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· Question 1

5 out of 5 points

Correct

Find the Chi-Square critical value for the test of association where alpha is the level of significance, R is the number of rows and C is number of columns.

alpha (level of significance) =0.005 and R = 5, C = 7, where degree of freedom = (R - 1)(C - 1)

Selected Answer:

40.8

· Question 2

5 out of 5 points

Correct

Find the Chi-Square critical value for goodness of fit where alpha is the level of significance and k is the number of possible outcomes for each trial.

alpha (level of significance) =0.05 and k = 22, where degree of freedom = k - 1

Selected Answer:

32.671

· Question 3

0 out of 5 points

Incorrect

Calculate the Chi-square test statistic for the goodness of fit with the following table:

The following data represents scores on a police entrance exam.

                                                             Level 1                           Level 2                   Level 3

Observed Values, O                           29                                   201                        169

Expected Values, E                             20.5                               218.8                     159.7

Selected Answer:

9.159

· Question 4

0 out of 5 points

Incorrect

An investigator was interested in the relationship between color preference and number of siblings. A test of independence produced a χ2 that allowed the null hypothesis to be rejected. The proper conclusion is

Selected Answer:

both options are correct

· Question 5

0 out of 5 points

Incorrect

Find the Chi-Square critical value for the test of association where alpha is the level of significance, R is the number of rows and C is number of columns.

alpha (level of significance) =0.10 and R = 2, C = 3, where degree of freedom = (R - 1)(C - 1)

Selected Answer:

2.56

· Question 6

5 out of 5 points

Correct

The null hypothesis for testing the significance of rs is that the population correlation coefficient is

Selected Answer:

1.00

· Question 7

0 out of 5 points

Incorrect

Nonparametric tests are used rather than a t test or an ANOVA when

Selected Answer:

a null hypothesis cannot be specified

· Question 8

5 out of 5 points

Correct

The smallest value of a Spearman rs that is significant at the .05 level for a two-tailed test when the number of pairs is 20 is

Selected Answer:

.45

· Question 9

5 out of 5 points

Correct

Suppose a researcher found an rs of .89 between amount of blood cholesterol and the severity of the heart attack. Based on an of 6 and a two-tailed test, the researcher should conclude

Selected Answer:

significant at the .05 level

· Question 10

2.5 out of 5 points

Partial Credit

             are based on the idea that subjects are randomly assigned to groups

Selected Answer:

parametric tests