Writing 3 pages (Drilling Fluids)

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PEE241Drilling.pptx

PEE241 Drilling and Well Completion

Eng. Rashed Alazemi

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UNIT CONVERSION REVIEW

Eng. Rashed Alazemi

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Common Systems of Units

Three common systems of units can be found throughout hydrology when assigning a quantity to variables in hydrology:

1. System International (SI)

2. centimeter-gram-second (cgs) system

3. English system

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Conversion Factors

Unit Conversion Factor

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Surface Area and Volume

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Exercises

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CHAPTER 1 INTRODUCTION TO DRILLING

Eng. Rashed Alazemi

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1.1 History

Oil has been used for lighting purposes for many thousand years.

Darks Well was the first commercial oil well drilled in 1859 in Pennylvania.

Cable tool drilling technique was used to drill to a final depth of 70 ft (21.18 m). It took one and a half year to reach the above depth.

Onshore drilling for oil began o the coast of Summereld, California, just south of Santa Barbara, in 1896.

In 1900 the rotary drilling technique was invented by Lucas.

The first successful attempts at oshore drilling occurred between 1910 and 1920.

In about 1920 mud was used instead of water to circulate the cutting out the hole.

The first directional drilling recorded instance of a well being deliberately drilled along a deviated course was in California in 1930.

First horizontal well in Kern County ,California at Edison field in 1980.

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1.2 Objectives of Drilling

Drilling is the process of making a hole into a hard surface where the length of the hole is very large compared to the diameter.

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1.3 Types of Drilling

There are two types of drilling for oil and gas wells :

Exploration drilling (often called Wildcat wells): is the Initial phase of drilling for the purpose of determining the physical properties and boundaries of a reservoir.

Development drilling (or Production wells): is drilled to a depth that is likely to be productive, so as to maximize the chances of success.

According to a wells final depth, it can be classified into:

Shallow well: < 6000 ft

Conventional well: 6000 ft− 11,000 ft

Deep well: 11,000 ft−16,000 ft

Ultra deep well: > 16,000 ft

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1.4 Drilling Methods

The two most widely used drilling methods are :

Cable-Tool Drilling

Rotary Drilling

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1.4.1 Cable-Tool Drilling

Cable-tool was the first method used to drill a bore hole and is still in use, particularly for shallow oil or gas wells.

In the cable-tool method, drilling is accomplished by lowering a wire line or cable into the hole.

On the end of the line is a heavy chisel-shaped piece of steel called the drilling bit.

An up-and down motion is applied to the line at the surface.

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Cable-Tool Drilling

Advantages for this well

Cheap

Good and fast for hard formation

Disadvantages for this well

Drilling has to stop for cutting removal

Not compatible with soft formation ( caving of unconsolidated rock)

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1.4.2 Rotary Drilling

A bit used to cut the formation is attached to steel pipe called drillpipe.

The bit is lowered to the bottom of the hole.

The pipe is rotated form the surface by means of a rotary table, through which is inserted a square or hexagonal piece called a kelly.

The kelly, connected to the drillpipe at the surface, passes through the rotary table.

The turning action oft the rotary table is applied to the Kelly, which is turn rotate, the drillpipe and the drilling bit

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1.5 Types of Drilling Rigs

The term ”rig” generally refers to the complex of equipment that is used to penetrate the surface of the Earth’s crust.

Drilling and workover rigs come in a variety of shapes and sizes with each having its own characteristics suited for a particular job.

Although there are many factors to be considered in selecting the best rig for the job, a few are especially critical. They are:

• Surface location (land, inland water, offshore)

• Estimated maximum hole depth

• Horsepower requirements

• Cost

• Availability

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Drilling rigs are classified as

Onshore (Land) rigs.

Offshore (Marine) rigs.

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1.5.1 Onshore Rigs

These rigs are primarily used on land.

Major components of the rig include the mud tanks, the mud pumps, the derrick or mast, the drawworks, the rotary table or topdrive, the drillstring, the power generation equipment and auxiliary equipment.

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1.5.2 Offshore Rigs

The first successful attempts at offshore drilling occurred between 1910 and 1920.

The major types of offshore rigs:

1. Floating rigs

(a) Semisubmersible

(b) Drillships

2. Bottom-supported rigs: There are three types:

(a) Jack-ups

(b) Platform

(c) Submesrsible

(d) Barge

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1.6 Drilling Team

The people directly involved in drilling a well are employed either by the operating company, the drilling contractor or one of the service companies.

Tool Pusher : The tool pusher supervises all drilling operations and is the leading man of the drilling contractor on location. Which is the highest position at the drilling location, responsible for every crew..

Company Man : The company man is in direct charge of all the companys activities on the rig site. He is responsible for the drilling strategy as well as the supplies and services in need. His decisions directly eect the progress of the well.

Driller : The crew supervisor on a drilling rig, working under the toolpusher.

Derrick Man : The derrickman works on the so-called monkeyboard, a small platform up in the derrick, usually about 90 [ft] above the rotary table. When a connection is made or during tripping operations he is handling and guiding the upper end of the pipe.

Floor Man : During tripping, the rotary helpers are responsible for handling the lower end of the drill pipe to make or break a connection.

Mud Engineer, Mud Logger : The service company who provides the mud almost always sends a mud engineer and a mud logger to the rig site. They are constantly responsible for logging what is happening in the hole as well as maintaining the propper mud conditions.

Roustabout : The roustabout is a unskilled worker, especially one who works in a port or at an oil well. Roustabout maintaining equipment, unloading supplies and helping the drilling team.

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CHAPTER 2 ROTARY DRILLING

Eng. Rashed Alazemi

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2.1 Rotary Drilling

The most common drilling rigs in use today are rotary drilling rigs.

The main components of a rotary drilling rig can be seen in Figure 3-2.

For all rigs, the depth of the planned well determines basic rig requirements like hoisting capacity, power system, circulation system (mud pressure, mud stream, mud cleaning), as well as the pressure control system.

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Main Component Parts of a Rotary Rig are:

1. Power System

2. Hoisting System

3. Fluid Circulating System

4. Rotary System

5. Well Control System

6. Well Monitoring System

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2.1 Power System

Objective : To provide power to the rig equipment.

The power system of a rotary drilling rig has to supply the following main components:

Rotary system

Hoisting system and

Drilling fluid circulation system.

The largest power consumers on a rotary drilling rig are the hoisting and the circulation system, these components determine mainly the total power requirements.

The power itself is either generated at the rig site using internal-combustion diesel engines, or taken as electric power supply from existing power lines.

As guideline, power requirements for most rigs are between 1,000 to 3,000 hp.

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The rig power systems performance is characterised by the output horse- power, torque and fuel consumption for various engine speeds. These parameters are calculated with equations 3.1 to 3.4:

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Example 3-1:

A diesel engine givens as output torque of 1,740 ft-lbf at engine speed of 1,200 rpm. If the fuel consumption rate was 31.5 gal/hr, what is the out- put power and overall efficiency of the engine?

