Week 2 - Assignment: Apply the T-Test Reflect in e Portfolio Submit Feedback
1 Running Head: T-TEST
Apply the T-test
Nikki Owens
BUS-7106: Statistics II
Northcentral University
Dr. Fred Rispoli
May 9, 2021
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2 T-TEST
Apply the T-test
Introduction
“T-test is a statistical test that is used to compare the means of two groups. It is often used
in hypothesis testing to determine whether a process or treatment actually influences the
population or interest, or whether two groups are different from one another” (Bevans, 2020).
This paper will analyze a t-test for a CEO of a firm with 500 employees. The CEO is
performing a study to determine how committed the employees are to the firm. A t-test is
performed to test the null hypothesis which is there is no statistically significant difference
between the two groups of workers in the dataset. The t-test was chosen to analyze the results of
the hypothesis because the two variables have an unknown variance which can be known by the
t-test. The analysis information that was found during the test is discussed below.
T-test Excel
T-Test
t-Test: Two-Sample Assuming Equal Variances
Job Status Commitme
nt
Mean 0.5 3.71666667
Variance 0.2542372
9 0.66624294
Observations 60 60
Pooled Variance 0.4602401
1 Hypothesized Mean Difference 0
df 118
t Stat -25.97015
P(T<=t) one-tail 6.312E-51
t Critical one-tail 1.6578695
2
P(T<=t) two-tail 1.2624E-
50
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3 T-TEST
t Critical two-tail 1.9802722
5
Based on the results in the analysis above the most important number that is really
needed is the P-value. The p-value is what determines if the null hypothesis is accepted or
rejected. The p-value was found to be 1.2624E-50 and the significant alpha value used was 0.05.
Since the P-value of 1.2624E-50 is less than 0.05, the variables of job status and commitment do
have a statistically significant difference and therefore the null hypothesis would be rejected
since the CEO wanted to test the variables for no significant difference amoung them.
T-test SPSS
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4 T-TEST
Based on the results in the analysis above, the P-value was found to be 0.696 and the
significant alpha value used was 0.05. Since the P-value of 0.696 is greater than 0.05, the
variables of job status and commitment do not have a statistically significant difference and
therefore the null hypothesis would be accepted since the results was true based on what the
CEO was testing in the study.
Results
When it comes to calculating the t-value, I would simply use the formula t=mean-
theoretical mean value divided by standard deviation divided by the square root of the variable
dataset size (n). This is how I would calculate the t-value manually, however, I used Microsoft
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5 T-TEST
excel and SPSS software to calculate the t-value for the study which was a lot faster and less
time consuming. When I tested the null hypothesis t-test in Microsoft excel it was determined
that the variables had a difference, so the null hypothesis was rejected. When I tested the null
hypothesis t-test in SPSS software it was determined that the variables were the same and did not
have a difference, so the null hypothesis was accepted. Both software’s had different results but
used the same information that was collected from a survey, but the SPSS was more accurate for
the study and was able to help the CEO determine how committed the employees were based on
their job status.
Conclusion
In conclusion, based on the SPSS software, if I was the CEO, I would accept the null
hypothesis and come up with a plan to keep my employees committed to the firm by determining
where they are most experienced and place them in that position because the two variables used
from the survey had no significant differences between each other due to they had similar mean
values and the p-value was greater than the significant value of 0.05.
References
Bevans, R. (2020). An introduction to t-test. Retrieved from https://www.scribbr.com/statistics/t-
test/
Microsoft Excel Software
SPSS Software
Weiers, R. M. (2011). Introduction to business statistics (7th ed.). Mason, OH: South-
Western, Cengage Learning
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6 T-TEST
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