple num ber
U pper
control lim
it
P rocess
average
Low er
control lim
it
X
1. F or x-C
harts w hen w
e know s
U pper control lim
it (U C
L) = x + zs
x
Low er control lim
it (LC L) = x
-zs x
w here
x =
m ean of the sam
ple m eans (or a target
value set for the process) z
= num
ber of norm al standard deviations
s x
= standard deviation of the sam
ple m eans
= s
/ n s
= population
standard deviation n
= sam
ple size
C hart P
aram eters -
-
2
U C
L X
z or X
A R
s
2
L C
L X
z or X
A R
s
1 2
3 4
5 6
7 8
9 10
S am
ple num ber
U pper
control lim
it
P rocess
average
Low er
control lim
it
X
C hart P
aram eters -
-
X -bar C
hart C alculations
2
sam ple size
num ber of sam
ples average of the sam
ple m eans
From T
able 6-1, p. 182 param
eter (A
SSU M
PT IO
N : 3
nkXA levelofcontrol
s22
U C
L L
C L
X A R
X A R
Factor for x-C hart
A 2
D 3
D 4
2 1.88
0.00 3.27
3 1.02
0.00 2.57
4 0.73
0.00 2.28
5 0.58
0.00 2.11
6 0.48
0.00 2.00
7 0.42
0.08 1.92
8 0.37
0.14 1.86
9 0.34
0.18 1.82
10 0.31
0.22 1.78
11 0.29
0.26 1.74
12 0.27
0.28 1.72
13 0.25
0.31 1.69
14 0.24
0.33 1.67
15 0.22
0.35 1.65
Factors for R -C
hart S
am ple S
ize (n)
194
E xam
ple for V ariable C
ontrol C
harts
O bservation
S am
ple 1 S
am ple 2
S am
ple 3 x
1 15.8
16.1 16.0
x 2
16.0 16.0
15.9 x
3 15.8
15.8 15.9
x 4
15.9 15.9
15.8
• A
quality control inspector at the C ocoa F
izz soft drink com
pany has taken three sam ples w
ith four observations each of the volum
e of bottles filled (ounces). U se the data
below to develop R
and X -bar control charts w
ith three sigm
a control lim its for the 16 oz. bottling operation.
Layout can be inverted
X -bar
C hart E
xam ple
O bservation
S am
ple 1 S
am ple 2
S am
ple 3 x
1 15.8
16.1 16.0
x 2
16.0 16.0
15.9 x
3 15.8
15.8 15.9
x 4
15.9 15.9
15.8 S
am ple M
ean 15.875
15.950 15.900
n =?
k =?
C enter line = ?
U C
L = ? A
2 = ?
LC L = ?
Factor for x-C hart
A 2
D 3
D 4
2 1.88
0.00 3.27
3 1.02
0.00 2.57
4 0.73
0.00 2.28
5 0.58
0.00 2.11
6 0.48
0.00 2.00
7 0.42
0.08 1.9 2
8 0.37
0.14 1.86
9 0.34
0.18 1.82
10 0.31
0.22 1.78
11 0.29
0.26 1.74
12 0.27
0.28 1.72
13 0.25
0.31 1.69
14 0.24
0.33 1.67
15 0.22
0.35 1.65
Factors for R -C
hart S
am ple S
ize (n)
X -bar
C hart E
xam ple
2
4315.875 15.95
15.90
15.91 3
0.73
nkXA U
C L
15.91 0.73(0.233)
16.08 L
C L
15.91 0.73(0.233)
15.74
O bservation
S am
ple 1 S
am ple 2
S am
ple 3 x
1 15.8
16.1 16.0
x 2
16.0 16.0
15.9 x
3 15.8
15.8 15.9
x 4
15.9 15.9
15.8 S
am ple
M ean
15.875 15.950
15.900
X -bar C
hart E xam
ple, cont.