3.2 Hoisting System

The function of the hoisting system is to provide a means of lowering or raising drillstring, casing string, and other subsurface equipment into or out of the hole.

The principle components of the hoisting system are

(1) The derrick and substructure

(2) The block and tackle,

(3) The drawworks.

Two routine drilling operations performed with the hoisting system are called

Making a connection,

Making a trip.

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3.2.1 Derrick

The function of a derrick is to provide the vertical height required to raise sections of pipe from or lower them into hole.

The greater the height, the longer the section of pipe that can be handle and, thus, the faster a long string of pipe can be inserted in or removed from the hole.

The most commonly used drillpipe is between 27 or 30 ft long.

Derricks that can handle sections called stands, which are composed of two, three, or four joints od drillpipe, are said to be capable of pulling doubles, thribbles, or fourbles, respectively.

Derricks are rated according to their ability to withstand compressive loads and wind loads.

Substructure is space below the derrick floor to provide working for pressure control valves called blowout preventers.

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3.2.2 Block and Tackle

The block and tackle is comprised of

The crown block

The travelling block,

The drilling line.

The arrangement and nomenclature of the block and tackle used on rotary rigs are shown in figure 3-7.

The principle function of the block and tackle is to provide a mechanical advantage, which permits easier handling of large loads

The mechanical advantage M of block and tackle is simply the load support by the travelling block, W, divided by load imposed on drawworks, Ff:

The load on the drawworks is the tension in the fast line.

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3.2.3 Drawworks

The drawworks (Figure 3-11) provide the hoisting and braking power required to raise and lower the heavy strings of pipe.

The principle parts of the drawworks are

The drum

The brakes

The transmission,

The catheads

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The drum transmit the torque required for hoisting or braking. It also stores the drilling line required to move the travelling block length of the derrick.

The brakes must have capacity to stop and sustain the great weights imposed when lowering a string of pipe into the hole. Auxiliary brakes are used to help dissipate the large amount of heat generated during braking.

Two types of auxiliary brakes commonly used are (1) the hydrodynamic type and (2) the electromagnetic type. The drawworks transmission provides a means for easily changing the direction and speed of the travelling block.

Power also must be transmitted to catheads attached to both ends of drawworks.

Friction catheads shown in Figure 3-12 turn continuously and can be used to assist in lifting or moving equipment on the rig floor.

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3.3 Circulating System

A major function of fluid circulating is to remove the rock cuttings from the hole as drilling progresses

The principle components of the mud circulation system are:

Mud pumps

Mud pits

Mud mixing equipment

Contaminant removal equipment

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3.3.1 Mud Pumps

Nowadays there are two types of mud pumps in use (duplex pump, triplex pump), both equipped with reciprocating positive-displacement pistons.

The amount of mud and the pressure the mud pumps release the mud to the circulation system are controlled via changing of pump liners and pistons as well as control of the speed [stroke/minute] the pump is moving.

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Duplex Mud Pump

The duplex mud pump consists of two cylinders and is double-acting. This means that drilling mud is pumped with the forward and backward movement of the barrel.

The pump displacement on the forward movement of the piston is given by:

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On the backward movement of the piston, the volume is displaced:

Thus the total displacement per complete pump cycle is:

Since duplex mud pumps are equipped with two cylinders, and assuming a volumetric efficiency Ev , the total pump displacement per cycle is given by:

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Triplex Mud Pump

The triplex mud pump consists of three cylinders and is single-acting. The pump displacement per cylinder for one complete cycle is given by:

Thus the triplex mud pump, having a volumetric efficiency Ev has a total mud displacement of Fp per complete cycle.

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where,

Fp : Pump displacement (also called pump factor), in2/cycle.

Ev : Volumetric efficiency,fraction.

Ls : Stroke Length, in.

dr : Piston rod diameter,in.

dl : Liner diameter,in

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Example 3-3:

Compute the pump factor in units of barrels per stroke for duplex pump having 6.5 in. liners, 2.5 in. rods, 18 in. strokes, and a volumetric efficiency of 90 %.

Solution

The pump factor for a duplex pump is given by Eq.3.14:

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Then convert in3/stroke to bbl/stroke

The flow rate of the pump [in2/min] can be calculated with:

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where,

N : Number of cycle per minute, cycle/min

The overall efficiency of a mud pump is the product of the mechanical and the volumetric efficiency. The mechanical efficiency is often assumed to be 90% and is related to the efficiency of the primemover itself and the linkage to the pump drive shaft. The volumetric efficiency of a mud pump with adequately charged suction system can be as high as 100%.

Therefore most manufactures rate their pumps with a total efficiency of 90% (mechanical efficiency: 90%, volumetric eciency:100%).

Note that per revolution, the duplex pump makes two cycles (double-acting) where the triplex pump completes one cycle (single-acting).

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The terms "cycle" and "stroke" are applied interchangeably in the industry and refer to one complete pump revolution.

Pumps are generally rated according to their:

1. Hydraulic power,

2. Maximum pressure,

3. Maximum ow rate.

Since the inlet pressure is essentially atmospheric pressure, the increase of

mud pressure due to the mud pump is approximately equal the discharge

pressure.

The hydraulic power " hp " provided by the mud pump can be calculated as:

where:

p : Pump discharge pressure, psi.

q : Pump discharge flow rate, gal/min.

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3.4 The Rotary System

The function of the rotary system is to transmit rotation to the drillstring and consequently rotate the bit. During drilling operation, this rotation is to the right.

The main parts of the rotary system are: (1) swivel, (2) rotary hose, (3) kelly, (4) rotary drive (master pushing, kelly pushing), (5) rotary table and(6) drillstring, see figure 3-16.

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3.4.1 Swivel

The swivel is suspended by the hook of the traveling block and allows the drillstring to rotate as drilling fluid is pumped to within the drillstring.

Without the swivel, drilling uid could not be pumped downhole, or the drillstring could not rotate.

The swivel also supports the axial load of the drillstring. see gure for cuts of swivel showing the internal parts.

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3.4.2 Kelly

The kelly has a square or hexagonal cross-section and provides the rotation of the drillstring.

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3.4.3 Rotary Drive

The rotary drive consists of master pushing and kelly pushing. The master pushing receives its rotational momentum from the compound and drives the kelly pushing which in turn transfers the rotation to the kelly.

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3.4.4 Drillstring

A drillstring on a drilling rig is a column, or string, of drill pipe that transmits drilling fluid (via the mud pumps) and torque (via the kelly drive or top drive) to the drill bit.

The term is loosely applied as the assembled collection of the drill pipe, drill collars, tools and drill bit.

