MATH quiz (need it in 8 hours)
1: (10 Points) Prove or disprove the following statements (if it is true, please write a proof; if it is false,
please provide an counter example to disprove it):
a:
Let S = {t2 + 1, t + 1, t2 + t} be a set of polynomials. Then P2 = Span(S).
b:
The set of all pairs of real numbers of the form hx, yi, where xy � 0, with the
standard operations on R2 is a vector space. (That is the union of the first and third
quadrants in the xy-plane.)
2
2: (15 Points)Let T : R7 ! R4 be given by T(~x) = A~x,
where A =
2
66 4
7 �28 2 17 �3 73 24 �3 �12 4 �17 2 �3 �22 �5 20 2 �19 7 �67 �84 2 �8 �3 12 4 �43 37
3
77 5
rref���!
2
66 4
1 �4 0 3 0 5 6 0 0 1 �2 0 7 �3 0 0 0 0 1 �8 4 0 0 0 0 0 0 0
3
77 5
.
a: Determine row space of A as span of the linearly independent vectors.
b: Determine column space as span of the linearly independent vectors.
c: Determine ker(T) or the null space as span of the linearly independent vectors.
3
3: (45 Points) Consider the matrix A =
2
4 7 4 16
�2 �2 �4 �4 �2 �9
3
5
a: (12 Points) Find the characteristic polynomial. Then find the eigenvalues by solving
the characteristic polynomial.
4
b: (12 Points) Find a basis for each eigenspace corresponding to each eigenvalue from
part a. Indicate the dimension of each eigenspace for the matrix A.
5
c: (4 Points) Diagonalize the matrix A, that is, find an invertiable matrix P , and a
diagonal matrix D such that A = PDP �1.
d: (10 Points) Find the inverse of P by performing row operations to the matrix [P |I].
Then perform matrix multiplication to verify that A = PDP �1.
6
e: (7 Points) Use the factorization A = PDP �1 to prove that A7 = PD7P �1. Then
compute A7. Make sure you compute the following separately: D7, PD7.
7
4: (10 Points) The first four Chebyshev Polynomials of the Second kind are 1, 2t, �1 + 4t2, and �4t +
8t3.
a: Show that the first four Hermite polynomials form a basis of P3.
b: Denote the Chevyshev Polynomials as B and let p(t) = 1 + 8t2 + 8t3. Find the
coordinate vector of p(t) relative to B, where B is the basis of P3 consisting of the
Chebyshev Polynomials.
8
5: (20 Points) Consider the matrix A =
2
66 4
�1 6 6 3 �8 3 1 �2 6 1 �4 �3
3
77 5.
a: Show that the column vectors are linearly independent; and hence, we can conclude
that the column space is of dimension 3.
b: By the Gram-Schmidt Process, find an orthogonal basis for the column space of the
matrix A
9