X -bar C
hart
15.7
15.8
15.9
16.0
16.1
1 2
3 S
am ple N
um ber
C ontrol C
harts for V
ariables •
X -bar C
hart: M ean
– P
lots sam ple averages
– M
easures central tendency (location) of the process
• R
C hart: R
ange –
P lots sam
ple ranges –
M easures dispersion (variation) of the process
R C
hart 4
U C
L D R
1 2
3 4
5 6
7 8
9 10
S am
ple num ber
U pper
control lim
it
P rocess
average
Low er
control lim
it 3
L C
L D R
R bar
sz R
U C L
E xam
ple for V ariable C
ontrol C
harts
O bservation
S am
ple 1 S
am ple 2
S am
ple 3 x
1 15.8
16.1 16.0
x 2
16.0 16.0
15.9 x
3 15.8
15.8 15.9
x 4
15.9 15.9
15.8
• A
quality control inspector at the C ocoa F
izz soft drink com
pany has taken three sam ples w
ith four observations each of the volum
e of bottles filled (ounces). U se the data
below to develop R
and X -bar control charts w
ith three sigm
a control lim its for the 16 oz. bottling operation.
R -C
hart “Factors”
34
sam ple size
num ber of sam
ples average sam
ple range
From T
able 6-1, p. 182 L
C L
param eter
U C
L param
eter
nkRDD
43
U C
L L
C L
D R
D R
Factor for x-C hart
A 2
D 3
D 4
2 1.88
0.00 3.27
3 1.02
0.00 2.57
4 0.73
0.00 2.28
5 0.58
0.00 2.11
6 0.48
0.00 2.00
7 0.42
0.08 1.92
8 0.37
0.14 1.86
9 0.34
0.18 1.82
10 0.31
0.22 1.78
11 0.29
0.26 1.74
12 0.27
0.28 1.72
13 0.25
0.31 1.69
14 0.24
0.33 1.67
15 0.22
0.35 1.65
Factors for R -C
hart S
am ple S
ize (n)
R -C
hart E xam
ple
3 4
430.2 0.3
0.2
0.233 3
0.00, 2.28
nkRD D
U C
L 2.28(0.233)
0.53 L
C L
0.00(0.233) 0.00
O bservation
S am
ple 1
S am
ple 2 S
am ple 3
x 1
15.8 16.1
16.0 x
2 16.0
16.0 15.9
x 3
15.8 15.8
15.9 x
4 15.9
15.9 15.8
R ange
0.2 0.3
0.2
R -C
hart E xam
ple, cont.
R C
hart
0.00 0.10 0.20 0.30 0.40 0.50 0.60
1 2
3 S
am ple N
um ber
N ote: LC
L on R chart N
E V
E R
negative- -
round to 0
Types of C
ontrol C harts
1. C
ontrol chart for variables •
are used to m onitor characteristics that can be
m easured, e.g. length, w
eight, diam eter, tim
e
– X
-bar C hart
– R
C hart
2. C ontrol charts for attributes
– P
C hart
– C
C hart
C ontrol C
harts for A ttributes
• p-C
harts
– D
iscrete values and can be counted •
E ach item
= Y es/no or good/ bad
• E
xam ples of this type of quality variable?
– C
alculate the proportion of non- conform
ing parts or deliverables in each
sam ple
(% defective)
P C
hart C alculations
sam ple size (num
ber in each sam ple)
average percent defective in a sam ple
(1 )
std. deviation of percent defective in a sam ple
num ber of std. deviations aw
ay from process average
(
p np
p p
n z
s
usually 3.0 or 2.0)
U C
L
L C
L m
ax{ ,0}
p
p
p z p z
s
s
W here does “z” com
e from ?
If you w anted to have lim
its that trap, say, 97.5% of the observations that w
ill occur, then z = ?
F inding z for desired control
97.5% (1)
F inding z for desired control
97.5% 1.00 -
.975 = .025 (2)
F inding z for desired control1.00 -
.975 = .025
A nd since w
e w ant .025 split on both ends, then .025/2 = .0125
.0125 .0125
(3)
(2)
F inding z for desired control
.4875
(3)
S o that from
the O N
E S
ID E
D table, z is based on .5000 -.0125 = .4875
and therefore z = ?