The drill string is hollow so that drilling uid can be pumped down through it and circulated back up the annulus (the void between the drill string and the casing/open hole).

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Drillpipe

The major portion of the drillstring is composed of drillpipe.

The drillpipe in common use is pierced, seamless tubing. API has development specications for drillpipe. Drillpipe is specied by its outer diameter, weight per foot, steel grade, and range length.

The dimensions and strength of API drillpipe of grades D, E, G and S-135 are shown in Table 3-4. Drillpipe is furnished in following API length ranges.

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Range 2 drillpipe is used most commonly. Since each joint of pipe has

a unique length, the length of each joint must be measured carefully and

recorded during drilling operations,

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The drillpipe joint are fastened together in the drillstring by means of tool joints. The female portion of the tool joint is called the box and the male portion is called the pin.

The portion of the drillpipe to which the tool joint is attached has thicker walls that the rest of the drillpipe to provide for a stronger joint. This thicker portion of the pipe is called the upset.

If the extra thickness is achieved by decreasing the internal diameter, the pipe is said to have an internal upset.

Table 3-5: Dimensions and strength of API seamless internal upset drillpipe

Drill collars

The lower section of rotary drillstring is composed of drill collars. The drill collars are thick-walled heavy steel tubulars used tp apply weight to the bit. The buckling tendency of the relatively thin-walled drillpipe is too great to use it for this purpose. The smaller clearance between the borehole and the drill collars helps to keep the hole straight.

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Drilling bit

Drill bit depends on several factors, such as the condition of the bit, the weight applied to it, and the rate at which it is rotated.

Also important for a bit performance is the effectiveness of the drilling fluid in clearing cuttings, produced by the bit away from the bottom.

Drill bit selection is in general a complicated process but, when performed properly, has a major impact on the total well cost.

Three principal types of bits are used in a rotary drilling operation:

Drag of fish-tail bits,

Rolling cutter bits more commonly called rockbits, and

Diamond bits.

Most drilling bits are rock bits.

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Capacity and Volume of Drillstring

Capacity is the amount (volume) that something will hold, or its internal volume.

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where, d pipe diameter , in.

Capacity means that each 1 inch of length will be hold 1 cubic inch. : For

the Oilfield units bbl/ft.

Then,

Volume is the amount of space taken up by a solid object. Volume is calculate how much pipe can be hold in barrel (bbl).

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This equation is using to calculate volume of one barrel (bbl) in 1 foot (ft) of pipe which is also the pipe capacity in bbl/ft

For drillpipe and drill collars we using inner diameter (ID) to calculate capacity of pipe to hold one barrel in each one foot.

Which is

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Example 3-4:

5 inch OD drill pipe has an inside diameter of 4.276 inches.length of pipe

1000 feet. Calculate the following: (a) Capacity bbl=ft (b) Volume bbl.

solution

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Example 3-5:

8 inch drill collars ID 3 inch, Length of drill collars 450 ft.Calculate the

following: (a) Capacity bbl=ft (b) Volume bbl.

solution

Capacity and Volume of Annulus

If you place a pipe inside another pipe there is a space between them. This is called an annulus.

The annulus of an oil well refers to any void between any piping, tubing or casing and the piping, tubing, or casing immediately surrounding it.

To calculate annular capacities and volumes (e.g. pipe in hole, pipe in casing).

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- Annulus Capacity opposite drillpipe, bbl/ft

where,

Aadp : Capacity of annulus opposite drillpipe, bbl/ft

dh : Hole diameter, in.

ODdp : Outer diameter of drillpipe, in.

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- Annulus Volume opposite drillpipe, bbl

where,

Vadp : Volume of annulus opposite drillpipe, bbl

dh : Hole diameter, in.

ODdp : Outer diameter of drillpipe, in.

Ldp : Length of drillpipe, ft

- Annulus Capacity opposite drill collars bbl/ft

where,

Aadc : Capacity of annulus opposite drill collars, bbl=ft

dh : Hole diameter, in.

ODdc : Outer diameter of drillpipe, in.

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- Annulus Volume opposite drill collars, bbl

where,

Vadc : Volume of annulus opposite drill collars, bbl

dh : Hole diameter, in.

ODdp : Outer diameter of drillpipe, in.

Ldc : Length of drill collars, ft

Example 3-6:

Calculate the following annulus capacities in bbl/ft.

(a) 5 inch drillpipe in 171/2 inch hole.

(b) 8 inch drill collars in 121/4 inch hole.

solution

Displacement of Drillstring

The term displacement often is used to refer to the cross-sectional area of steel in the pipe expressed in units of volume per unit length. The displacement, Ad , of a section of pipe is given by

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Example 3-7:

A drillstring is composed of 7,000 ft of 5-in., 19.5lbf=ft drillpipe and 500 ft of 8 in. OD by 2.75 in. ID drill collars when drilling a 9.875 in. borehole assuming that the borehole remains in gauge, compute the number of pump cycles required to circulated mud from the surface to bit and from the bottom of the hole to the surface if the pump factor is 0.1781 bbl/cycle.

Solution

Given

Drillpipe Drill collars

OD :5 in OD : 8 in

Weigth: 19.5 lbf/ft ID : 2.75 in

Length:7000 ft Length:500 ft

Hole diameter: 9.875 in Fp = 0.1781 bbl=cycle.

Using Table 3-5, the inner diameter of 5 in., 19.5 lbm/ft drillpipe is 4.276in.

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- First, number of pump cycles required to circulated mud from the surface to bit:

- The capacity of the drillpipe

- The volume of the drillpipe

- The capacity of drill collars

- The volume of the drill collars

- The number of pump cycles

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-Second ,number of pump cycles required to circulated mud from the bit to surface:

- The annulus capacity outside the drillpipe

- The annulus volume of the drillpipe

- The annulus capacity outside the drill collars

- The annulus volume of the drill collars

- The number of pump cycles

3.5 Well control System

The well control system prevents the uncontrolled flow of formation fluids from the wellbore.

When the bit penetrates a permeable formation that has a fluid pressure in excess of the hydrostatic pressure exerted by the drilling fluid, formation fluids will begin displacing the drilling fluid from the well.

The flow of formation fluids into the well in the presence of drilling fluid is called a kick.

The well control system permits :

Detecting the kick,

Closing the well at the surface,

circulating the well under pressure to remove the formation fluids and increase the mud density,

moving the drill string under pressure, and

diverting flow away from rig personnel and equipment

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Failure of the well control system results in an uncontrolled flow of formation fluids and is called a blowout.

Blowouts can cause loss of life, drilling equipment, the well, much of the oil and gas reserves in the underground reservoir, and damage to the environment near the well.

The well control system is one of the more important systems on the rig. Annular preventers, sometimes called bag-type preventers, stop flow from the well using a ring of synthetic rubber that contracts in thefl uid passage.

