economics
Q3
| A utility company wants to catgotize its customers in three categories - low bills, medium bills and high bills. | |||||
| The bills below $50 are low, above 150 high and in between medium. | |||||
| The data was collected and a histogram was plotted. It determined that the data is distributed as a Normal | |||||
| distribution whose mean and stadard devaition are 100 and 25 respectively. | Mu | 100 | |||
| Sigma | 25 | ||||
| a) What is the probability of a customerto be in the low category? | P (X<50) | 0.0227501319 | |||
| b) What proportions of the customers are in the medium category? | P (50 < X<150) | 0.9544998681 | |||
| c) What percentage of the customers are in the high category? | P (X>150 | 0.02275 | |||
| d) How much a customer must spend to be in the bottom 5%? | P (X<x?) =.05 | 58.8786593262 | |||
Q4
| In reference to Problem 3, a random sample of 25 customers was taken. | |||||||||||||
| Mu | 100 | n | 25 | SigmaofXBAR | 5 | ||||||||
| sigma | 25 | ||||||||||||
| a | What is the probability that the sample mean is below $95? | P (XBAR <95) | 0.1586552539 | ||||||||||
| b. What proportion of the sample mean are above $110? | P (XBAR>110) | 0.0227501319 | |||||||||||
| c. What percentage of the sample mean be between $95 and $110? | 0.8185946141 | ||||||||||||
| d. | If the data was not distributed as a Normal Distribution, would you be able to answer the above questions? | No,theample sizemust be at least30) | |||||||||||
Q5
| Data was collected to study the background of the people who participate in the stock market. | |||||||||||||
| 49 customers were selected at random and asked about their annual savings and whether they lived in a suburb. | |||||||||||||
| After the sample was collected, the data was analyzed to calculate sample mean annual savings , sample standard deviation and the sample proportion | |||||||||||||
| of people living in a suburb | |||||||||||||
| n | 49 | ||||||||||||
| Sample mean = $10K | Sample Standard Deviation = $3K | Sample Proportion = 0.4 | |||||||||||
| Sample Mean Standard deviation | 0.4285714286 | t for0.025and48df | 1.6772241961 | ||||||||||
| a. | Calculate the 90% confidence limits for the Annual Savings. | 10 | 0.7188103698 | 9.2811896302 | Upper Limit | ||||||||
| 10.7188103698 | Lower Limit | ||||||||||||
| The interval 9.28 and 10.72 contains the true population mean 90% ofthetime | |||||||||||||
| b. | Calculate the 95% confidence limits for the population proportion living in suburbs | Z | 1.96 | ||||||||||
| p | 0.4 | upper limit | 0.5371714256 | ||||||||||
| p(1-p) | 0.24 | Lower Limit | 0.2628285744 | ||||||||||
| p (1-p)/n | 0.0048979592 | ||||||||||||
| The true percentage of people living in suburbs is in the range 26 and 54 95% ofthetime. | |||||||||||||
| SQRT() | 0.0699854212 | ||||||||||||