.0125
F or P
rob = 0.4875
z = 2.24
P -C
hart E xam
ple
S am
ple N
um ber
of D
efective Tires
N um
ber of Tires in each
S am
ple
P roportion
D efective
1 3
20 2
2 20
3 1
20 4
2 20
5 1
20 Total
9 100
• A
P roduction m
anager for a tire com
pany has inspected the num
ber of defective tires in five random
sam ples w
ith 20 tires in each sam
ple. T he
table show s the num
ber of defective tires in each sam
ple of 20 tires. C alculate
the proportion defective for each sam
ple, the center line, and control lim
its using z
= 3.00. n = ? k = num
ber of sam ples = ?
p = ? C
L = ?
P -C
hart E xam
ple, cont.
20, 3.00 #D
efectives 9
C L
0.09 T
otal Inspected 100
(0.09 )(0.91)
0.064 20
0.09 3(0.064
) 0.282
0.09 3(0.064
) 0.102
0
p
n z
p
U C L
L C L
s
P -C
hart E xam
ple, cont.
P -C
hart
0.00
0.05
0.10
0.15
0.20
0.25
0.30
1 2
3 4
5 S
am ple N
um ber
D eveloping
a C ontrol C
hart 1.
C om
pute the C L, U
C L and LC
L •
C L, U
C L and LC
L should be based on sam ple m
easurem ents
w hen the process is in-control
2. T
ake periodic sam ples
• If assignable causes are present then discard the data
3. P
lot sam ple points on control chart
4. Interpret the chart -
- determ
ine if process is “in control”
• A
re there any “A ssignable” causes of the variability
noted?
S ources
of V ariation
• C
om m
on causes of variation
– R
andom causes that w
e cannot identify –
U navoidable
– e.g. slight differences in process variables like diam
eter, w eight, service tim
e, tem perature
• A
ssignable causes of variation
– C
auses can be identified and elim inated
– e.g. poor em
ployee training, w orn tool, m
achine needing repair
T he process is “in control”
T he process is “out of control”
A P
rocess is “In C ontrol” if -
-
1. N
o sam ple points are outside lim
its
Im plication: this 9
th sam
ple is “not like” the others
I’m 99.7%
sure (ie, 3 sigm
a confident)
1.N o sam
ple points are outside lim its
2. T
here are no P
A TTE
R N
s in the observations
¾ T
he observations are N O
T random
¾ S
ystem atic
fluctuations ¾
T here exist som
e B IA
S in the process now
A P
rocess is “In C ontrol” if -
-
Individual M easurem
ents
X bar chart Sam
ple M eans
LC L
U C
L
Individual M easurem
ents
X bar chart Sam
ple M eans
LC L
U C
L
W hat do you E
xpect to see if this process is IN C
ontrol?
“A bout an equal num
ber of sam ple points
are above and below the average”
Individual M easurem
ents
In c
o n
tro l ?
N ext 9 days
LC L
U C
L
R ules to detect P
atterns
• S
et up A , B
, and C “zones”
“A ”
“A ”
“B ”
“B ”
“C ”
“C ”
R ules to detect P
atterns
• S
et up A , B
, and C “zones”
“A ”
“A ”
“B ”
“B ”
“C ”
“C ”
A ny observations in the A
zone?
A ny observations in the B
zone? C
zone?
O thers -
-
O thers -
-
Im plications?
1.A pattern
exist, and therefore -
-
2. T here is an abnorm
al B ias in the process
so that _ _
3. It is O ut of control -
- an A
ssignable cause of variation likely exist (w
ith probability ___% )
P atterns
• U
se “zones” to identify “bias”
W estern E
lectric rules (N ote: these apply to sym
m etric charts like X
bar, but not to asym
m etric charts like R
charts) - -
C ontrolling P
rocesses
N ext: C
apability of P rocesses