Annular preventers are available for working pressures of 2000, 5000 and 10000 psig.

Both the ram and annular BOPs are closed hydraulically.

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3.6 Well monitoring System

Safety and efficiency considerations require constant monitoring of the well to detect drilling problems quickly.

Devices record or display parameters such as depth, penetration rate, hook load, rotary speed, rotary torque, pump rate, pump pressure, mud density, mud temperature, mud salinity, gas content of mud, hazardous gas content of air, pit level and mud flow rate.

In addition to assisting the driller in detecting drilling problems, good historical records of various aspects of the drilling operation also can aid geological, engineering, and supervisory personnel.

This unit provides detailed information about the formation being drilled and uids being circulated to the surface in the mud as well as centralizing the record keeping of drilling parameters.

The mud logger carefully inspects rock cuttings taken from the shale shaker at regular intervals and maintains a log describing their appearance.

These systems are especially useful in monitoring hole direction in non-vertical wells.

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Chapter 3 DRILLING FLUIDS

Eng. Rashed Alazemi

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Chapter 3: DRILLING FLUIDS

Drilling fluid or also called drilling mud is a mixture of water, oil, clay and various chemicals.

Drilling fluid is a fluid used to aid the drilling of boreholes into the earth.

The three main categories of drilling fluids are water-based muds ,oil-based mud, and gaseous drilling fluid, in which a wide range of gases can be used.

The main functions of drilling fluids include providing hydrostatic pressure to prevent formation fluids from entering into the well bore, keeping the drill bit cool and clean during drilling, carrying out drill cuttings, and suspending the drill cuttings while drilling is paused and when the drilling assembly is brought in and out of the hole

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The drilling fluid used for a particular job is selected to avoid formation damage and to limit corrosion.

Drilling fluid is used in the rotary drilling process to:

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Circulate (clean) the cutting and remove them out of hole

(2) Cool and lubricate the bit

(3) Control formation pressures

(4) Minimizing formation damage

(5) Support of Weight of Drill Pipe and Casing.

(6) Maximise penetration rates

3.1 Functions of Drilling Fluids

In the early days of rotary drilling, the primary function of drilling fluids was to bring the cuttings from the bottom of the hole to the surface. Today it is recognized the drilling fluid has at least ten important functions:

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3.1.1 Removal of Cuttings

The removal of cuttings from the face of the well bore is still one of the most important functions of drilling fluids.

Fluid flowing from the bit nozzles exerts a jetting action that keeps the face of the hole and edge of the bit clear of cuttings.

This insures longer bit life and greater efficiency in drilling.

The circulating fluid rising from the bottom of the well bore carries the cuttings toward the surface.

The effectiveness of mud in removing the cuttings from the hole depends on several factors.

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3.1.2 Cooling and Lubrication

Heat is generated from mechanical and hydraulic forces at the bit and when the drill string rotates and rubs against casing and wellbore.

Cool and transfer heat away from source and lower to temperature than bottom hole.

If not, the bit, drill string and mud motors would fail more rapidly.

Lubrication based on the coefficient of friction.

Oil and synthetic based mud generally lubricate better than water-based mud.

Amount of lubrication provided by drilling fluid depends on type & quantity of drill solids and weight materials plus chemical composition of system.

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3.1.3 Control formation pressures

If formation pressure increases, mud density should also be increased, often with barite (or other weighting materials) to balance pressure and keep the wellbore stable.

Unbalanced formation pressures will cause an unexpected influx of pressure in the wellbore possibly leading to a blowout from pressured formation fluids.

Hydrostatic pressure = density of drilling fluid × true vertical depth × acceleration of gravity.

If hydrostatic pressure is greater than or equal to formation pressure, formation fluid will not flow into the wellbore.

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3.1.4 Minimizing formation damage

Skin damage or any reduction in natural formation porosity and permeability (washout) constitutes formation damage.

Most common damage; Mud or drill solids invade the formation matrix, reducing porosity and causing skin effect.

Swelling of formation clays within the reservoir, reduced permeability.

Mud filtrate and formation fluids form an emulsion, reducing reservoir porosity.

Specially designed drill-in fluids or workover and completion fluids, minimize formation damage.

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3.1.5 Support of Weight of Drill Pipe and Casing

With increasing depths, the weight supported by the surface equipment becomes increasingly important.

Since a force equal to the weight of mud displaced buoys up both the drill pipe and casing, an increase in mud density necessarily results in a considerable reduction in total weight, which the surface equipment must support.

Equally, if the casing is not completely filled up during running, some of the hook load is alleviated and the string can be ”floated in”.

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3.1.6 Maximise penetration rates

The drilling fluid is so intimately involved in the drilling process that it is inevitable that a wide range of fluid properties will influence the rate of penetration, apart from the mechanical considerations, such as the type of bit, weight on the bit and rate of rotation.

Fluid properties, such as low viscosities at high shear rates, low solids, high fluid loss and lower densities than are required to balance pore pressure, all contribute to faster penetration rates.

It can be seen that some of the properties, such as high fluid loss and under balance fluid densities are contradictory to the properties required for a stable hole, and a compromise must be reached.

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3.2 Types of Drilling Fluids

Many types of drilling fluids are used in industry. Major categories include air, water- and oil base fluids.

Each has many subcategories based on purpose, additives, or clay states. (see Figure 4-2)

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3.2.1 Water Based Muds

Water based Muds (WBMs) are used to drill approximately 80% of all wells.

The base fluid may be fresh water, seawater, brine, saturated brine, or a formate brine.

The type of fluid selected depends on anticipated well conditions or on the specific interval of the well being drilled.

For example, the surface interval typically is drilled with a low-density water- or seawater-based mud that contains few commercial additives.

These systems incorporate natural clays in the course of the drilling operation.

Some commercial bentonite or attapulgite also may be added to aid in fluid-loss control and to enhance hole-cleaning effectiveness.

After surface casing is set and cemented, the operator often continues drilling with a WBF unless well conditions require displacing to an oil- or synthetic-based system.

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3.2.2 Oil Based Muds

Oil-based systems were developed and introduced in the 1960s to help address several drilling problems:

-Formation clays that react, swell, or slough after exposure to WBMs

-Increasing downhole temperatures

-Contaminants

-Stuck pipe and torque and drag

Oil-based Muds (OBMs) in use today are formulated with diesel, mineral oil, or low-toxicity linear olefins and paraffins.

The olefins and paraffins are often referred to as ”synthetics” although some are derived from distillation of crude oil and some are chemically synthesised from smaller molecules.

The electrical stability of the internal brine or water phase is monitored to help ensure that the strength of the emulsion is maintained at or near a predetermined value.

The emulsion should be stable enough to incorporate additional water volume if a downhole water flow is encountered.

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4.3 Properties of Drilling Fluids

Drilling Fluid Properties related to its performances such as Density, Viscosity, pH concentration and other properties.

