Pert method - excel

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PERTShortPPT.pdf

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► CPM assumes we know a fixed time estimate for each activity and there is no variability in activity times

► PERT uses a probability distribution for activity times to allow for variability

Variability in Activity Times

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► Three time estimates are required

► Optimistic time (a) – if everything goes according to plan

► Pessimistic time (b) – assuming very unfavorable conditions

► Most likely time (m) – most realistic estimate

Variability in Activity Times

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Estimate follows beta distribution

Variability in Activity Times

Expected activity time:

Variance of activity completion times:

t = (a + 4m + b)/6

v = [(b – a)/6]2

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Expected activity time:

Variance of activity completion times:

t = (a + 4m + b)/6

v = [(b – a)/6]2

Estimate follows beta distribution

Variability in Activity Times

t = (a + 4m + b)/6

v = [(b − a)/6]2Probability of 1 in 100 of > b occurring

Probability of 1 in 100 of < a occurring

P ro

b a

b ili

ty

Optimistic Time (a)

Most Likely Time (m)

Pessimistic Time (b)

Activity Time

Figure 3.11

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Computing Variance

TABLE 3.4 Time Estimates (in weeks) for Milwaukee Paper's Project

ACTIVITY OPTIMISTIC

a

MOST

LIKELY m

PESSIMISTIC b

EXPECTED TIME t = (a + 4m + b)/6

VARIANCE

[(b – a)/6]2

A 1 2 3 2 .11

B 2 3 4 3 .11

C 1 2 3 2 .11

D 2 4 6 4 .44

E 1 4 7 4 1.00

F 1 2 9 3 1.78

G 3 4 11 5 1.78

H 1 2 3 2 .11

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Probability of Project

Completion

Project variance is computed by summing the variances of critical activities

s2 = Project variance

= (variances of activities on critical path)

p

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Probability of Project

Completion

Project variance is computed by summing the variances of critical activitiesProject variance

s2 = .11 + .11 + 1.00 + 1.78 + .11 = 3.11

Project standard deviation

sp = Project variance

= 3.11 = 1.76 weeks

p

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Probability of Project

Completion

PERT makes two more assumptions:

► Total project completion times follow a normal probability distribution

► Activity times are statistically independent

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Probability of Project

Completion

Standard deviation = 1.76 weeks

15 Weeks

(Expected Completion Time)

Figure 3.12

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Probability of Project

Completion

What is the probability this project can be completed on or before the 16 week deadline?

Z = – /sp

= (16 weeks – 15 weeks)/1.76

= 0.57

Due Expected date date of completion

Where Z is the number of standard deviations the due

date or target date lies from the mean or expected date

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Probability of Project

Completion

What is the probability this project can be completed on or before the 16 week deadline?

Z = − /sp

= (16 wks − 15 wks)/1.76

= 0.57

due expected date date of completion

Where Z is the number of standard deviations the due

date or target date lies from the mean or expected date

.00 .01 .07 .08

.1 .50000 .50399 .52790 .53188

.2 .53983 .54380 .56749 .57142

.5 .69146 .69497 .71566 .71904

.6 .72575 .72907 .74857 .75175

From Appendix I

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Probability of Project

Completion

Time

Probability

(T ≤ 16 weeks)

is 71.57%

Figure 3.13

0.57 Standard deviations

15 16

Weeks Weeks

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Determining Project

Completion Time

Probability of 0.01

Z

Figure 3.14

From Appendix I

Probability of 0.99

2.33 Standard deviations

0 2.33

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Variability of Completion Time

for Noncritical Paths

► Variability of times for activities on noncritical paths must be considered when finding the probability of finishing in a specified time

► Variation in noncritical activity may cause change in critical path

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What Project Management Has

Provided So Far

1. The project’s expected completion time is 15 weeks

2. There is a 71.57% chance the equipment will be in place by the 16 week deadline

3. Five activities (A, C, E, G, and H) are on the critical path

4. Three activities (B, D, F) are not on the critical path and have slack time

5. A detailed schedule is available