Peer Response 1

· Respond to your classmates’ posts in at least 25 words.

PEERS RESPONSE:

I was assigned number 42, for solving the problems 3 from page 708 and 3 from page 719.

Problem 3 from Page 708. 

f(x)=2x−1.

The function of this equation is (x)=2x−1. 

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. Domain: (−∞, ∞). The range is a set of all valid y values: Range (−∞, ∞).

The relation is a set of ordered pairs of the x and y intercepts.  This passes the Vertical Line Test because, all x values have a single y value.

x	f(x)=2x−1	y
1/2	2(1/2)-1	0
0	2(0)-1	-1
1	2(1)-1	1
-1/2	2(-1/2)-1	-2

Problem 3 from Page 719

f(x) = (x − 3)2 For the Horizontal Transformation of this equation since any real number can be used to replace x in (x − 3)2, the domain is (−∞, ∞). And since the graph continues up from (3, 0), the range is [0, ∞).

x	f(x) = (x-3)^2	y
3	(3-3)^2	0
2	(2-3)^2	1
1	(1-3)^2	4
0	(-3-3)^2	9

-Angela