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3.3.1 Mud Balance

Density, or Mud Weight is weight per unit of volume.

Once the density is determined it may be expressed in any convenient unit; for example, in pounds per gallon (lb/gal or ppg), pounds per cubic foot (lb/ft3).

Specific Gravity (SG), or in pressure gradient as pounds per square inch per 1,000 feet (psi/1, 000 ft) of mud in the hole.

Normal pressure gradient by water is equal to (0.433 psi/ft) and equal to 433 psi/1000 ft.

The latter unit is most convenient because it may be readily used to calculate the hydrostatic head of the mud column for any depth of hole in the same units in which the pump pressure and the reservoir or formation fluid pressure are calculated.

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This facilitates control when excessive formation pressure or lost circulation is encountered. The conversion factors are as follows:

The mud balance (Fig.4-3) provides the most convenient way of obtaining a precise volume. It consists of a supporting base, a cup, a lid, and a graduated arm carrying a sliding weight. A knife edge on the arm rests on the supporting base.

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Example 3-1:

If the mud reading is 1.20 SG.

then, it equals 10:0 lb/gal = 74.8 lb/ft3 = 519 psi/1; 000 ft of depth.

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4.3.2 Marsh Funnel

The time required for a mud sample to flow through a Marsh funnel is rapid test of the consistency of a drilling fluid. The test consists essentency of filling the funnel with a mud sample and measuring the time required for 1 quart of the sample to flow from the initially full funnel into the mud cup. The funnel viscosity is reported in unit of second per quart. Fresh water at 75◦F has a funnel viscosity of 26 s/qt.

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The flow rate from the marsh funnel changes significantly during the measurement fluid level in the funnel. This causes the test results to become less meaningful for non-Newtonian fluids, which exhibit different apparent viscosities at different flow rates for a given tube size. Unfortunately, most drilling fluids exhibit a non-Newtonian behavoir. Thus, while the funnel viscometer can detect an undesirable drilling fluid consistency, additional tests usually must be made before an appropiatemus treatment can be prescribed.

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3.3.3 The Rotational Viscometer

The rotational viscometer can provide a more meaningful measurement of the rheological characteristics of the mud then marsh funnel.

Six standard speeds plus a variable viscometer shown in Fig.4-4.

Only two standard speeds are possible on most models designed for field use.

The dimensions of the bob and rotor are chosen so the dial reading is equal to the apparent Newtonian viscosity in centipoise at rotor speed of 300 rpm.

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At other speeds, the apparent viscosity, µa , is given by

where θN is the dial reading in degrees and N is rotor speed in revolutions per minute.

The viscometer also can be used to determine rheological parameters the describe non-Newtonian fluid behavoir.

At present, the flow parameters of the Bingham plasic rheological model are reported on the standard API drilling mud report.

Two parameters are required to characterize fluids that follow the Bingham plastic model.

These parameters are called the plastic viscosity and yield point of the fluid. The plastic viscosity , µp , in centipoise normally is computed using

where θ600 is the dial reading with the viscometer operating at 600 rpm and θ300 is the dial reading with viscometer operating at 300 rpm.

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The yield point, τy , in lbf/100 sqft normally is computed using

A third non-Newtonian rheological parameter called gel strength, in unit of lbf/100 sqft , is obtained by noting maximum dial deflection when the rotational is turned at a low rotor speed (usually 3 rpm) after the mud has remained static for some period of time.

If the mud is allowed to remian static in viscometer dial deflection obtained when the viscometer for a period of 10 seconds, the maximum dial deflection obtained when the viscometer is turned on is reported as the initial gel on the API mud report form.

If the mud is allowed to remain static for 10 minutes, the maximum dial deflection is reported as the 10-min gel.

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Example 3-2:

A mud sample in a rotational viscometer equipped with a standard tor- sion spring gives a dial reading of 46 when operated at 600 rpm and a dial reading of 28 when operated at 300 rpm. Compute the apparent viscosity of the mud at each rotor speed. Also compute the plastic viscosity and yield point.

solution

Use of Eq. 4.3 for the 300 rpm dial reading gives

Similarly, use of Eq. 4.3 for the 600-rpm dial reading gives

Note that the apparent viscosity does not remain constant but decreases as the rotor speed is increased. This type of non-Newtonian behavior is shown by essentially all drilling muds. The plastic viscosity of the mud can be computed using Eq. 4.4:

The yield point can be computed using Eq. 4.5:

3.3.4 pH Determination

The term pH is used to express the concentration of hydrogen ions in an aqueous solution. pH is defined by

where [H+] is the hydrogen ion concentration in moles per liter. at room temperature, the ion product constant of water, Kw , has a value of 1.0x10-14 mol/L. Thus, for water

For pure water,[H+] = [OH-] = 1.0x10-7 and the pH is equal to 7.

Since ,in any aqueous solution the product [H+] [OH-] must remain constant ,an increase in [H+] requires a corresponding decrease in [OH-].

A solution in which [H+] > [OH-] is said to be acidic, and a solution in which[OH-] > [H+] is said to be alkaline.

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The relation between pH, [H+] , and [OH-] is summarized in Table

The pH of a fluid can be determined using either a special pH paper or pH meter.

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Example 3-3:

Compute the amount of caustic required to raise the pH of water from 7 to 10.5. The molecular weight of caustic is 40.

Solution:

The concentration of OH− in solution at given pH is given by

The change in OH− concentration required to increase the pH from 7 to 10.5 is given by:

Since caustic has a molecular weight of 40, the weight of caustic required per litre of solution is given by

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3.4 Mud Weight Calculation

Additives are added to the drilling fluid in order to bring the fluid parameters to required values.

Density and viscosity are the two most basic parameters to control.

The drilling fluid technician or engineer should carry some calculations, and laboratory measurements and tests to determine the correct additive and the correct amount to be mixed to the fluid system.

Fluid volumes are normally measured in barrels. Useful conversion factors are:

Powder and dry additives are normally measured in pounds, and liquid additives are normally measured in gallons or barrels.

Pilot tests are lab- oratory (small scale) tests that aim to determine the amounts of additive required to bring some fluid parameters to determinate values.

Small scale tests are fast and cheap to perform.

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A handy conversion for is that of lbm/bbl to g/cm3 :

Therefore, in a pilot test with 350 ml of fluid, 1 gram of added additive corresponds to the addition of 1 lbm of dry additive to 1 barrel of fluid.

A similar conversion shows that 25 ml of liquid additive in 350 ml or fluid corresponds to 3 gallons of additive per barrel of fluids.

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3.4.1 Density Calculations

It is frequently necessary to compute the density of a mixture from the amount of the substance in the mixture.

It is also important to be able to calculate the amount to be added of a given substance in order to increase or decrease the density of the mixture.

The density and specific gravity of some common substances used in drilling fluids are shown in following table:

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The assumption that the mixture is ideal, that volume of the mixture is equal to the volume of the components (not valid for highly soluble substance like NaCl in water) facilities the volume-density calculations.

The relations are

where Vmix is the volume of the mixture and Vi is the volume of the component i of the mixture, and

where M is mass and ρ is density. In general, the final density of a mixture of sunstances ( assuming ideal mixture) is:

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Example 3-4:

Calculate the volume and density of a fluid composed of 25 lbm of bentonite, 60 lbm of barite, and 1 bbl of fresh water.

solution:

The volume and the mas of the mixture are:

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Mixing Fluids of Different Densities

If two substances having different densities are mixed then the density of the mixture is a function of the quantity and density of the components of the mixture.

This relationship can be expressed as follows:

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Case #1: No limit is placed on volume:

Example 4-5:

Determine the density and volume when the two following muds are mixed together.

V1 = 400 bbl ρ1 = 11.0 ppg

V2 = 400 bbl ρ2 = 14.0 ppg

Solution:

Using Eq.4.10 to Final density and volume:

Therefore, Final Volume = 800 bbl & Final Density = 12.5 ppg

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Case #2: A limit is placed on the desired volume:

Example 4-6:

Determine the volume of 400 bbl of 11.0ppg mud and 400bbl 14.0 ppg mud required to build 300 bbl of 11.5 ppg mud.

Solution:

Let V1 = bbl of 11 ppg mud

V2 = bbl of 14.0 ppg mud

then,

Therefore, V2 = 50 bbl of 14.0 ppg mud

V1 + V2 = 300 bbl

V1 = 300−50 = 250 bbl of 11 ppg mud

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3.4.2 Density Control Computation

The density control of a drilling fluid is obtained usually with use of barium sulfate (BaSO4) commonly called barite.

The specific gravity of pure barite is 4.5, and the average specific gravity of API barite is 4.2, or 35 lbm/gal.

When excess storage capacity is not available and to limit the amount of added, the density increase will required discarding a portion of the mud.

In this case the proper volume of old mud should be discarded before adding weight material. For ideal mixing the mud, V1, and weight material ,VB must sum to the desired new volume,V2:

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Likewise, the total mass of mud and weight material must sum to the desired density-volume product:

Solving these simultaneous equations for unknowns V1 and mB yields

when the volume of mud is not limited, the final volume can be calculated from the initial volume by rearranging Eq. 4.12

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and

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Example 4-7:

It is desired to increase the density of 200 bbl of 11 lbm/gal mud to 11.5 lbm/gal using barite. The final volume is not limited. Compute the weight of barite required.

solution:

From table the density of barite is 35.0 lbm/gal. using Eq. 4.14, the final volume V2 is given by

using equation 4.14, the weight of barite required is given by

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The addition of large amounts of barite to the drilling fluid can cause the drilling fluid become quite viscous. The finely divided barite has extremely large surface area and can adsorb a significant amount of free water in the drilling fluid. This problem can be overcome by adding water with the weight material to make up for the water adsorbed on the surface of the finely divided particles. However, this solution has disadvantage of requiring additional weight material to achieve a given increase in mud density because the additional water tends to lower the density of the mixture. Thus, it is often desirable to add only the minimum water required to wet the surface of the weight material. The addition of approximately 1 gal of water per 100 lbm of barite is usually sufficient to prevent unacceptable increase in fluid viscosity. Including a required water volume per unit mass

of barite, VwB, in the expression for total volume yields:

Likewise, including the mass of water in the mass balance expression givens

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solving these simultaneous equations for unknowns V1 and mB yields:

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Reduce mud weight by dilution

The process of adding fresh mud (or liquid phase) in order to reduce the solids content and maintain the properties of the drilling uid in the active system.

Case #1: No limit is placed on volume:

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Case #2: A limit is placed on the desired volume:

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Chapter 4 CASING AND CEMENTING

Eng. Rashed Alazemi

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5.1 Introduction

Very often in completions, casing must be run to seal the wellbore from encroaching fluids. In order to attach the casing firmly to the wellbore wall and stabilize the hole, cement is pumped downhole.

5.2 Casing

Casing must be run into a well if commercial indications of hydrocarbon are observed casing normally is run through the low interval then it is cemented in place.

Casing has several functions:

It contains formation pressures and prevents fracturing of the upper and weaker zone.

It keeps the hole from caving in .

It confines production to the wellbore.

It provides an anchor for surface equipment

It provides an anchor for artificial lift equipment

It separates the formations behind the pipe and limits the pipe and limits production to the zones selected by the engineer.

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Because casing has several different functions. It is usually necessary to install more than one strain of casing or pipe.

These kinds of casing are divided into five classifications:

Conductor pipe

Surface casing

Intermediate casing

Liner string

Production casing

5.2.1 Conductor pipe

Conductor pipe is the conduit that also raises drilling fluid high enough above ground level to return the fluid to the mud

pit. And it prevents washing out around the rigs base.

Conductor pipe is set after the well location has been graded and prepared for the rig. Then the pipe is lowered into the hole and concrete is poured around it to ll the surrounding space.

In swamps and onshore locations, the pipe is driven in with a pile driver. Onshore, the diameter of the pipe can range from 30-42 in., while onshore diameters are usually smaller 16 20 in.

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5.2.2 Surface casing

The next casing to be set is surface casing, which protects fresh waster sands from contamination by oil, gas or salt water from the deeper producing formations . Since freshwater formations normally occur at shallow depths; no more than 2, 000 ft of surface casing are usually required.

An important auxiliary function of the surface casing is to provide a place to attach the blowout preventers. Once the well is completed a production manifold or Christmas tree replaces the BOP.

The outside diameter of the sur4face st4infg is slightly smaller than the inside diameter of the conductor pipe. The surface casing is lowered inside the conductor pipe .The minimum depth is usually 10% of the expected total depth (TD) of the well or 500 ft,. When the expected depth is reached, this string of casing is cemented to the surrounding conductor pipe.

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5.2.3 Intermediate Casing

An intermediate casing, through not always run, protects the hole against loss of circulation in shallow formation In shallow formations. When drilling in areas that have abnormal formation pressure, heaving shales, or lost-circulation zones, a string of casing may need to be run to minimize hazards before drilling to greater depths.

Intermediate casing strings are suspended and sealed at the surface with a casing hanger. The lower portion is cemented by circulating cement down and out around the bottom of the pipe and up across the intervals where cement is needed.

5.2.4 Liner Strings

Unlike casing that is run from the surface to a given depth and overlaps the previous casing, a liner is run only from the bottom of the previous string to the bottom of the open hole. Liners are suspended from a previous string with a hanger. They are often cemented in place but may be suspended in the well without cementing.

Once advantages of using a liner is that it is not necessary to run the string

back to the surface.

Sometimes liners are set in a hole as a protective string, serving the same function as an intermediate string.

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5.2.5 Production Casing

Production Casing is sometimes known as the oil string or the long string. It isolates the oil and /or gas from undesirable fluids in the production formation and from other zones penetrated by the wellbore. This casing also serves as the protection housing for the tubing and other equipment used in a well.

The oil string is the last string of casing run in the well. It is a continuous length of pipe from the well surface to the producing formations.

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5.3 Cementing

Oilwell cementing is the process of mixing and displacing cement slurry down the casing and up the annular space behind the pipe. A bond between the pipe and the formations is made after the cement sets. Cement serves several purposes:

Bonds the pipe to the rock formations

Protects the pipe and the producing formations

Seal o troublesome formations before drilling deeper

Helps keep high-pressure zones from blowing out

Provides support for the casing

Prevents pipe corrosion

Forms a seal in the event of a kick (sudden pressure increase) during further drilling

Cementing is classied as primary or secondary. Primary cementing is done immediately after the casing is run into the well. The objective is to effectively seal and separate each zone and to protect the pipe. Secondary cementing is performed after the primary cement job. Usually it is part 01 a repair or remedial job.

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5.4 Cement Additives

Most cementing jobs are performed using bulk systems rather than handling sacks manually. Bulk systems let workers prepare and supply compositions tailored to suit the requirements of any well condition. This is accomplished by using additives are retarders; some are accelerators that alter cement setting times. Various additives can provide the following functions:

Reduce slurry density

Increase slurry volume

Increase thickening time and related setting

Reduce writing on-cement (WOC) time and decrease early strength

Reduce Water loss

Help prevent premature dehydration

Increase slurry density to restrain pressure

Chapter 6 DRILLING HYDRAULIC

133

Eng. Rashed Alazemi

Chapter 6: DRILLING HYDRAULIC

The science of fluid mechanics is very important to the drilling engineer. Extremely large fluid pressure are created in long slender wellbore and tubular pipe strings by the presence of drilling mud or cement.

The presence of these subsurface pressures must be considered in almost every well problem encountered.

In this chapter, the relations needed to determine the subsurface well conditions.

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These well conditions include

a static condition in which both the well fluid and the central pipe string are at rest.

a circulating operation in which the fluids are being pumped down the central pipe string and up the annulus, and

a tripping operation in which a central pipe string is being moved up or down through the fluid.

The pressure at any point in a column of fluid caused by the weight of fluid above that point.

Controlling the hydrostatic pressure of a mud column is a critical part of mud engineering.

Mud weight must be monitored and adjusted to always stay within the limits imposed by the drilling situation.

Sufficient hydrostatic pressure (mud weight) is necessary to prevent an influx of fluids from downhole, but excessive pressure must also be avoided to prevent creation of hydraulic fractures in the formation, which would cause lost circulation.

Hydrostatic pressure is calculated from mud weight and true vertical depth as follows:

Hydrostatic Pressur, psi = 0.052 × Mud Weight,ppg × True Vertical Depth, ft

For Example for fresh water density 8.33 ppg and hydrostatic pressure gradient is 0.433 psi/ft.

6.1 Hydrostatic Pressure in Liquid Columns

The hydrostatic pressure of the drilling fluid is an essential feature in maintaining control of a well and preventing blowouts.

It is defined, in a practical sense, as the static pressure of a column of fluid.

Although the fluid is generally mud, it can include air, natural gas, foam, mist, or aerated mud. Only liquid-based systems such as mud will be considered.

The hydrostatic pressure of a mud column is a function of the mud weight and the true vertical depth of the well.

It is imperative that attention be given to the well depth so that the measured depth, or total depth, is not used inadvertently.

Since mud weights and well depths are often measured with different units, the equation constants will vary.

Common form of the hydrostatic pressure equation are as follows:

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Example 6-1:

A well is drilled at 8000 ft with 11.0 ppg mud. surface casing set at 2500 ft.

What is hydrostatic pressure at 8000 ft?

What is the hydrostatic pressure at the surface casing shoe at 2500 ft?

Solution:

Example 6-2:

Calculate the static mud density required to prevent flow from permeable zone at 12,200 ft if the pore pressure of the formation fluid is 8,500 psig.

Solution:

6.2 Hydrostatic pressure in gas Columns

In many drilling and completion operations, a gas is present in at least a portion of the well.

In some cases, gas is injected in the well from the surface while in other cases gas my enter the well from subsurface formation.

The variation of pressure with depth in a static gas column is more complicated that in a static liquid column because the gas density changes with changing pressure.

The gas behavoir can be described using the real gas equation defined by

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The gas deviation factor z is a measure of how mush the gas behavoir deviates from that of an ideal gas. An ideal gas is one in which there are no attractive force between gas molecules.

The gas density can be expressed as function of pressure by rearranging Eq.6.3. Solving this equation for gas density ρ yields

Changing units from consistent units to common field units gives:

where ρ is expressed in pounds mass per gallon, p is in pounds per square inch absolute, and T is degrees Rankine.

When the gas column is not short or highly pressure, the variation of gas density with depth within the gas column should be

integration of this equation gives

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Example 6-3:

A well contains tubing filled with methane gas (molecular weight=16) to a vertical depth of 10,000 ft. the annular space is filled with a 9.0 lbm/gal brine. Assuming ideal gas behavior, compute the amount by which the ex- terior pressure on the tubing exceeds the interior tubing preesure at 10,000 ft if the surface tubing pressure is 1,000 psia and mean gas temperature is 140 ◦F. if the collapse resistance of the tubing is 8,330 psi, will the tubing collapse due to the high external pressure ?

Solution:

6.3 Hydrostatic Pressure in Complex Fluid columns

During many drilling operations, the well fluid column contains several sections of different fluid densities.

The variation of pressure with depth in this type of complex fluid column must be determined by separating the effect of each fluids segment.

For ex- ample, consider the complex liquid column shown in Figure 6-2. If the pressure at top of section 1 is known to be p0, then the pressure at the bottom od section 1 can be compute from Eq.6.2.

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The pressure at the bottom of section 1 is essentially equal to the pressure at the top of section 2. Even if an interface is present, the capillary pressure would be negligible for any reasonable wellbore geometry.

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Thus, the pressure at the bottom of section 2 can be expressed in terms of the pressure at the top of section 2:

In general, the pressure p at any vertical distance depth D can be expressed by

It is frequently desirable to view the fluid system shown in figure 6-2. as a manometer when solving for the pressure at a given point in the well. The drillstring interior usually is represented by the left side of the manometer, and the annulus usually represented by right side of the manometer. A hydrostatic pressure balance can then be written in terms of a known pressure and the unknown pressure using Eq.6.11.

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Example 6-4:

An intermediate casing string is to be cemented in place at a depth of 10,000 ft. the well contains 10.5 lbm/gal mud when the casing is placed on the bottom. The cement operation is designed so that the 10.5 lbm/gal mud will be displaced from annulus by (1) 300 ft of 8.5 lbm/gal mud flush, (2)1,700 ft of 12.7 lbm/gal filler cement, and (3) 1,000 ft of 16.7 lbm/gal high strength cement. The high strength cement with be displaced from casing with 9 lbm/gal brine. Calculate the pump pressure required to completely displace the cement from the casing .

Solution:

The complex well fluid system us understood more easily if viewed as a manometer in figure 6-3. The hydrostatics pressure balance is written by starting at the known pressure and moving through the various fluid sec- tions to the point of the unknown pressure. When moving down through a section, (Di+1 −Di) is positive and the change in hydrostatic pressure is added to the known pressure ; conversely, when moving up through a section, (Di+1 −Di) is negative and change in the change in hydrostatic pressure is subtracted from known pressure.

Pa = P0 + 0.052[10.5(7,000) + 8.5(300) + 12.7(1,700) + 16.7(1,000) − 9.0(10,000)] Since the known pressure p0 is 0 psig, then pa = 1,266 psig

6.3.1 Equivalent Density Concept

Field experience in a given area often allows guidelines to be developed for the maximum mud density that formations at given depth with stand without fracturing during normal drilling operations.

It is sometimes helpful to compare a complex well fluid column to equivalent single fluid column that is open to the atmosphere.

This accomplished by calculating the equivalent mud density ρe, which is defined by

The equivalent mud density always should be referenced at a specific depth.

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Example 6-5:

Calculate the equivalent density at a depth of 10,000 ft for Example 6-4 for static well conditions after the cement has been displaced completely from the casing.

Solution:

At a depth of 10,000 ft.

Using Eq.6.12.

Archimedes principle of buoyancy states that the buoyant force exerted on a body fully or partially immersed in a fluid is equal in magnitude (and opposite in direction) to the weight of the volume of fluid which is displaced by they body.

For homogeneous bodies immersed in homogenous fluids, the not or buoyed weight of the body can be calculated from:

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6.4 Buoyancy

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Example 6-6:

Ten thousand feet of 19.5 lbf/ft drillpipe and 600 ft of 147 lbf/ft drill collars are suspended off bottom in a 15.0 lbm/gal mud. Calculate the effective hook load that must be supported by the derrick.

Solution:

The weight of drillstring in air is given by

The effective weight of drillstring in mud:

6.5 Nonstatic Well conditions

The determination of pressure at various points in the well can be quite complex when either the drilling mud or the drillstring is moving.

Frictional force in the well system can be difficult to describe mathematically.

The effect of these frictional forces must be determined for calculation of

(1)The flowing bottomehole pressure or equivalent circulating density during drilling or cementing operations,

(2)The bottomhole pressure or equivalent circulating density during tripping operations,

(3)The optimum pump pressure, flow rate, and bit nozzle sizes during drilling operations,

(4) The cutting carrying capacity of the mud, and

(5) The surface and downhole pressures that will occur in the drillstring during well control operations for various mud flow rates.

The basic physical laws commonly applied to the momvement of fluids are (1) conversation of mass, (2) conversation of energy, and (3) conversation of momentum.

All of the equations describing fluid flow are obtained by application of these physical laws using an assumed rheological model and equation of state.

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6.5.1 Mass Balance

The law of conversation of mass states that the net mass rate into any volume V is equal to the time rate of increase of mass within the volume.

The drilling engineer normally considers only steady state conditions in which the mass concentration or fluid density at any point in the well remains constant.

Also, with the exception of air or gas drilling, the drilling fluid can considered incompressible-i.e., the fluid density is essentially the same at all points in well system.

The mean velocity at a given point is defined as the flow rate per unit area at that point. Because of nonuniform ow geometry, the mean velocity at various points in the well may be different even though the flow rate at all points in the well is the same.

A knowledge of the mean velocity at a given point in the well often is desired. Shown in Table 6-1 are convenient forms of q/A for units frequently used in the field.

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Example 6-7:

A 12 lbm/gal mud is being circulated at 400 gal/min .The 5.0 in. drillpipe

has an internal diameter of 4.33 in., and the drill collars have an internal

diameter of 2.5 in. The bit has a diameter of 9.875 in. Calculate the aver-

age velocity in the (1) drillpipe, (2) drillcollars, and (2) annulus opposite

the drill pipe.

6.5.2 Energy Balance

The law of conservation of energy states that the net energy rate out of a system is equal to the time rate of work done within the system. Consider the generalized flow system shown in Figure 6-4. The energy entering the system is the sum of

The energy leaving the system is the sum of

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The work done by the fluid is equal to the energy per unit mass of fluid

given by the fluid to a fluid engine. Thus, the law of conversation of energy

yields

Simplifying this expression using differential notations

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For incompressible fluids, expressing this equation in practical field units

of pounds per square inch, pounds per gallons, feet per second, and feet

gives

Example 6-8:

Determine the pressure at the bottom of the drillstring if the frictional pressure loss in the drillstring is 1,400 psi, the flow rate is 400 gal/min, the mud density is 12 lbm/gal, and the well depth is 10,000 ft. the internal diameter of the drill collars at the bottom of the drillstring is 2.5 in. and the pressure increase developed by the pump is 3,000 psi.

Solution:

6.6 Flow Through Jet Bits

The pressure drop across the bit is mainly due to the change of fluid velocities in the nozzles.

To increase the penetration rate, when the mud flows through the nozzles its speed is increased drastically which causes a high impact force when the mud hits the bottom of the hole.

This high fluid speed on the other hand causes a relative high pressure loss.

The bit pressure drop itself can be calculated with:

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Bit nozzle diameters often are expressed in 32nds of inch. For example, if the bit nozzles are described as "12-13-13" this denotes that the bit contains one nozzle having a diameter of 12/32 in. and two nozzles having a diameter of 13/32 in.

Example 6-9:

A 12.0-lbm/gal drilling uid is owing through a bit containing three 13/32 in. nozzles at rate of 400 gal=min. Calculate the pressure drop across the

bit.

Solution:

6.6.1 Hydraulic Power

Since power is rate of doing work, pump energy W cab be converted to hydraulic power PH by multiplying W by the mass flow rate ρq. Thus,

If the flow rate q is expressed in gallons per minute and pump pressure Δpp is expressed in pounds per square inch,

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where PH is expressed in hydraulic horsepower.

Example 6-10:

Determine the hydraulic horsepower being developed by the pump discussed in Example 6-8. How much of this power is being lost due to the viscous forces in the drillstring.

Solution:

The pump power being used is given by Eq. 6.19.

The power consumed due to "friction" in the drillstring is